Chapter 22, Problem 6P

To determine

The wavelength of a $29.75\times {10}^{9}Hz$ radar signal.

Answer to Problem 6P

The answer is $1.008\times {10}^{-2}m$ .

Explanation of Solution

Given info:

Frequency, $f=29.75\times {10}^{9}Hz$

Factor, $c=3.00\times {10}^{8}m/s$

Formula used:

The relation between frequency and wavelength: $f=\frac{c}{\lambda }$

Where,

  $f$ is frequency

  $\lambda$ is wavelength

  $c$ is a factor

Calculation:

Rearrange the relation between frequency and wavelength: $f=\frac{c}{\lambda }$ . So, $\lambda =\frac{c}{f}$

Substitute the given values in formula, $\lambda =\frac{c}{f}$

  $\lambda =\frac{3\times {10}^{8}m/s}{29.75\times {10}^{9}Hz}=1.008\times {10}^{-2}m$

Conclusion: The required wavelength is $1.008\times {10}^{-2}m$ .