The number of stereoisomers possible for 9 , 10 − dibromohexadecanoic acids is to be determined and the three-dimensional structures for (±) − threo, 9 , 10 − dibromohexadecanoic acids are to be written. Concept Introduction: The pair of diastereomers that shows different configuration at the chirality center are called epimers. Monosaccharide, having its highest chirality center same as that of D (or +) − glyceraldhyde , is designated as D − sugar , conversely, if the same monosaccharide has its highest chirality center same as that of L (or − ) − glyceraldhyde , it is designated as L − sugar . The pair of isomers of a molecule that are mirror images of one another are called enantiomers. The molecules or compounds which are non-superimposable or not identical with its mirror image are known as chiral molecules. The pair of two mirror images which are non-identical are known as enantiomers and these are optically active. The objects or molecules which are superimposable with their mirror images are achiral objects or molecules and these objects have a centre of symmetry or plane of symmetry. The achiral compounds in which plane of symmetry is present internally and consists of chiral centres are known as meso compounds but they are optically inactive. The stereoisomers which are non-superimposable on each other and not mirror images of each other are known as diastereomers. Chiral molecules are capable of rotating plane polarized light The molecules which are superimposable or identical with their mirror images are known as achiral molecules, and achiral molecules are not capable of rotating the plane-polarised light. Plane of symmetry is the plane that bisects the molecule in two equal halves, such that they are mirror images of each other. Compounds having plane of symmetry are usually achiral as they do not have different atoms around the central carbon atom. Threo and erythro are commonly used to distinguish diastereomers. In fischer projection, the erythro isomer has two identical substituents on the same side. In fischer projection, the threo isomer has two identical substituents on the opposite side. In zig-zag formula, the erythro isomer has two identical substituents on different sides of the plane. The names are derived from the diastereomeric aldoses erythrose and threose. In double bond or cyclic compounds, if two same functional groups are present on the same side of the double bond or cyclic compound, the given compound can be labeled as cis. If the two functional groups are present on the different sides of the double bond or cyclic compound, the given compound can be labeled as Trans. Cis-trans isomerism exists in the compounds in which similar groups are present on the adjacent carbon atoms.

Question

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Answer 1

Question

Chapter 23, Problem 1PP

Interpretation Introduction

Interpretation:

The number of stereoisomers possible for 9,10−dibromohexadecanoic acids is to be determined and the three-dimensional structures for (±)−threo, 9,10−dibromohexadecanoic acids are to be written.

Concept Introduction:

The pair of diastereomers that shows different configuration at the chirality center are called epimers.

Monosaccharide, having its highest chirality center same as that of D (or +)−glyceraldhyde, is designated as D−sugar, conversely, if the same monosaccharide has its highest chirality center same as that of L (or −)−glyceraldhyde, it is designated as L−sugar.

The pair of isomers of a molecule that are mirror images of one another are called enantiomers.

The molecules or compounds which are non-superimposable or not identical with its mirror image are known as chiral molecules.

The pair of two mirror images which are non-identical are known as enantiomers and these are optically active.

The objects or molecules which are superimposable with their mirror images are achiral objects or molecules and these objects have a centre of symmetry or plane of symmetry.

The achiral compounds in which plane of symmetry is present internally and consists of chiral centres are known as meso compounds but they are optically inactive.

The stereoisomers which are non-superimposable on each other and not mirror images of each other are known as diastereomers.

Chiral molecules are capable of rotating plane polarized light

The molecules which are superimposable or identical with their mirror images are known as achiral molecules, and achiral molecules are not capable of rotating the plane-polarised light.

Plane of symmetry is the plane that bisects the molecule in two equal halves, such that they are mirror images of each other.

Compounds having plane of symmetry are usually achiral as they do not have different atoms around the central carbon atom.

Threo and erythro are commonly used to distinguish diastereomers.

In fischer projection, the erythro isomer has two identical substituents on the same side.

In fischer projection, the threo isomer has two identical substituents on the opposite side.

In zig-zag formula, the erythro isomer has two identical substituents on different sides of the plane.

The names are derived from the diastereomeric aldoses erythrose and threose.

In double bond or cyclic compounds, if two same functional groups are present on the same side of the double bond or cyclic compound, the given compound can be labeled as cis.

If the two functional groups are present on the different sides of the double bond or cyclic compound, the given compound can be labeled as Trans.

Cis-trans isomerism exists in the compounds in which similar groups are present on the adjacent carbon atoms.

Expert Solution & Answer

Answer to Problem 1PP

Solution:

a)

Two sets of enantiomers of erythrose and threose are given as:

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 1

b)

The three-dimensional structures of the given compound are as:

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 2

Explanation of Solution

a) The number of stereoisomers are possible for 9,10−dibromohexadecanoic acids

The product obtained from the reaction of bromine with palmitoleic acid is a mixture of erythrose and threose. The designations erythro and threo come from the names of the sugars called erythrose and threose. Both D− and L− forms of erythrose are diastereomers (stereoisomers that are not mirror images of one another) of both the isomers of threose. Thus, there would be two sets of enantiomers, giving a total of four stereoisomers, which are shown below.

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 3

b) The three-dimensional structures for the (±)−threo-9,10−dibromohexadecanoic acids

As per the information given in the question, the addition of bromine is an anti-addition to the double bond, that is, it takes place through bromonium ion as an intermediate. Formation of a bromonium ion at the other end of the palmitoleic acid gives a result, such that only threo enantiomers are produced due to the racemic modification.

The three-dimensional structures of the (±)−threo, 9,10−dibromohexadecanoic acids considering the cis stereochemistry of the double bond of the palmitoleic acid and bromine addition can be given as:

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 4

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Answer 2

Question

Chapter 23, Problem 1PP

Interpretation Introduction

Interpretation:

The number of stereoisomers possible for 9,10−dibromohexadecanoic acids is to be determined and the three-dimensional structures for (±)−threo, 9,10−dibromohexadecanoic acids are to be written.

Concept Introduction:

The pair of diastereomers that shows different configuration at the chirality center are called epimers.

Monosaccharide, having its highest chirality center same as that of D (or +)−glyceraldhyde, is designated as D−sugar, conversely, if the same monosaccharide has its highest chirality center same as that of L (or −)−glyceraldhyde, it is designated as L−sugar.

The pair of isomers of a molecule that are mirror images of one another are called enantiomers.

The molecules or compounds which are non-superimposable or not identical with its mirror image are known as chiral molecules.

The pair of two mirror images which are non-identical are known as enantiomers and these are optically active.

The objects or molecules which are superimposable with their mirror images are achiral objects or molecules and these objects have a centre of symmetry or plane of symmetry.

The achiral compounds in which plane of symmetry is present internally and consists of chiral centres are known as meso compounds but they are optically inactive.

The stereoisomers which are non-superimposable on each other and not mirror images of each other are known as diastereomers.

Chiral molecules are capable of rotating plane polarized light

The molecules which are superimposable or identical with their mirror images are known as achiral molecules, and achiral molecules are not capable of rotating the plane-polarised light.

Plane of symmetry is the plane that bisects the molecule in two equal halves, such that they are mirror images of each other.

Compounds having plane of symmetry are usually achiral as they do not have different atoms around the central carbon atom.

Threo and erythro are commonly used to distinguish diastereomers.

In fischer projection, the erythro isomer has two identical substituents on the same side.

In fischer projection, the threo isomer has two identical substituents on the opposite side.

In zig-zag formula, the erythro isomer has two identical substituents on different sides of the plane.

The names are derived from the diastereomeric aldoses erythrose and threose.

In double bond or cyclic compounds, if two same functional groups are present on the same side of the double bond or cyclic compound, the given compound can be labeled as cis.

If the two functional groups are present on the different sides of the double bond or cyclic compound, the given compound can be labeled as Trans.

Cis-trans isomerism exists in the compounds in which similar groups are present on the adjacent carbon atoms.

Expert Solution & Answer

Answer to Problem 1PP

Solution:

a)

Two sets of enantiomers of erythrose and threose are given as:

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 1

b)

The three-dimensional structures of the given compound are as:

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 2

Explanation of Solution

a) The number of stereoisomers are possible for 9,10−dibromohexadecanoic acids

The product obtained from the reaction of bromine with palmitoleic acid is a mixture of erythrose and threose. The designations erythro and threo come from the names of the sugars called erythrose and threose. Both D− and L− forms of erythrose are diastereomers (stereoisomers that are not mirror images of one another) of both the isomers of threose. Thus, there would be two sets of enantiomers, giving a total of four stereoisomers, which are shown below.

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 3

b) The three-dimensional structures for the (±)−threo-9,10−dibromohexadecanoic acids

As per the information given in the question, the addition of bromine is an anti-addition to the double bond, that is, it takes place through bromonium ion as an intermediate. Formation of a bromonium ion at the other end of the palmitoleic acid gives a result, such that only threo enantiomers are produced due to the racemic modification.

The three-dimensional structures of the (±)−threo, 9,10−dibromohexadecanoic acids considering the cis stereochemistry of the double bond of the palmitoleic acid and bromine addition can be given as:

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 4

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Answer 3

Question

Chapter 23, Problem 1PP

Interpretation Introduction

Interpretation:

The number of stereoisomers possible for 9,10−dibromohexadecanoic acids is to be determined and the three-dimensional structures for (±)−threo, 9,10−dibromohexadecanoic acids are to be written.

Concept Introduction:

The pair of diastereomers that shows different configuration at the chirality center are called epimers.

Monosaccharide, having its highest chirality center same as that of D (or +)−glyceraldhyde, is designated as D−sugar, conversely, if the same monosaccharide has its highest chirality center same as that of L (or −)−glyceraldhyde, it is designated as L−sugar.

The pair of isomers of a molecule that are mirror images of one another are called enantiomers.

The molecules or compounds which are non-superimposable or not identical with its mirror image are known as chiral molecules.

The pair of two mirror images which are non-identical are known as enantiomers and these are optically active.

The objects or molecules which are superimposable with their mirror images are achiral objects or molecules and these objects have a centre of symmetry or plane of symmetry.

The achiral compounds in which plane of symmetry is present internally and consists of chiral centres are known as meso compounds but they are optically inactive.

The stereoisomers which are non-superimposable on each other and not mirror images of each other are known as diastereomers.

Chiral molecules are capable of rotating plane polarized light

The molecules which are superimposable or identical with their mirror images are known as achiral molecules, and achiral molecules are not capable of rotating the plane-polarised light.

Plane of symmetry is the plane that bisects the molecule in two equal halves, such that they are mirror images of each other.

Compounds having plane of symmetry are usually achiral as they do not have different atoms around the central carbon atom.

Threo and erythro are commonly used to distinguish diastereomers.

In fischer projection, the erythro isomer has two identical substituents on the same side.

In fischer projection, the threo isomer has two identical substituents on the opposite side.

In zig-zag formula, the erythro isomer has two identical substituents on different sides of the plane.

The names are derived from the diastereomeric aldoses erythrose and threose.

In double bond or cyclic compounds, if two same functional groups are present on the same side of the double bond or cyclic compound, the given compound can be labeled as cis.

If the two functional groups are present on the different sides of the double bond or cyclic compound, the given compound can be labeled as Trans.

Cis-trans isomerism exists in the compounds in which similar groups are present on the adjacent carbon atoms.

Expert Solution & Answer

Answer to Problem 1PP

Solution:

a)

Two sets of enantiomers of erythrose and threose are given as:

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 1

b)

The three-dimensional structures of the given compound are as:

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 2

Explanation of Solution

a) The number of stereoisomers are possible for 9,10−dibromohexadecanoic acids

The product obtained from the reaction of bromine with palmitoleic acid is a mixture of erythrose and threose. The designations erythro and threo come from the names of the sugars called erythrose and threose. Both D− and L− forms of erythrose are diastereomers (stereoisomers that are not mirror images of one another) of both the isomers of threose. Thus, there would be two sets of enantiomers, giving a total of four stereoisomers, which are shown below.

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 3

b) The three-dimensional structures for the (±)−threo-9,10−dibromohexadecanoic acids

As per the information given in the question, the addition of bromine is an anti-addition to the double bond, that is, it takes place through bromonium ion as an intermediate. Formation of a bromonium ion at the other end of the palmitoleic acid gives a result, such that only threo enantiomers are produced due to the racemic modification.

The three-dimensional structures of the (±)−threo, 9,10−dibromohexadecanoic acids considering the cis stereochemistry of the double bond of the palmitoleic acid and bromine addition can be given as:

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 4

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Answer 4

Question

Chapter 23, Problem 1PP

Interpretation Introduction

Interpretation:

The number of stereoisomers possible for 9,10−dibromohexadecanoic acids is to be determined and the three-dimensional structures for (±)−threo, 9,10−dibromohexadecanoic acids are to be written.

Concept Introduction:

The pair of diastereomers that shows different configuration at the chirality center are called epimers.

Monosaccharide, having its highest chirality center same as that of D (or +)−glyceraldhyde, is designated as D−sugar, conversely, if the same monosaccharide has its highest chirality center same as that of L (or −)−glyceraldhyde, it is designated as L−sugar.

The pair of isomers of a molecule that are mirror images of one another are called enantiomers.

The molecules or compounds which are non-superimposable or not identical with its mirror image are known as chiral molecules.

The pair of two mirror images which are non-identical are known as enantiomers and these are optically active.

The objects or molecules which are superimposable with their mirror images are achiral objects or molecules and these objects have a centre of symmetry or plane of symmetry.

The achiral compounds in which plane of symmetry is present internally and consists of chiral centres are known as meso compounds but they are optically inactive.

The stereoisomers which are non-superimposable on each other and not mirror images of each other are known as diastereomers.

Chiral molecules are capable of rotating plane polarized light

The molecules which are superimposable or identical with their mirror images are known as achiral molecules, and achiral molecules are not capable of rotating the plane-polarised light.

Plane of symmetry is the plane that bisects the molecule in two equal halves, such that they are mirror images of each other.

Compounds having plane of symmetry are usually achiral as they do not have different atoms around the central carbon atom.

Threo and erythro are commonly used to distinguish diastereomers.

In fischer projection, the erythro isomer has two identical substituents on the same side.

In fischer projection, the threo isomer has two identical substituents on the opposite side.

In zig-zag formula, the erythro isomer has two identical substituents on different sides of the plane.

The names are derived from the diastereomeric aldoses erythrose and threose.

In double bond or cyclic compounds, if two same functional groups are present on the same side of the double bond or cyclic compound, the given compound can be labeled as cis.

If the two functional groups are present on the different sides of the double bond or cyclic compound, the given compound can be labeled as Trans.

Cis-trans isomerism exists in the compounds in which similar groups are present on the adjacent carbon atoms.

Expert Solution & Answer

Answer to Problem 1PP

Solution:

a)

Two sets of enantiomers of erythrose and threose are given as:

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 1

b)

The three-dimensional structures of the given compound are as:

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 2

Explanation of Solution

a) The number of stereoisomers are possible for 9,10−dibromohexadecanoic acids

The product obtained from the reaction of bromine with palmitoleic acid is a mixture of erythrose and threose. The designations erythro and threo come from the names of the sugars called erythrose and threose. Both D− and L− forms of erythrose are diastereomers (stereoisomers that are not mirror images of one another) of both the isomers of threose. Thus, there would be two sets of enantiomers, giving a total of four stereoisomers, which are shown below.

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 3

b) The three-dimensional structures for the (±)−threo-9,10−dibromohexadecanoic acids

As per the information given in the question, the addition of bromine is an anti-addition to the double bond, that is, it takes place through bromonium ion as an intermediate. Formation of a bromonium ion at the other end of the palmitoleic acid gives a result, such that only threo enantiomers are produced due to the racemic modification.

The three-dimensional structures of the (±)−threo, 9,10−dibromohexadecanoic acids considering the cis stereochemistry of the double bond of the palmitoleic acid and bromine addition can be given as:

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 4

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Answer 5

Chapter 23, Problem 1PP

Interpretation Introduction

Interpretation:

The number of stereoisomers possible for 9,10−dibromohexadecanoic acids is to be determined and the three-dimensional structures for (±)−threo, 9,10−dibromohexadecanoic acids are to be written.

Concept Introduction:

The pair of diastereomers that shows different configuration at the chirality center are called epimers.

Monosaccharide, having its highest chirality center same as that of D (or +)−glyceraldhyde, is designated as D−sugar, conversely, if the same monosaccharide has its highest chirality center same as that of L (or −)−glyceraldhyde, it is designated as L−sugar.

The pair of isomers of a molecule that are mirror images of one another are called enantiomers.

The molecules or compounds which are non-superimposable or not identical with its mirror image are known as chiral molecules.

The pair of two mirror images which are non-identical are known as enantiomers and these are optically active.

The objects or molecules which are superimposable with their mirror images are achiral objects or molecules and these objects have a centre of symmetry or plane of symmetry.

The achiral compounds in which plane of symmetry is present internally and consists of chiral centres are known as meso compounds but they are optically inactive.

The stereoisomers which are non-superimposable on each other and not mirror images of each other are known as diastereomers.

Chiral molecules are capable of rotating plane polarized light

The molecules which are superimposable or identical with their mirror images are known as achiral molecules, and achiral molecules are not capable of rotating the plane-polarised light.

Plane of symmetry is the plane that bisects the molecule in two equal halves, such that they are mirror images of each other.

Compounds having plane of symmetry are usually achiral as they do not have different atoms around the central carbon atom.

Threo and erythro are commonly used to distinguish diastereomers.

In fischer projection, the erythro isomer has two identical substituents on the same side.

In fischer projection, the threo isomer has two identical substituents on the opposite side.

In zig-zag formula, the erythro isomer has two identical substituents on different sides of the plane.

The names are derived from the diastereomeric aldoses erythrose and threose.

In double bond or cyclic compounds, if two same functional groups are present on the same side of the double bond or cyclic compound, the given compound can be labeled as cis.

If the two functional groups are present on the different sides of the double bond or cyclic compound, the given compound can be labeled as Trans.

Cis-trans isomerism exists in the compounds in which similar groups are present on the adjacent carbon atoms.

Expert Solution & Answer

Answer to Problem 1PP

Solution:

a)

Two sets of enantiomers of erythrose and threose are given as:

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 1

b)

The three-dimensional structures of the given compound are as:

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 2

Explanation of Solution

a) The number of stereoisomers are possible for 9,10−dibromohexadecanoic acids

The product obtained from the reaction of bromine with palmitoleic acid is a mixture of erythrose and threose. The designations erythro and threo come from the names of the sugars called erythrose and threose. Both D− and L− forms of erythrose are diastereomers (stereoisomers that are not mirror images of one another) of both the isomers of threose. Thus, there would be two sets of enantiomers, giving a total of four stereoisomers, which are shown below.

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 3

b) The three-dimensional structures for the (±)−threo-9,10−dibromohexadecanoic acids

As per the information given in the question, the addition of bromine is an anti-addition to the double bond, that is, it takes place through bromonium ion as an intermediate. Formation of a bromonium ion at the other end of the palmitoleic acid gives a result, such that only threo enantiomers are produced due to the racemic modification.

The three-dimensional structures of the (±)−threo, 9,10−dibromohexadecanoic acids considering the cis stereochemistry of the double bond of the palmitoleic acid and bromine addition can be given as:

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 4

Answer 6

Chapter 23, Problem 1PP

Interpretation Introduction

Interpretation:

The number of stereoisomers possible for 9,10−dibromohexadecanoic acids is to be determined and the three-dimensional structures for (±)−threo, 9,10−dibromohexadecanoic acids are to be written.

Concept Introduction:

The pair of diastereomers that shows different configuration at the chirality center are called epimers.

Monosaccharide, having its highest chirality center same as that of D (or +)−glyceraldhyde, is designated as D−sugar, conversely, if the same monosaccharide has its highest chirality center same as that of L (or −)−glyceraldhyde, it is designated as L−sugar.

The pair of isomers of a molecule that are mirror images of one another are called enantiomers.

The molecules or compounds which are non-superimposable or not identical with its mirror image are known as chiral molecules.

The pair of two mirror images which are non-identical are known as enantiomers and these are optically active.

The objects or molecules which are superimposable with their mirror images are achiral objects or molecules and these objects have a centre of symmetry or plane of symmetry.

The achiral compounds in which plane of symmetry is present internally and consists of chiral centres are known as meso compounds but they are optically inactive.

The stereoisomers which are non-superimposable on each other and not mirror images of each other are known as diastereomers.

Chiral molecules are capable of rotating plane polarized light

The molecules which are superimposable or identical with their mirror images are known as achiral molecules, and achiral molecules are not capable of rotating the plane-polarised light.

Plane of symmetry is the plane that bisects the molecule in two equal halves, such that they are mirror images of each other.

Compounds having plane of symmetry are usually achiral as they do not have different atoms around the central carbon atom.

Threo and erythro are commonly used to distinguish diastereomers.

In fischer projection, the erythro isomer has two identical substituents on the same side.

In fischer projection, the threo isomer has two identical substituents on the opposite side.

In zig-zag formula, the erythro isomer has two identical substituents on different sides of the plane.

The names are derived from the diastereomeric aldoses erythrose and threose.

In double bond or cyclic compounds, if two same functional groups are present on the same side of the double bond or cyclic compound, the given compound can be labeled as cis.

If the two functional groups are present on the different sides of the double bond or cyclic compound, the given compound can be labeled as Trans.

Cis-trans isomerism exists in the compounds in which similar groups are present on the adjacent carbon atoms.

Expert Solution & Answer

Answer to Problem 1PP

Solution:

a)

Two sets of enantiomers of erythrose and threose are given as:

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 1

b)

The three-dimensional structures of the given compound are as:

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 2

Explanation of Solution

a) The number of stereoisomers are possible for 9,10−dibromohexadecanoic acids

The product obtained from the reaction of bromine with palmitoleic acid is a mixture of erythrose and threose. The designations erythro and threo come from the names of the sugars called erythrose and threose. Both D− and L− forms of erythrose are diastereomers (stereoisomers that are not mirror images of one another) of both the isomers of threose. Thus, there would be two sets of enantiomers, giving a total of four stereoisomers, which are shown below.

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 3

b) The three-dimensional structures for the (±)−threo-9,10−dibromohexadecanoic acids

As per the information given in the question, the addition of bromine is an anti-addition to the double bond, that is, it takes place through bromonium ion as an intermediate. Formation of a bromonium ion at the other end of the palmitoleic acid gives a result, such that only threo enantiomers are produced due to the racemic modification.

The three-dimensional structures of the (±)−threo, 9,10−dibromohexadecanoic acids considering the cis stereochemistry of the double bond of the palmitoleic acid and bromine addition can be given as:

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 4

Answer 7

Chapter 23, Problem 1PP

Interpretation Introduction

Interpretation:

The number of stereoisomers possible for 9,10−dibromohexadecanoic acids is to be determined and the three-dimensional structures for (±)−threo, 9,10−dibromohexadecanoic acids are to be written.

Concept Introduction:

The pair of diastereomers that shows different configuration at the chirality center are called epimers.

Monosaccharide, having its highest chirality center same as that of D (or +)−glyceraldhyde, is designated as D−sugar, conversely, if the same monosaccharide has its highest chirality center same as that of L (or −)−glyceraldhyde, it is designated as L−sugar.

The pair of isomers of a molecule that are mirror images of one another are called enantiomers.

The molecules or compounds which are non-superimposable or not identical with its mirror image are known as chiral molecules.

The pair of two mirror images which are non-identical are known as enantiomers and these are optically active.

The objects or molecules which are superimposable with their mirror images are achiral objects or molecules and these objects have a centre of symmetry or plane of symmetry.

The achiral compounds in which plane of symmetry is present internally and consists of chiral centres are known as meso compounds but they are optically inactive.

The stereoisomers which are non-superimposable on each other and not mirror images of each other are known as diastereomers.

Chiral molecules are capable of rotating plane polarized light

The molecules which are superimposable or identical with their mirror images are known as achiral molecules, and achiral molecules are not capable of rotating the plane-polarised light.

Plane of symmetry is the plane that bisects the molecule in two equal halves, such that they are mirror images of each other.

Compounds having plane of symmetry are usually achiral as they do not have different atoms around the central carbon atom.

Threo and erythro are commonly used to distinguish diastereomers.

In fischer projection, the erythro isomer has two identical substituents on the same side.

In fischer projection, the threo isomer has two identical substituents on the opposite side.

In zig-zag formula, the erythro isomer has two identical substituents on different sides of the plane.

The names are derived from the diastereomeric aldoses erythrose and threose.

In double bond or cyclic compounds, if two same functional groups are present on the same side of the double bond or cyclic compound, the given compound can be labeled as cis.

If the two functional groups are present on the different sides of the double bond or cyclic compound, the given compound can be labeled as Trans.

Cis-trans isomerism exists in the compounds in which similar groups are present on the adjacent carbon atoms.

Answer 8

Expert Solution & Answer

Answer to Problem 1PP

Solution:

a)

Two sets of enantiomers of erythrose and threose are given as:

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 1

b)

The three-dimensional structures of the given compound are as:

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 2

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

a) The number of stereoisomers are possible for 9,10−dibromohexadecanoic acids

The product obtained from the reaction of bromine with palmitoleic acid is a mixture of erythrose and threose. The designations erythro and threo come from the names of the sugars called erythrose and threose. Both D− and L− forms of erythrose are diastereomers (stereoisomers that are not mirror images of one another) of both the isomers of threose. Thus, there would be two sets of enantiomers, giving a total of four stereoisomers, which are shown below.

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 3

b) The three-dimensional structures for the (±)−threo-9,10−dibromohexadecanoic acids

As per the information given in the question, the addition of bromine is an anti-addition to the double bond, that is, it takes place through bromonium ion as an intermediate. Formation of a bromonium ion at the other end of the palmitoleic acid gives a result, such that only threo enantiomers are produced due to the racemic modification.

The three-dimensional structures of the (±)−threo, 9,10−dibromohexadecanoic acids considering the cis stereochemistry of the double bond of the palmitoleic acid and bromine addition can be given as:

EBK ORGANIC CHEMISTRY, Chapter 23, Problem 1PP , additional homework tip 4

Answer 12

Ch. 23 - Prob. 1PP Ch. 23 - Prob. 2PP Ch. 23 - Prob. 3PP Ch. 23 - Prob. 4PP Ch. 23 - Prob. 5PP Ch. 23 - Prob. 6PP Ch. 23 - Prob. 7PP Ch. 23 - Prob. 8PP Ch. 23 - Prob. 9PP Ch. 23 - Prob. 10PP

Concept explainers

Answer to Problem 1PP

Explanation of Solution

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