KLEIN'S ORGANIC CHEMISTRY
3rd Edition
ISBN: 9781119423126
Author: Klein
Publisher: WILEY
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Question
Chapter 22, Problem 96CP
(a)
Interpretation Introduction
Interpretation: The structures of 3 and 4 with diastereomeric centers have to be drawn
Concept Introduction:
Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions.
If a carbon is attached with four different groups without any elements of symmetry, then that center has a chirality center. Diastereomers (sometimes called diastereoisomers) are a type of a stereoisomer. Diastereomerism occurs when two or more stereoisomers of a compound have different configurations at one or more stereocenters and are not mirror images of each other. When two diastereoisomers differ from each other at only one stereocenter, they are epimers. Each stereocenter gives rise to two different configurations and thus increases the number of stereoisomers by a factor of two.
To find: Draw the structure of 3 and the reason for its production as a diastereomeric mixture
Do reductive amination in compound 2
(b)
Interpretation Introduction
Interpretation: The structures of 3 and 4 with diastereomeric centers have to be drawn
Concept Introduction:
An amide group is formed from an amine compound and the ester group.
If a carbon is attached with four different groups without any elements of symmetry, then that center has a chirality center. Diastereomers (sometimes called diastereoisomers) are a type of a stereoisomer. Diastereomerism occurs when two or more stereoisomers of a compound have different configurations at one or more stereocenters and are not mirror images of each other. When two diastereoisomers differ from each other at only one stereocenter, they are epimers. Each stereocenter gives rise to two different configurations and thus increases the number of stereoisomers by a factor of two.
To find: Draw the structure of 4 and determine the possibility of its production as a diastereomeric mixture
Decide the nature of the
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Students have asked these similar questions
20. The Brusselator. This hypothetical system was first proposed by a group work-
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nonuniform chemical patterns. Because certain steps involve trimolecular reac
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has been studied extensively. The reaction steps are
A-X.
B+X-Y+D.
2X+ Y-3X,
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305
It is assumed that concentrations of A, B, D, and E are kept artificially con
stant so that only X and Y vary with time.
(a) Show that if all rate constants are chosen appropriately, the equations de
scribing a Brusselator are:
dt
A-(B+ 1)x + x²y,
dy
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di
Problem 3. Provide a mechanism for the following transformation:
H₂SO A
Me.
Me
Me
Me
Me
You are trying to decide if there is a single reagent you can add that will make the following synthesis possible without any other major side products:
xi
1. ☑
2. H₂O
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i
Draw the missing reagent X you think will make this synthesis work in the drawing area below.
If there is no reagent that will make your desired product in good yield or without complications, just check the box under the drawing area and leave it blank.
Click and drag to start drawing a
structure.
There is no reagent that will make this synthesis work without complications.
: ☐
S
☐
Chapter 22 Solutions
KLEIN'S ORGANIC CHEMISTRY
Ch. 22.2 - Prob. 1LTSCh. 22.2 - Prob. 1PTSCh. 22.2 - Prob. 2PTSCh. 22.2 - Prob. 3ATSCh. 22.3 - Prob. 4CCCh. 22.3 - Prob. 5CCCh. 22.3 - Prob. 6CCCh. 22.3 - Prob. 7CCCh. 22.3 - Prob. 8CCCh. 22.3 - Prob. 9CC
Ch. 22.4 - Prob. 10CCCh. 22.4 - Prob. 11CCCh. 22.5 - Prob. 2LTSCh. 22.5 - Prob. 12PTSCh. 22.5 - Prob. 13ATSCh. 22.6 - Prob. 3LTSCh. 22.6 - Prob. 14PTSCh. 22.6 - Prob. 15ATSCh. 22.7 - Prob. 4LTSCh. 22.7 - Prob. 16PTSCh. 22.7 - Prob. 17PTSCh. 22.7 - Prob. 18PTSCh. 22.7 - Prob. 19ATSCh. 22.8 - Prob. 20CCCh. 22.8 - Prob. 21CCCh. 22.8 - Prob. 22CCCh. 22.9 - Prob. 5LTSCh. 22.9 - Prob. 23PTSCh. 22.9 - Prob. 24ATSCh. 22.10 - Prob. 25CCCh. 22.11 - Prob. 26CCCh. 22.11 - Prob. 6LTSCh. 22.11 - Prob. 27PTSCh. 22.11 - Prob. 28ATSCh. 22.12 - Prob. 29CCCh. 22.12 - Prob. 30CCCh. 22.13 - Prob. 31CCCh. 22.13 - Prob. 32CCCh. 22 - Prob. 33PPCh. 22 - Prob. 34PPCh. 22 - Prob. 35PPCh. 22 - Prob. 36PPCh. 22 - Prob. 37PPCh. 22 - Prob. 38PPCh. 22 - Prob. 39PPCh. 22 - Prob. 40PPCh. 22 - Prob. 41PPCh. 22 - Prob. 42PPCh. 22 - Prob. 43PPCh. 22 - Prob. 44PPCh. 22 - Prob. 45PPCh. 22 - Prob. 46PPCh. 22 - Prob. 47PPCh. 22 - Prob. 48PPCh. 22 - Prob. 49PPCh. 22 - Prob. 50PPCh. 22 - Prob. 51PPCh. 22 - Prob. 52PPCh. 22 - Prob. 53PPCh. 22 - Prob. 54PPCh. 22 - Prob. 55PPCh. 22 - Prob. 56PPCh. 22 - Prob. 57PPCh. 22 - Prob. 58PPCh. 22 - Prob. 59PPCh. 22 - Prob. 60PPCh. 22 - Prob. 61PPCh. 22 - Prob. 62PPCh. 22 - Prob. 63PPCh. 22 - Prob. 64PPCh. 22 - Prob. 65PPCh. 22 - Prob. 66PPCh. 22 - Prob. 67PPCh. 22 - Prob. 68PPCh. 22 - Prob. 69PPCh. 22 - Prob. 70PPCh. 22 - Prob. 71PPCh. 22 - Prob. 72PPCh. 22 - Prob. 73IPCh. 22 - Prob. 74IPCh. 22 - Prob. 75IPCh. 22 - Prob. 76IPCh. 22 - Prob. 77IPCh. 22 - Prob. 78IPCh. 22 - Prob. 79IPCh. 22 - Prob. 80IPCh. 22 - Prob. 81IPCh. 22 - Prob. 82IPCh. 22 - Prob. 83IPCh. 22 - Prob. 84IPCh. 22 - Prob. 85IPCh. 22 - Prob. 86IPCh. 22 - Prob. 87IPCh. 22 - Prob. 88IPCh. 22 - Prob. 89IPCh. 22 - Prob. 90IPCh. 22 - Prob. 91IPCh. 22 - Prob. 92IPCh. 22 - Prob. 93IPCh. 22 - Prob. 94IPCh. 22 - Prob. 95IPCh. 22 - Prob. 96CPCh. 22 - Prob. 97CPCh. 22 - Prob. 98CPCh. 22 - Prob. 99CP
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