Physics
Physics
5th Edition
ISBN: 9781260486919
Author: GIAMBATTISTA
Publisher: MCG
bartleby

Videos

Question
Book Icon
Chapter 22, Problem 86P

(a)

To determine

The alignment of axis of coil.

(a)

Expert Solution
Check Mark

Answer to Problem 86P

The alignment of axis of coil has to be with magnetic field.

Explanation of Solution

For the best result of magnetic dipole antenna which is used to detect electromagnetic waves, the magnetic flux associated with the axis of the coil have to be the highest.

The alignment of axis of coil has to be with magnetic field so that the total magnetic flux in the coil will be the maximum.

(b)

To determine

The amplitude of the induced emf in the coil.

(b)

Expert Solution
Check Mark

Answer to Problem 86P

The amplitude of the induced emf in the coil is 3.6mV.

Explanation of Solution

Write the expression for Faraday’s law.

  |ε|=NΔΦBΔt                                                                                        (I)

Here, |ε| is the induced emf in the coil, N is the number of turns in coil, and ΔΦBΔt is the change in magnetic flux.

Write the expression to find the maximum magnetic flux.

  ΦB=BA=B(πr2)                                                                                         (II)

Here, B is the magnetic field, A is the area of the coil, and r is the radius of coil.

Substitute equation (II) in (I) to find the amplitude of the induced emf in the coil.

  |ε|=NΔ(B(πr2))Δt=Nπr2ΔBΔt                                                                                       (III)

Consider that field is sinusoidal.

Write the expression to find the magnetic field.

  B=Bmsin(kz+ωt)                                                                                        (IV)

Here, k is the wave number, ω is the angular velocity, and Bm is the amplitude of magnetic field.

Substitute equation (IV) in (III) to find the induced emf in the coil.

  |ε|=Nπr2Δ(Bmsin(kz+ωt))Δt=Nπr2Δ(ωBmcos(kz+ωt))Δt

Re-write the expression considering the maximum value of ΔBΔt.

  |ε|=Nπr2ωBm

Conclusion:

Substitute 50 for N, 5.0cm for r, 870kHz for ω, and 1.7×109T for Bm to find the amplitude of the induced emf in the coil.

  |ε|=(50)π(5.0cm102m1.0cm)2(870kHz103Hz1.0kHz)(1.7×109T)=(50)π(5.0×102m)2(870×103Hz)(1.7×109T)=3.6×103V(1mV103V)=3.6mV

(c)

To determine

The amplitude of emf induced in an electric dipole antenna.

(c)

Expert Solution
Check Mark

Answer to Problem 86P

The amplitude of emf induced in an electric dipole antenna is 25mV.

Explanation of Solution

Write the expression to find the amplitude of emf induced in an electric dipole antenna.

  εm=EmL

Here, εm is the amplitude of emf induced in an electric dipole antenna, Em is the electric field amplitude, and L is the length of antenna.

Conclusion:

Substitute 5.0cm for L and 0.50V/m for λ to find the amplitude of emf induced in an electric dipole antenna.

  εm=(0.50V/m)(5.0cm102m1.0cm)=25×103V(1mV103V)=25mV

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
A uniform ladder of length L and weight w is leaning against a vertical wall. The coefficient of static friction between the ladder and the floor is the same as that between the ladder and the wall. If this coefficient of static friction is μs : 0.535, determine the smallest angle the ladder can make with the floor without slipping. ° = A 14.0 m uniform ladder weighing 480 N rests against a frictionless wall. The ladder makes a 55.0°-angle with the horizontal. (a) Find the horizontal and vertical forces (in N) the ground exerts on the base of the ladder when an 850-N firefighter has climbed 4.10 m along the ladder from the bottom. horizontal force magnitude 342. N direction towards the wall ✓ vertical force 1330 N up magnitude direction (b) If the ladder is just on the verge of slipping when the firefighter is 9.10 m from the bottom, what is the coefficient of static friction between ladder and ground? 0.26 × You appear to be using 4.10 m from part (a) for the position of the…
Your neighbor designs automobiles for a living. You are fascinated with her work. She is designing a new automobile and needs to determine how strong the front suspension should be. She knows of your fascination with her work and your expertise in physics, so she asks you to determine how large the normal force on the front wheels of her design automobile could become under a hard stop, ma when the wheels are locked and the automobile is skidding on the road. She gives you the following information. The mass of the automobile is m₂ = 1.10 × 103 kg and it can carry five passengers of average mass m = 80.0 kg. The front and rear wheels are separated by d = 4.45 m. The center of mass of the car carrying five passengers is dCM = 2.25 m behind the front wheels and hcm = 0.630 m above the roadway. A typical coefficient of kinetic friction between tires and roadway is μk 0.840. (Caution: The braking automobile is not in an inertial reference frame. Enter the magnitude of the force in N.)…
John is pushing his daughter Rachel in a wheelbarrow when it is stopped by a brick 8.00 cm high (see the figure below). The handles make an angle of 0 = 17.5° with the ground. Due to the weight of Rachel and the wheelbarrow, a downward force of 403 N is exerted at the center of the wheel, which has a radius of 16.0 cm. Assume the brick remains fixed and does not slide along the ground. Also assume the force applied by John is directed exactly toward the center of the wheel. (Choose the positive x-axis to be pointing to the right.) (a) What force (in N) must John apply along the handles to just start the wheel over the brick? (No Response) N (b) What is the force (magnitude in kN and direction in degrees clockwise from the -x-axis) that the brick exerts on the wheel just as the wheel begins to lift over the brick? magnitude (No Response) KN direction (No Response) ° clockwise from the -x-axis

Chapter 22 Solutions

Physics

Ch. 22.7 - Prob. 22.7PPCh. 22.7 - Prob. 22.8PPCh. 22.8 - Prob. 22.9PPCh. 22 - Prob. 1CQCh. 22 - Prob. 2CQCh. 22 - Prob. 3CQCh. 22 - Prob. 4CQCh. 22 - Prob. 5CQCh. 22 - Prob. 6CQCh. 22 - Prob. 7CQCh. 22 - Prob. 8CQCh. 22 - Prob. 9CQCh. 22 - Prob. 10CQCh. 22 - Prob. 11CQCh. 22 - Prob. 12CQCh. 22 - Prob. 13CQCh. 22 - Prob. 14CQCh. 22 - Prob. 15CQCh. 22 - Prob. 1MCQCh. 22 - Prob. 2MCQCh. 22 - Prob. 3MCQCh. 22 - Prob. 4MCQCh. 22 - 5. If the wavelength of an electromagnetic wave is...Ch. 22 - Prob. 6MCQCh. 22 - 7. A dipole radio transmitter has its rod-shaped...Ch. 22 - Prob. 8MCQCh. 22 - Prob. 9MCQCh. 22 - Prob. 10MCQCh. 22 - Prob. 1PCh. 22 - Prob. 2PCh. 22 - Prob. 3PCh. 22 - Prob. 4PCh. 22 - Prob. 5PCh. 22 - 6. What is the wavelength of the radio waves...Ch. 22 - Prob. 7PCh. 22 - Prob. 8PCh. 22 - Prob. 9PCh. 22 - Prob. 10PCh. 22 - Prob. 12PCh. 22 - 12. In order to study the structure of a...Ch. 22 - Prob. 13PCh. 22 - 14. When the NASA Rover Spirit successfully landed...Ch. 22 - Prob. 15PCh. 22 - 16. You and a friend are sitting in the outfield...Ch. 22 - Prob. 14PCh. 22 - Prob. 18PCh. 22 - Prob. 17PCh. 22 - Prob. 20PCh. 22 - Prob. 21PCh. 22 - Prob. 22PCh. 22 - Prob. 23PCh. 22 - Prob. 24PCh. 22 - Prob. 25PCh. 22 - Prob. 26PCh. 22 - Prob. 27PCh. 22 - Prob. 28PCh. 22 - Prob. 29PCh. 22 - 30. The intensity of the sunlight that reaches...Ch. 22 - Prob. 31PCh. 22 - Prob. 32PCh. 22 - Prob. 33PCh. 22 - Prob. 34PCh. 22 - Prob. 35PCh. 22 - 36. The intensity of the sunlight that reaches...Ch. 22 - Prob. 37PCh. 22 - Prob. 38PCh. 22 - Prob. 39PCh. 22 - Prob. 40PCh. 22 - Prob. 41PCh. 22 - Prob. 42PCh. 22 - Prob. 43PCh. 22 - Prob. 44PCh. 22 - Prob. 45PCh. 22 - Prob. 46PCh. 22 - Prob. 47PCh. 22 - Prob. 48PCh. 22 - Prob. 49PCh. 22 - Prob. 50PCh. 22 - Prob. 51PCh. 22 - Prob. 52PCh. 22 - Prob. 53PCh. 22 - Prob. 54PCh. 22 - Prob. 55PCh. 22 - Prob. 56PCh. 22 - Prob. 57PCh. 22 - Prob. 58PCh. 22 - Prob. 59PCh. 22 - Prob. 60PCh. 22 - Prob. 62PCh. 22 - Prob. 61PCh. 22 - Prob. 63PCh. 22 - Prob. 64PCh. 22 - Prob. 65PCh. 22 - Prob. 66PCh. 22 - Prob. 67PCh. 22 - Prob. 68PCh. 22 - Prob. 69PCh. 22 - Prob. 70PCh. 22 - Prob. 71PCh. 22 - Prob. 72PCh. 22 - Prob. 73PCh. 22 - Prob. 74PCh. 22 - Prob. 75PCh. 22 - Prob. 76PCh. 22 - Prob. 77PCh. 22 - Prob. 78PCh. 22 - Prob. 80PCh. 22 - Prob. 82PCh. 22 - Prob. 79PCh. 22 - Prob. 81PCh. 22 - Prob. 84PCh. 22 - Prob. 83PCh. 22 - Prob. 86PCh. 22 - Prob. 85P
Knowledge Booster
Background pattern image
Physics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Text book image
University Physics (14th Edition)
Physics
ISBN:9780133969290
Author:Hugh D. Young, Roger A. Freedman
Publisher:PEARSON
Text book image
Introduction To Quantum Mechanics
Physics
ISBN:9781107189638
Author:Griffiths, David J., Schroeter, Darrell F.
Publisher:Cambridge University Press
Text book image
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:9780321820464
Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:Addison-Wesley
Text book image
College Physics: A Strategic Approach (4th Editio...
Physics
ISBN:9780134609034
Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:PEARSON
What Are Electromagnetic Wave Properties? | Physics in Motion; Author: GPB Education;https://www.youtube.com/watch?v=ftyxZBxBexI;License: Standard YouTube License, CC-BY