BIOLOGY
5th Edition
ISBN: 9781265202859
Author: BROOKER
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 23, Problem 1CQ
Summary Introduction
To determine: The percentage of individuals in a population that are expected to be heterozygous carriers on the basis of Hardy-Weinberg equation.
Introduction: The Hardy-Weinberg equation represents a mathematical model in which a single gene exists in two different forms of alleles represented by p and q. This equation is derived from the fact that at the time of fertilization, alleles combine randomly when diploid offspring are produced.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Tay–Sachs disease is an autosomal recessive disorder. Among Ashkenazi Jews, the frequency of Tay–Sachs disease is 1 in 3600. Assuming the Ashkenazi population is in Hardy-Weinberg equilibrium, what proportion of the population is expected to be carriers (e.g. heterozygous) for the Tay–Sachs allele?
If a disease determined by autosomal recessive heredity occurs at a frequency of 0.04 in a population, what is the frequency of this disease allele in the population? Assume Hardy-Weinberg equilibrium and use Aand a to symbolize the dominant and recessive alleles, respectively. Show calculation.
8% of XY individuals are color blind in a population. Assume Hardy-Weinberg conditions. Submit your answer as it is.
a) What is the percentage of color-blind XX individuals?
b) What is the percentage of XX individuals who are carriers?
c) If this population has 1000 individuals with 50% of male and 50% of female, how many carriers are present in this
population? Submit your answer as it is. Do not round up.
Chapter 23 Solutions
BIOLOGY
Ch. 23.1 - Prob. 1CSCh. 23.2 - Prob. 1CCCh. 23.2 - Prob. 2CCCh. 23.2 - Prob. 3CCCh. 23.3 - Prob. 1CCCh. 23.3 - Prob. 1EQCh. 23.3 - Prob. 2EQCh. 23.3 - Prob. 3EQCh. 23.4 - Genetic Drift Concept Check: How does the...Ch. 23.4 - Prob. 1CS
Ch. 23.5 - Prob. 1CCCh. 23 - Population geneticists are interested in the...Ch. 23 - The Hardy-Weinberg equation characterizes the...Ch. 23 - Prob. 3TYCh. 23 - Prob. 4TYCh. 23 - Prob. 5TYCh. 23 - Prob. 6TYCh. 23 - Prob. 7TYCh. 23 - Prob. 8TYCh. 23 - Kimuras proposal regarding neutral variation...Ch. 23 - Populations that experience inbreeding may also...Ch. 23 - Prob. 1CQCh. 23 - Prob. 2CQCh. 23 - Prob. 3CQCh. 23 - Antibiotics are commonly used to combat bacterial...Ch. 23 - Discuss die similarities and differences among...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- In a population of 200 people, an allele F has a frequency of 84%. What is the frequency of allele f? Using the Hardy-Weinberg equation, estimate the numbers of homozygous dominant, heterozygous, and homozygous recessive genotypes. (Remember that the formula is: p2 + 2pq + q2 = 1, where p represents the dominant allele and q represents the recessive allele.) *Be sure to account for all 200 people in the population.arrow_forwardA given autosomal locus has three possible alleles (A1, A2, and A3). Assuming that the numbers of individuals with the six possible genotypes are as follows, what would be the frequency of the A1 allele in the population? A1A1 = 30 A1A2 = 27 A2A2 = 12 A1A3 = 17 A2A3 = 10 A3A3 = 4 What would be the frequency of the A1A1 genotype? Assume the population is under Hardy-Weinberg equilibrium. A. 0.182 B. 0.27 C. 0.107 D. 0.317 E. 0.09 F. 0.03arrow_forwardSickle-cell anemia is a recessive disease that afflicts approximately 1 in 12 African Americans, meaning that the frequency of ss homozygotes is 0.09. Assuming the African American population is in Hardy-Weinberg equilibrium, what is the frequency of Ss carriers in this population?arrow_forward
- What is the expected genotype frequency of the heterozygous genotype under the Hardy-Weinberg equation P = 0.7?arrow_forwardIn a human population at equilibrium, three genotypes are present in the following proportions: A/A = 0.81, A/a = 0.18, a/a = 0.01. Answer the following questions: What are the frequencies of gene A and gene a? What will their frequencies be in the next generation? What proportion of all marriages in this population is between heterozygotic parents?arrow_forwardAssume that the frequency of gene B in a hypothetical population Is 0.63, that there are only two alleles (B and b) of the gee in the population, that allele B is dominant over allele b, that neither allele has a selective advantage over the other, and that the population is at equilibrium with regard to this particular gene. And how many individuals in this population are expected to be of genotype BB according to the Hardy-Weinberg formula? (Assume that the total population size is 150) 71 52 118 60 131arrow_forward
- Consider the case of a hypothetical genetic disease called WhySciEleven (WSE), an inherited disease that results to the inability to complete production of an amino acid “moduleactivity” that results in brain damage if untreated. WSE is due to a recessive allele. Given one WSE occurrence per 10,000 births. Which term in the Hardy-Weinberg equation corresponds to the frequency of individuals who have no alleles for the disease WSE? a. p b. 2pq c. p2 d. q2arrow_forwardThe frequency of individuals who express a recessive disease in a population is 16%. What variable in the Hardy Weinberg equations does the 16% refer to? Why?arrow_forwardIn a system that meets the requirements for Hardy-Weinberg equilibrium 75% of individuals exhibit the dominant phenotype for a trait. What percentage of the total population of these organisms will be heterozygotes for that trait?arrow_forward
- Phenylketonuria is a recessive autosomal genetic disorder that can cause mental retardation. Phenylketonuria is particularly common in Turkey, where 1 in 2600 children are born with the disease. As of 2011, the population of Turkey was 73.6 million. Based on this data, and assuming that the Turkish population is in Hardy-Weinberg equilibrium. (a) Estimate the number of carriers of phenylketonuria in Turkey (b) Estimate the proportion of unaffected individuals who are carriers.arrow_forwardIf the frequency of PKU, an autosomal recessive disease, is 2.7% in males what is the frequency of females with PKU? ( You may assume that the population is in Hardy-Weinberg equilibrium.)arrow_forwarda) The allele frequency of albinism is 0.12 in a population of 450 individuals. If the number of individuals that are carriers of albinism is 101. Calculate the number of individuals with normal pigmentation? b) A rare disease which is due to a recessive allele (A) that is lethal when homozygous occurs within a specific population at a frequency of three in a million. How many individuals in a town with a population of 3000 will be expected to carry this allele?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning
Human Heredity: Principles and Issues (MindTap Co...
Biology
ISBN:9781305251052
Author:Michael Cummings
Publisher:Cengage Learning
Mechanisms of Genetic Change or Evolution; Author: Scientist Cindy;https://www.youtube.com/watch?v=5FE8WvGzS4Q;License: Standard Youtube License