Explanation Given information: The given function is f ( x ) = { x 2 − 2 if x > 1 2 x − 3 if x ≤ 1 ........... ( 1 ) Calculation: Since given function has two branches which are polynomial in x , therefore the function is continuous every where and the only point where it is breakable is at x = 1 . So, the suspicious point is x = 1 and checking continuity at point x = 1 , from (1) gives, lim x → 1 − { f ( x ) } = lim x → 1 − ( 2 x − 3 ) = ( 2 ( 1 ) − 3 ) = − 1 .....

6th Edition

ISBN: 9781465208880

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 2.3, Problem 15PS

To determine

Tofind:All the points of discontinuity for the function

f(x)={x2−2 if x>12x−3 if x≤1

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Chapter 2.3, Problem 14PS

Chapter 2.3, Problem 16PS

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Chapter 2 Solutions

Calculus

Ch. 2.1 - Prob. 1PS Ch. 2.1 - Prob. 2PS Ch. 2.1 - Prob. 3PS Ch. 2.1 - Prob. 4PS Ch. 2.1 - Prob. 5PS Ch. 2.1 - Prob. 6PS Ch. 2.1 - Prob. 7PS Ch. 2.1 - Prob. 8PS Ch. 2.1 - Prob. 9PS Ch. 2.1 - Prob. 10PS

Ch. 2.1 - Prob. 11PS Ch. 2.1 - Prob. 12PS Ch. 2.1 - Prob. 13PS Ch. 2.1 - Prob. 14PS Ch. 2.1 - Prob. 15PS Ch. 2.1 - Prob. 16PS Ch. 2.1 - Prob. 17PS Ch. 2.1 - Prob. 18PS Ch. 2.1 - Prob. 19PS Ch. 2.1 - Prob. 20PS Ch. 2.1 - Prob. 21PS Ch. 2.1 - Prob. 22PS Ch. 2.1 - Prob. 23PS Ch. 2.1 - Prob. 24PS Ch. 2.1 - Prob. 25PS Ch. 2.1 - Prob. 26PS Ch. 2.1 - Prob. 27PS Ch. 2.1 - Prob. 28PS Ch. 2.1 - Prob. 29PS Ch. 2.1 - Prob. 30PS Ch. 2.1 - Prob. 31PS Ch. 2.1 - Prob. 32PS Ch. 2.1 - Prob. 33PS Ch. 2.1 - Prob. 34PS Ch. 2.1 - Prob. 35PS Ch. 2.1 - Prob. 36PS Ch. 2.1 - Prob. 37PS Ch. 2.1 - Prob. 38PS Ch. 2.1 - Prob. 39PS Ch. 2.1 - Prob. 40PS Ch. 2.1 - Prob. 41PS Ch. 2.1 - Prob. 42PS Ch. 2.1 - Prob. 43PS Ch. 2.1 - Prob. 44PS Ch. 2.1 - Prob. 45PS Ch. 2.1 - Prob. 46PS Ch. 2.1 - Prob. 47PS Ch. 2.1 - Prob. 48PS Ch. 2.1 - Prob. 49PS Ch. 2.1 - Prob. 50PS Ch. 2.1 - Prob. 51PS Ch. 2.1 - Prob. 52PS Ch. 2.1 - Prob. 53PS Ch. 2.1 - Prob. 54PS Ch. 2.1 - Prob. 55PS Ch. 2.1 - Prob. 56PS Ch. 2.1 - Prob. 57PS Ch. 2.1 - Prob. 58PS Ch. 2.1 - 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Prob. 37PS Ch. 2.3 - Prob. 38PS Ch. 2.3 - Prob. 39PS Ch. 2.3 - Prob. 40PS Ch. 2.3 - Prob. 41PS Ch. 2.3 - Prob. 42PS Ch. 2.3 - Prob. 43PS Ch. 2.3 - Prob. 44PS Ch. 2.3 - Prob. 45PS Ch. 2.3 - Prob. 46PS Ch. 2.3 - Prob. 47PS Ch. 2.3 - Prob. 48PS Ch. 2.3 - Prob. 49PS Ch. 2.3 - Prob. 50PS Ch. 2.3 - Prob. 51PS Ch. 2.3 - Prob. 52PS Ch. 2.3 - Prob. 53PS Ch. 2.3 - Prob. 54PS Ch. 2.3 - Prob. 56PS Ch. 2.3 - Prob. 57PS Ch. 2.3 - Prob. 58PS Ch. 2.3 - Prob. 59PS Ch. 2.3 - Prob. 60PS Ch. 2.4 - Prob. 1PS Ch. 2.4 - Prob. 2PS Ch. 2.4 - Prob. 3PS Ch. 2.4 - Prob. 4PS Ch. 2.4 - Prob. 5PS Ch. 2.4 - Prob. 6PS Ch. 2.4 - Prob. 7PS Ch. 2.4 - Prob. 8PS Ch. 2.4 - Prob. 9PS Ch. 2.4 - Prob. 10PS Ch. 2.4 - Prob. 11PS Ch. 2.4 - Prob. 12PS Ch. 2.4 - Prob. 13PS Ch. 2.4 - Prob. 14PS Ch. 2.4 - Prob. 15PS Ch. 2.4 - Prob. 16PS Ch. 2.4 - Prob. 17PS Ch. 2.4 - Prob. 18PS Ch. 2.4 - Prob. 19PS Ch. 2.4 - Prob. 20PS Ch. 2.4 - Prob. 21PS Ch. 2.4 - Prob. 22PS Ch. 2.4 - Prob. 23PS Ch. 2.4 - Prob. 24PS Ch. 2.4 - Prob. 25PS Ch. 2.4 - Prob. 26PS Ch. 2.4 - 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Tofind: All the points of discontinuity for the function f ( x ) = { x 2 − 2 if x > 1 2 x − 3 if x ≤ 1

Solution Summary: The author calculates that the given function is continuous for all xin R and the only point where it is breakable is at

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Tofind:All the points of discontinuity for the function

f(x)={x2−2 if x>12x−3 if x≤1

Want to see the full answer?

Chapter 2 Solutions

Tofind: All the points of discontinuity for the function f ( x ) = { x 2 − 2 if x &gt; 1 2 x − 3 if x ≤ 1

Solution Summary: The author calculates that the given function is continuous for all xin R and the only point where it is breakable is at

Videos

Tofind:All the points of discontinuity for the function f(x)={x2−2 if x>12x−3 if x≤1

Want to see the full answer?

Chapter 2 Solutions

Tofind: All the points of discontinuity for the function f ( x ) = { x 2 − 2 if x > 1 2 x − 3 if x ≤ 1

Tofind:All the points of discontinuity for the function

f(x)={x2−2 if x>12x−3 if x≤1