Concept explainers
(a)
Interpretation:
The informational strand of DNA that correspond to the given DNA template strand should be written.
Concept Introduction:
Conversion of genetic information in DNA into mRNA is called transcription. DNA is in double helix form and in order to proceed transcription, DNA double strand should be separated. Template strand is the strand of DNA used for transcription. Informational strand is the complementary strand of the template strand.
(b)
Interpretation:
mRNA prepared from the given template should be written.
Concept Introduction:
Conversion of genetic information in DNA into mRNA is called transcription. The DNA strand from the DNA double helix which is used for mRNA synthesis is the template strand. Transcription proceeds from 3' end to 5' end. Complementary base pairing determines which
(c)
Interpretation:
The polypeptide prepared from the mRNA transcribed should be determined.
Concept Introduction:
mRNA strand provides code for the synthesis of polypeptide chain with 20 different amino acids. A sequence of three nucleotides which is called a codon codes for a specific amino acid. There are 4 types of nucleotides found in RNA strand which are A, C, G and U. These four nucleotides can be combine in 64 different ways to make codons with three nucleotides. From these, only 61 codes for amino acids. Other three does not correspond to any of the amino acid, so, they are called stop codons.
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Chapter 22 Solutions
GENERAL,ORGANIC, & BIOLOGICAL CHEM-ACCES
- Don't used hand raitingarrow_forwardQuizzes - Gen Organic & Biological Che... ☆ myd21.lcc.edu + O G screenshot on mac - Google Search savings hulu youtube google disney+ HBO zlib Homework Hel...s | bartleby cell bio book Yuzu Reader: Chemistry G periodic table - Google Search b Home | bartleby 0:33:26 remaining CHEM 120 Chapter 5_Quiz 3 Page 1: 1 > 2 > 3 > 6 ¦ 5 > 4 > 7 ¦ 1 1 10 8 ¦ 9 a ¦ -- Quiz Information silicon-27 A doctor gives a patient 0.01 mC i of beta radiation. How many beta particles would the patient receive in I minute? (1 Ci = 3.7 x 10 10 d/s) Question 5 (1 point) Saved Listen 2.22 x 107 222 x 108 3.7 x 108 2.22 x 108 none of the above Question 6 (1 point) Listen The recommended dosage of 1-131 for a test is 4.2 μCi per kg of body mass. How many millicuries should be given to a 55 kg patient? (1 mCi = 1000 μСi)? 230 mCiarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
- Don't used hand raiting and don't used Ai solutionarrow_forwardQ3: Arrange each group of compounds from fastest SN2 reaction rate to slowest SN2 reaction rate. CI Cl H3C-Cl CI a) A B C D Br Br b) A B C Br H3C-Br Darrow_forwardQ4: Rank the relative nucleophilicity of halide ions in water solution and DMF solution, respectively. F CI Br | Q5: Determine which of the substrates will and will not react with NaSCH3 in an SN2 reaction to have a reasonable yield of product. NH2 Br Br Br .OH Brarrow_forward
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- General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningOrganic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,
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