BIOCHEM-ACHIEVE(FIRST DAY DISCOUNTED)
9th Edition
ISBN: 2818000069358
Author: BERG
Publisher: MAC HIGHER
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Question
Chapter 23, Problem 10P
Interpretation Introduction
Interpretation:
The identify the rapid donors of the nitrogen atoms of urea.
Concept introduction:
The urea cycle is a series of biochemical reactions which involve the formation of urea (NH2)2CO from the ammonia (NH3). It is also known as the ornithine cycle. It helps in the excretion of toxic ammonia by converting into urea. This cycle takes place in ureotelic organisms.
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Students have asked these similar questions
At a pH equal to the isoelectric point (pl) of alanine, the net charge of alanine is zero. Two structures can be drawn that have a
net charge of zero, but the predominant form of alanine at its pl is zwitterionic.
CH3
H,N
CH3
**
H¸N-C
H
Zwitterionic
H
Uncharged
OH
Select statements that explain why alanine is predominantly zwitterionic at its pl.
pk of alanine's amino group is more than its pl.
pk of alanine's carboxyl group is more than its pl.
PK of alanine's carboxyl group is less than its pl.
pk of alanine's amino group is less than its pl.
Correct Answer
What fraction of alanine is in the completely uncharged form at its pl?
1 in 2.2 × 107
1 in 1.6 × 10²
1 in 4680
1 in 9460
How does a voltage-gated sodium channel work? Specifically, how and why does a change in voltage trigger their opening? Please be detailed
When sodium ions enter a neuron during depolarization, they trigger the opening of additional voltage-gated sodium channels nearby, creating a positive feedback loop where the influx of sodium ions further depolarizes the membrane, causing even more sodium channels to open and allowing more sodium ions to enter the cell, thus sustaining the depolarization process until the action potential peaks. But how and why exactly does the influx of sodium ions trigger more sodium channels to let in more sodium? Please explain
Chapter 23 Solutions
BIOCHEM-ACHIEVE(FIRST DAY DISCOUNTED)
Ch. 23 - Prob. 1PCh. 23 - Prob. 2PCh. 23 - Prob. 3PCh. 23 - Prob. 4PCh. 23 - Prob. 5PCh. 23 - Prob. 6PCh. 23 - Prob. 7PCh. 23 - Prob. 8PCh. 23 - Prob. 9PCh. 23 - Prob. 10P
Ch. 23 - Prob. 11PCh. 23 - Prob. 12PCh. 23 - Prob. 13PCh. 23 - Prob. 14PCh. 23 - Prob. 15PCh. 23 - Prob. 16PCh. 23 - Prob. 17PCh. 23 - Prob. 18PCh. 23 - Prob. 19PCh. 23 - Prob. 20PCh. 23 - Prob. 21PCh. 23 - Prob. 22PCh. 23 - Prob. 23PCh. 23 - Prob. 24PCh. 23 - Prob. 25PCh. 23 - Prob. 26PCh. 23 - Prob. 27PCh. 23 - Prob. 28PCh. 23 - Prob. 29PCh. 23 - Prob. 30PCh. 23 - Prob. 31PCh. 23 - Prob. 32PCh. 23 - Prob. 33PCh. 23 - Prob. 34PCh. 23 - Prob. 35PCh. 23 - Prob. 36PCh. 23 - Prob. 37PCh. 23 - Prob. 38PCh. 23 - Prob. 39PCh. 23 - Prob. 40PCh. 23 - Prob. 41PCh. 23 - Prob. 42PCh. 23 - Prob. 43PCh. 23 - Prob. 44PCh. 23 - Prob. 45PCh. 23 - Prob. 46PCh. 23 - Prob. 47PCh. 23 - Prob. 48PCh. 23 - Prob. 49P
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