In the asymmetric synthesis of (−)-(S,S)-homaline, the conversion of compound 1 into compound 2 has to be found. Concept Introduction : Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines . An azide synthesis involves the reaction between alkyl halide and sodium azide. Alkyl azide is formed. To find: Convert the compound 1 into compound 2 in the asymmetric synthesis of (−)-(S,S)-homaline Show the synthetic route of reductive amination

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Answer 1

Question

Chapter 22, Problem 90IP

Interpretation Introduction

Interpretation: In the asymmetric synthesis of (−)-(S,S)-homaline, the conversion of compound 1 into compound 2 has to be found.

Concept Introduction:

Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.

An azide synthesis involves the reaction between alkyl halide and sodium azide. Alkyl azide is formed.

To find: Convert the compound 1 into compound 2 in the asymmetric synthesis of (−)-(S,S)-homaline

Show the synthetic route of reductive amination

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Answer 2

Question

Chapter 22, Problem 90IP

Interpretation Introduction

Interpretation: In the asymmetric synthesis of (−)-(S,S)-homaline, the conversion of compound 1 into compound 2 has to be found.

Concept Introduction:

Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.

An azide synthesis involves the reaction between alkyl halide and sodium azide. Alkyl azide is formed.

To find: Convert the compound 1 into compound 2 in the asymmetric synthesis of (−)-(S,S)-homaline

Show the synthetic route of reductive amination

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 22, Problem 90IP

Interpretation Introduction

Interpretation: In the asymmetric synthesis of (−)-(S,S)-homaline, the conversion of compound 1 into compound 2 has to be found.

Concept Introduction:

Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.

An azide synthesis involves the reaction between alkyl halide and sodium azide. Alkyl azide is formed.

To find: Convert the compound 1 into compound 2 in the asymmetric synthesis of (−)-(S,S)-homaline

Show the synthetic route of reductive amination

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 22, Problem 90IP

Interpretation Introduction

Interpretation: In the asymmetric synthesis of (−)-(S,S)-homaline, the conversion of compound 1 into compound 2 has to be found.

Concept Introduction:

Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.

An azide synthesis involves the reaction between alkyl halide and sodium azide. Alkyl azide is formed.

To find: Convert the compound 1 into compound 2 in the asymmetric synthesis of (−)-(S,S)-homaline

Show the synthetic route of reductive amination

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 22, Problem 90IP

Interpretation Introduction

Interpretation: In the asymmetric synthesis of (−)-(S,S)-homaline, the conversion of compound 1 into compound 2 has to be found.

Concept Introduction:

Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.

An azide synthesis involves the reaction between alkyl halide and sodium azide. Alkyl azide is formed.

To find: Convert the compound 1 into compound 2 in the asymmetric synthesis of (−)-(S,S)-homaline

Show the synthetic route of reductive amination

Answer 6

Chapter 22, Problem 90IP

Interpretation Introduction

Interpretation: In the asymmetric synthesis of (−)-(S,S)-homaline, the conversion of compound 1 into compound 2 has to be found.

Concept Introduction:

Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.

An azide synthesis involves the reaction between alkyl halide and sodium azide. Alkyl azide is formed.

To find: Convert the compound 1 into compound 2 in the asymmetric synthesis of (−)-(S,S)-homaline

Show the synthetic route of reductive amination

Answer 7

Chapter 22, Problem 90IP

Interpretation Introduction

Interpretation: In the asymmetric synthesis of (−)-(S,S)-homaline, the conversion of compound 1 into compound 2 has to be found.

Concept Introduction:

Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.

An azide synthesis involves the reaction between alkyl halide and sodium azide. Alkyl azide is formed.

To find: Convert the compound 1 into compound 2 in the asymmetric synthesis of (−)-(S,S)-homaline

Show the synthetic route of reductive amination

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 22.2 - Prob. 1LTS Ch. 22.2 - Prob. 1PTS Ch. 22.2 - Prob. 2PTS Ch. 22.2 - Prob. 3ATS Ch. 22.3 - Prob. 4CC Ch. 22.3 - Prob. 5CC Ch. 22.3 - Prob. 6CC Ch. 22.3 - Prob. 7CC Ch. 22.3 - Prob. 8CC Ch. 22.3 - Prob. 9CC

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Chapter 22 Solutions