Chapter 22, Problem 8P

To determine

The frequency

Answer to Problem 8P

The answer is $4.62\times {10}^{14}Hz$ , visible.

Explanation of Solution

Given info:

Wavelength, $\lambda =650nm=650\times {10}^{-9}m$

Factor, $c=3.00\times {10}^{8}m/s$

Formula used:

The relation between frequency and wavelength: $f=\frac{c}{\lambda }$

Where,

  $f$ is frequency

  $\lambda$ is wavelength

  $c$ is a factor

Calculation:

Substitute the given values in formula, $f=\frac{c}{\lambda }$

  $f=\frac{3\times {10}^{8}m/s}{650\times {10}^{-9}m}=4.62\times {10}^{14}Hz$

This frequency is just outside the red end of the visible region.So, it is visible.

Conclusion: The required frequency is $4.62\times {10}^{14}Hz$ , visible.