Chapter 22, Problem 10P

To determine

The frequency of a $49m$ radio signal.

Answer to Problem 10P

The answer is $6.1\times {10}^{6}Hz$ .

Explanation of Solution

Given info:

Wavelength, $\lambda =49m$

Factor, $c=3.00\times {10}^{8}m/s$

Formula used:

The relation between frequency and wavelength: $f=\frac{c}{\lambda }$

Where,

  $f$ is frequency

  $\lambda$ is wavelength

  $c$ is a factor

Calculation:

Substitute the given values in formula, $f=\frac{c}{\lambda }$

  $f=\frac{3\times {10}^{8}m/s}{49m}=6.1\times {10}^{6}Hz$

Conclusion: The required frequency is $6.1\times {10}^{6}Hz$ .