
EBK ORGANIC CHEMISTRY
12th Edition
ISBN: 9781119233664
Author: Snyder
Publisher: VST
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Textbook Question
Chapter 22, Problem 9PP
Practice Problem 22.9
What products would you expect to be formed when each of the following compounds is treated with an appropriate amount of periodic acid? How many molar equivalents of HIO4 would be consumed in each case?
(a) 2,3-Butanediol
(b) 1,2,3-Butanetriol
(c)
(d)
(e)
(f) cis-1,2-Cyclopentanediol
(g)
(h) D-Erythrose
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b.
CH3
H3C
CH3
CH3
H3C
an unexpected product,
containing a single 9-
membered ring
the expected product,
containing two fused rings
H3C-I
(H3C)2CuLi
an enolate
b.
H3C
CH3
1.
2. H3O+
H3C
MgBr
H3C
Predict the major products of this reaction:
excess
H+
NaOH
?
A
Note that the first reactant is used in excess, that is, there is much more of the first reactant than the second.
If there won't be any products, just check the box under the drawing area instead.
Explanation
Check
Click and drag to start drawing a
structure.
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Chapter 22 Solutions
EBK ORGANIC CHEMISTRY
Ch. 22 - Prob. 1PPCh. 22 - Prob. 2PPCh. 22 - Prob. 3PPCh. 22 - Prob. 4PPCh. 22 - Prob. 5PPCh. 22 - Prob. 6PPCh. 22 - Prob. 7PPCh. 22 - Prob. 8PPCh. 22 - Practice Problem 22.9 What products would you...Ch. 22 - Prob. 10PP
Ch. 22 - Prob. 11PPCh. 22 - Prob. 12PPCh. 22 - Prob. 13PPCh. 22 - Prob. 14PPCh. 22 - Prob. 15PPCh. 22 - Prob. 16PPCh. 22 - Prob. 17PPCh. 22 - Prob. 18PPCh. 22 - Prob. 19PPCh. 22 - Prob. 20PCh. 22 - Prob. 21PCh. 22 - Prob. 22PCh. 22 - Prob. 23PCh. 22 - Prob. 24PCh. 22 - Prob. 25PCh. 22 - Prob. 26PCh. 22 - Prob. 27PCh. 22 - Prob. 28PCh. 22 - Prob. 29PCh. 22 - Prob. 30PCh. 22 - Prob. 31PCh. 22 - Prob. 32PCh. 22 - Prob. 33PCh. 22 - Prob. 34PCh. 22 - Prob. 35PCh. 22 - Prob. 36PCh. 22 - Prob. 37PCh. 22 - Prob. 38PCh. 22 - Arbutin, a compound that can be isolated from the...Ch. 22 - Prob. 40PCh. 22 - Prob. 41PCh. 22 - Prob. 42PCh. 22 - Prob. 43PCh. 22 - 22.44 The following reaction sequence represents...Ch. 22 - 22.45
The NMR data for the two anomers...Ch. 22 - Shikimic acid is a key biosynthetic intermediate...
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