(a) Answer The value of limit of f ( x ) = { 1 x , x < 0 − 1 , x ≥ 0 as x → − ∞ is 0 . Explanation Given information: The function is f ( x ) = { 1 x , x < 0 − 1 , x ≥ 0 . Calculation: Consider the given function f ( x ) = { 1 x , x < 0 − 1 , x ≥ 0 . For x → − ∞ , the function is f ( x ) = 1 x . So, lim x → − ∞ f ( x ) = lim x → − ∞ ( 1 x ) = 0 Therefore, the value of limit of f ( x ) = { 1 x , x < 0 − 1 , x ≥ 0 when x → − ∞ is 0 . (b) To determine To find: The value of limit of f ( x ) = { 1 x , x < 0 − 1 , x ≥ 0 when x → ∞ . Answer The value of limit of f ( x ) = { 1 x , x < 0 − 1 , x ≥ 0 as x → ∞ is − 1 . Explanation Given information: The given function is f ( x ) = { 1 x , x < 0 − 1 , x ≥ 0 . Calculation: Consider the given function f ( x ) = { 1 x , x < 0 − 1 , x ≥ 0 . For x → ∞ , the function is f ( x ) = − 1 . So, lim x → ∞ f ( x ) = − 1 Therefore, the value of limit of f ( x ) = { 1 x , x < 0 − 1 , x ≥ 0 as x → ∞ is − 1 . (c) To determine To find: The value of limit of f ( x ) = { 1 x , x < 0 − 1 , x ≥ 0 as x → 0 − . Answer The value of limit of f ( x ) = { 1 x , x < 0 − 1 , x ≥ 0 as x → 0 − is − ∞ . Explanation Given information: The given function is f ( x ) = { 1 x , x < 0 − 1 , x ≥ 0 . Calculation: As x approaches to 0 from the left side, the function is f ( x ) = ( 1 x ) . The value of limit is: lim x → 0 − f ( x ) = lim x → 0 − ( 1 x ) = − ∞ Therefore, the value of limit of f ( x ) = { 1 x , x < 0 − 1 , x ≥ 0 when x → 0 − is − ∞ . (d) To determine To find: The value of limit of f ( x ) = { 1 x , x < 0 − 1 , x ≥ 0 as x → 0 + . Answer The value of limit of f ( x ) = { 1 x , x < 0 − 1 , x ≥ 0 as x → 0 + is − 1 . Explanation Given information: The given function is f ( x ) = { 1 x , x < 0 − 1 , x ≥ 0 . Calculation: As x approaches to 0 from the left side, the function is f ( x ) = − 1 . The value of limit is: lim x → 0 + f ( x ) = lim x → 0 + ( − 1 ) = − 1 Therefore, the value of limit of f ( x ) = { 1 x , x < 0 − 1 , x ≥ 0 as x → 0 + is − 1 .

Calculus: Graphical, Numerical, Algebraic: Solutions Manual

3rd Edition

ISBN: 9780132014144

Author: Ross L. Finney, Franklin Demana, Bert K. Waits, Daniel Kennedy

Publisher: Pearson Prentice Hall

See similar textbooks

Concept explainers

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topic…

Videos

Question

Chapter 2.2, Problem 53E

(a)

To determine

To find: The value of limit of f(x)={1x, x<0−1, x≥0 as x→−∞ .

(a)

Expert Solution

Answer to Problem 53E

The value of limit of f(x)={1x, x<0−1, x≥0 as x→−∞ is 0 .

Explanation of Solution

Given information:

The function is f(x)={1x, x<0−1, x≥0 .

Calculation:

Consider the given function f(x)={1x, x<0−1, x≥0 .

For x→−∞ , the function is f(x)=1x . So,

limx→−∞f(x)=limx→−∞(1x)=0

Therefore, the value of limit of f(x)={1x, x<0−1, x≥0 when x→−∞ is 0 .

(b)

To determine

To find:The value of limit of f(x)={1x, x<0−1, x≥0 when x→∞ .

(b)

Expert Solution

Answer to Problem 53E

The value of limit of f(x)={1x, x<0−1, x≥0 as x→∞ is −1 .

Explanation of Solution

Given information:

The given function is f(x)={1x, x<0−1, x≥0 .

Calculation:

Consider the given function f(x)={1x, x<0−1, x≥0 .

For x→∞ , the function is f(x)=−1 . So,

limx→∞f(x)=−1

Therefore, the value of limit of f(x)={1x, x<0−1, x≥0 as x→∞ is −1 .

(c)

To determine

To find:The value of limit of f(x)={1x, x<0−1, x≥0 as x→0− .

(c)

Expert Solution

Answer to Problem 53E

The value of limit of f(x)={1x, x<0−1, x≥0 as x→0− is −∞ .

Explanation of Solution

Given information:

The given function is f(x)={1x, x<0−1, x≥0 .

Calculation:

As x approaches to 0 from the left side, the function is f(x)=(1x) .

The value of limit is:

limx→0−f(x)=limx→0−(1x)=−∞

Therefore, the value of limit of f(x)={1x, x<0−1, x≥0 when x→0− is −∞ .

(d)

To determine

To find:The value of limit of f(x)={1x, x<0−1, x≥0 as x→0+ .

(d)

Expert Solution

Answer to Problem 53E

The value of limit of f(x)={1x, x<0−1, x≥0 as x→0+ is −1 .

Explanation of Solution

Given information:

The given function is f(x)={1x, x<0−1, x≥0 .

Calculation:

As x approaches to 0 from the left side, the function is f(x)=−1 .

The value of limit is:

limx→0+f(x)=limx→0+(−1)=−1

Therefore, the value of limit of f(x)={1x, x<0−1, x≥0 as x→0+ is −1 .

Chapter 2.2, Problem 52E

Chapter 2.2, Problem 54E

Chapter 2 Solutions

Calculus: Graphical, Numerical, Algebraic: Solutions Manual

Ch. 2.1 - Prob. 1QR Ch. 2.1 - Prob. 2QR Ch. 2.1 - Prob. 3QR Ch. 2.1 - Prob. 4QR Ch. 2.1 - Prob. 5QR Ch. 2.1 - Prob. 6QR Ch. 2.1 - Prob. 7QR Ch. 2.1 - Prob. 8QR Ch. 2.1 - Prob. 9QR Ch. 2.1 - Prob. 10QR

Ch. 2.1 - Prob. 1E Ch. 2.1 - Prob. 2E Ch. 2.1 - Prob. 3E Ch. 2.1 - Prob. 4E Ch. 2.1 - Prob. 5E Ch. 2.1 - Prob. 6E Ch. 2.1 - Prob. 7E Ch. 2.1 - Prob. 8E Ch. 2.1 - Prob. 9E Ch. 2.1 - Prob. 10E Ch. 2.1 - Prob. 11E Ch. 2.1 - Prob. 12E Ch. 2.1 - Prob. 13E Ch. 2.1 - Prob. 14E Ch. 2.1 - Prob. 15E Ch. 2.1 - Prob. 16E Ch. 2.1 - Prob. 17E Ch. 2.1 - Prob. 18E Ch. 2.1 - Prob. 19E Ch. 2.1 - Prob. 20E Ch. 2.1 - Prob. 21E Ch. 2.1 - Prob. 22E Ch. 2.1 - Prob. 23E Ch. 2.1 - Prob. 24E Ch. 2.1 - Prob. 25E Ch. 2.1 - Prob. 26E Ch. 2.1 - Prob. 27E Ch. 2.1 - Prob. 28E Ch. 2.1 - Prob. 29E Ch. 2.1 - Prob. 30E Ch. 2.1 - Prob. 31E Ch. 2.1 - Prob. 32E Ch. 2.1 - Prob. 33E Ch. 2.1 - Prob. 34E Ch. 2.1 - Prob. 35E Ch. 2.1 - Prob. 36E Ch. 2.1 - Prob. 37E Ch. 2.1 - Prob. 38E Ch. 2.1 - Prob. 39E Ch. 2.1 - Prob. 40E Ch. 2.1 - Prob. 41E Ch. 2.1 - Prob. 42E Ch. 2.1 - Prob. 43E Ch. 2.1 - Prob. 44E Ch. 2.1 - Prob. 45E Ch. 2.1 - Prob. 46E Ch. 2.1 - Prob. 47E Ch. 2.1 - Prob. 48E Ch. 2.1 - Prob. 49E Ch. 2.1 - Prob. 50E Ch. 2.1 - Prob. 51E Ch. 2.1 - Prob. 52E Ch. 2.1 - Prob. 53E Ch. 2.1 - Prob. 54E Ch. 2.1 - Prob. 55E Ch. 2.1 - Prob. 56E Ch. 2.1 - Prob. 57E Ch. 2.1 - Prob. 58E Ch. 2.1 - Prob. 59E Ch. 2.1 - Prob. 60E Ch. 2.1 - Prob. 61E Ch. 2.1 - Prob. 62E Ch. 2.1 - Prob. 63E Ch. 2.1 - Prob. 64E Ch. 2.1 - Prob. 65E Ch. 2.1 - Prob. 66E Ch. 2.1 - Prob. 67E Ch. 2.1 - Prob. 68E Ch. 2.1 - Prob. 69E Ch. 2.1 - Prob. 70E Ch. 2.1 - Prob. 71E Ch. 2.1 - Prob. 72E Ch. 2.1 - Prob. 73E Ch. 2.1 - Prob. 74E Ch. 2.1 - Prob. 75E Ch. 2.1 - Prob. 76E Ch. 2.1 - Prob. 77E Ch. 2.1 - Prob. 78E Ch. 2.1 - Prob. 79E Ch. 2.1 - Prob. 80E Ch. 2.2 - Prob. 1QR Ch. 2.2 - Prob. 2QR Ch. 2.2 - Prob. 3QR Ch. 2.2 - Prob. 4QR Ch. 2.2 - Prob. 5QR Ch. 2.2 - Prob. 6QR Ch. 2.2 - Prob. 7QR Ch. 2.2 - Prob. 8QR Ch. 2.2 - Prob. 9QR Ch. 2.2 - Prob. 10QR Ch. 2.2 - Prob. 1E Ch. 2.2 - Prob. 2E Ch. 2.2 - Prob. 3E Ch. 2.2 - Prob. 4E Ch. 2.2 - Prob. 5E Ch. 2.2 - Prob. 6E Ch. 2.2 - Prob. 7E Ch. 2.2 - Prob. 8E Ch. 2.2 - Prob. 9E Ch. 2.2 - Prob. 10E Ch. 2.2 - Prob. 11E Ch. 2.2 - Prob. 12E Ch. 2.2 - Prob. 13E Ch. 2.2 - Prob. 14E Ch. 2.2 - Prob. 15E Ch. 2.2 - Prob. 16E Ch. 2.2 - Prob. 17E Ch. 2.2 - Prob. 18E Ch. 2.2 - Prob. 19E Ch. 2.2 - Prob. 20E Ch. 2.2 - Prob. 21E Ch. 2.2 - Prob. 22E Ch. 2.2 - Prob. 23E Ch. 2.2 - Prob. 24E Ch. 2.2 - Prob. 25E Ch. 2.2 - Prob. 26E Ch. 2.2 - Prob. 27E Ch. 2.2 - Prob. 28E Ch. 2.2 - Prob. 29E Ch. 2.2 - Prob. 30E Ch. 2.2 - Prob. 31E Ch. 2.2 - Prob. 32E Ch. 2.2 - Prob. 33E Ch. 2.2 - Prob. 34E Ch. 2.2 - Prob. 35E Ch. 2.2 - Prob. 36E Ch. 2.2 - Prob. 37E Ch. 2.2 - Prob. 38E Ch. 2.2 - Prob. 39E Ch. 2.2 - Prob. 40E Ch. 2.2 - Prob. 41E Ch. 2.2 - Prob. 42E Ch. 2.2 - Prob. 43E Ch. 2.2 - Prob. 44E Ch. 2.2 - Prob. 45E Ch. 2.2 - Prob. 46E Ch. 2.2 - Prob. 47E Ch. 2.2 - Prob. 48E Ch. 2.2 - Prob. 49E Ch. 2.2 - Prob. 50E Ch. 2.2 - Prob. 51E Ch. 2.2 - Prob. 52E Ch. 2.2 - Prob. 53E Ch. 2.2 - Prob. 54E Ch. 2.2 - Prob. 55E Ch. 2.2 - Prob. 56E Ch. 2.2 - Prob. 57E Ch. 2.2 - Prob. 58E Ch. 2.2 - Prob. 59E Ch. 2.2 - Prob. 60E Ch. 2.2 - Prob. 61E Ch. 2.2 - Prob. 62E Ch. 2.2 - Prob. 63E Ch. 2.2 - Prob. 64E Ch. 2.2 - Prob. 65E Ch. 2.2 - Prob. 66E Ch. 2.2 - Prob. 67E Ch. 2.2 - Prob. 68E Ch. 2.2 - Prob. 69E Ch. 2.2 - Prob. 70E Ch. 2.2 - Prob. 71E Ch. 2.2 - Prob. 1QQ Ch. 2.2 - Prob. 2QQ Ch. 2.2 - Prob. 3QQ Ch. 2.2 - Prob. 4QQ Ch. 2.3 - Prob. 1QR Ch. 2.3 - Prob. 2QR Ch. 2.3 - Prob. 3QR Ch. 2.3 - Prob. 4QR Ch. 2.3 - Prob. 5QR Ch. 2.3 - Prob. 6QR Ch. 2.3 - Prob. 7QR Ch. 2.3 - Prob. 8QR Ch. 2.3 - Prob. 9QR Ch. 2.3 - Prob. 10QR Ch. 2.3 - Prob. 1E Ch. 2.3 - Prob. 2E Ch. 2.3 - Prob. 3E Ch. 2.3 - Prob. 4E Ch. 2.3 - Prob. 5E Ch. 2.3 - Prob. 6E Ch. 2.3 - Prob. 7E Ch. 2.3 - Prob. 8E Ch. 2.3 - Prob. 9E Ch. 2.3 - Prob. 10E Ch. 2.3 - Prob. 11E Ch. 2.3 - Prob. 12E Ch. 2.3 - Prob. 13E Ch. 2.3 - Prob. 14E Ch. 2.3 - Prob. 15E Ch. 2.3 - Prob. 16E Ch. 2.3 - Prob. 17E Ch. 2.3 - Prob. 18E Ch. 2.3 - Prob. 19E Ch. 2.3 - Prob. 20E Ch. 2.3 - Prob. 21E Ch. 2.3 - Prob. 22E Ch. 2.3 - Prob. 23E Ch. 2.3 - Prob. 24E Ch. 2.3 - Prob. 25E Ch. 2.3 - Prob. 26E Ch. 2.3 - Prob. 27E Ch. 2.3 - Prob. 28E Ch. 2.3 - Prob. 29E Ch. 2.3 - Prob. 30E Ch. 2.3 - Prob. 31E Ch. 2.3 - Prob. 32E Ch. 2.3 - Prob. 33E Ch. 2.3 - Prob. 34E Ch. 2.3 - Prob. 35E Ch. 2.3 - Prob. 36E Ch. 2.3 - Prob. 37E Ch. 2.3 - Prob. 38E Ch. 2.3 - Prob. 39E Ch. 2.3 - Prob. 40E Ch. 2.3 - Prob. 41E Ch. 2.3 - Prob. 42E Ch. 2.3 - Prob. 43E Ch. 2.3 - Prob. 44E Ch. 2.3 - Prob. 45E Ch. 2.3 - Prob. 46E Ch. 2.3 - Prob. 47E Ch. 2.3 - Prob. 48E Ch. 2.3 - Prob. 49E Ch. 2.3 - Prob. 50E Ch. 2.3 - Prob. 51E Ch. 2.3 - Prob. 52E Ch. 2.3 - Prob. 53E Ch. 2.3 - Prob. 54E Ch. 2.3 - Prob. 55E Ch. 2.3 - Prob. 56E Ch. 2.3 - Prob. 57E Ch. 2.3 - Prob. 58E Ch. 2.3 - Prob. 59E Ch. 2.3 - Prob. 60E Ch. 2.3 - Prob. 61E Ch. 2.3 - Prob. 62E Ch. 2.3 - Prob. 63E Ch. 2.3 - Prob. 64E Ch. 2.4 - Prob. 1QR Ch. 2.4 - Prob. 2QR Ch. 2.4 - Prob. 3QR Ch. 2.4 - Prob. 4QR Ch. 2.4 - Prob. 5QR Ch. 2.4 - Prob. 6QR Ch. 2.4 - Prob. 7QR Ch. 2.4 - Prob. 8QR Ch. 2.4 - Prob. 9QR Ch. 2.4 - Prob. 10QR Ch. 2.4 - Prob. 1E Ch. 2.4 - Prob. 2E Ch. 2.4 - Prob. 3E Ch. 2.4 - Prob. 4E Ch. 2.4 - Prob. 5E Ch. 2.4 - Prob. 6E Ch. 2.4 - Prob. 7E Ch. 2.4 - Prob. 8E Ch. 2.4 - Prob. 9E Ch. 2.4 - Prob. 10E Ch. 2.4 - Prob. 11E Ch. 2.4 - Prob. 12E Ch. 2.4 - Prob. 13E Ch. 2.4 - Prob. 14E Ch. 2.4 - Prob. 15E Ch. 2.4 - Prob. 16E Ch. 2.4 - Prob. 17E Ch. 2.4 - Prob. 18E Ch. 2.4 - Prob. 19E Ch. 2.4 - Prob. 20E Ch. 2.4 - Prob. 21E Ch. 2.4 - Prob. 22E Ch. 2.4 - Prob. 23E Ch. 2.4 - Prob. 24E Ch. 2.4 - Prob. 25E Ch. 2.4 - Prob. 26E Ch. 2.4 - Prob. 27E Ch. 2.4 - Prob. 28E Ch. 2.4 - Prob. 29E Ch. 2.4 - Prob. 30E Ch. 2.4 - Prob. 31E Ch. 2.4 - Prob. 32E Ch. 2.4 - Prob. 33E Ch. 2.4 - Prob. 34E Ch. 2.4 - Prob. 35E Ch. 2.4 - Prob. 36E Ch. 2.4 - Prob. 37E Ch. 2.4 - Prob. 38E Ch. 2.4 - Prob. 39E Ch. 2.4 - Prob. 40E Ch. 2.4 - Prob. 41E Ch. 2.4 - Prob. 42E Ch. 2.4 - Prob. 43E Ch. 2.4 - Prob. 44E Ch. 2.4 - Prob. 45E Ch. 2.4 - Prob. 46E Ch. 2.4 - Prob. 47E Ch. 2.4 - Prob. 48E Ch. 2.4 - Prob. 49E Ch. 2.4 - Prob. 50E Ch. 2.4 - Prob. 51E Ch. 2.4 - Prob. 52E Ch. 2.4 - Prob. 53E Ch. 2.4 - Prob. 54E Ch. 2.4 - Prob. 55E Ch. 2.4 - Prob. 1QQ Ch. 2.4 - Prob. 2QQ Ch. 2.4 - Prob. 3QQ Ch. 2.4 - Prob. 4QQ Ch. 2 - Prob. 1RE Ch. 2 - Prob. 2RE Ch. 2 - Prob. 3RE Ch. 2 - Prob. 4RE Ch. 2 - Prob. 5RE Ch. 2 - Prob. 6RE Ch. 2 - Prob. 7RE Ch. 2 - Prob. 8RE Ch. 2 - Prob. 9RE Ch. 2 - Prob. 10RE Ch. 2 - Prob. 11RE Ch. 2 - Prob. 12RE Ch. 2 - Prob. 13RE Ch. 2 - Prob. 14RE Ch. 2 - Prob. 15RE Ch. 2 - Prob. 16RE Ch. 2 - Prob. 17RE Ch. 2 - Prob. 18RE Ch. 2 - Prob. 19RE Ch. 2 - Prob. 20RE Ch. 2 - Prob. 21RE Ch. 2 - Prob. 22RE Ch. 2 - Prob. 23RE Ch. 2 - Prob. 24RE Ch. 2 - Prob. 25RE Ch. 2 - Prob. 26RE Ch. 2 - Prob. 27RE Ch. 2 - Prob. 28RE Ch. 2 - Prob. 29RE Ch. 2 - Prob. 30RE Ch. 2 - Prob. 31RE Ch. 2 - Prob. 32RE Ch. 2 - Prob. 33RE Ch. 2 - Prob. 34RE Ch. 2 - Prob. 35RE Ch. 2 - Prob. 36RE Ch. 2 - Prob. 37RE Ch. 2 - Prob. 38RE Ch. 2 - Prob. 39RE Ch. 2 - Prob. 40RE Ch. 2 - Prob. 41RE Ch. 2 - Prob. 42RE Ch. 2 - Prob. 43RE Ch. 2 - Prob. 44RE Ch. 2 - Prob. 45RE Ch. 2 - Prob. 46RE Ch. 2 - Prob. 47RE Ch. 2 - Prob. 48RE Ch. 2 - Prob. 49RE Ch. 2 - Prob. 50RE Ch. 2 - Prob. 51RE Ch. 2 - Prob. 52RE Ch. 2 - Prob. 53RE Ch. 2 - Prob. 54RE Ch. 2 - Prob. 55RE

Additional Math Textbook Solutions

Find more solutions based on key concepts

The following set of data is from sample of n=5: a. Compute the mean, median, and mode. b. Compute the range, v...

Basic Business Statistics, Student Value Edition

12. Designing Manholes According to the website www.torchmate.com, “manhole covers must be a minimum of 22 in. ...

Elementary Statistics (13th Edition)

Derivatives of Logarithms In Exercises 11-40, find the derivative of y with respect to x, t, or θ, as appropria...

University Calculus: Early Transcendentals (4th Edition)

In Problems 25-32, the graph of a function is given. Use the graph to find: a. The intercepts, if any b. The do...

Precalculus

Continuity at a point Determine whether the following functions are continuous at a. Use the continuity checkli...

Calculus: Early Transcendentals (2nd Edition)

A retail establishment accepts either the American Express or the VISA credit card. A total of 24 percent of it...

A First Course in Probability (10th Edition)

Knowledge Booster

$Calculus$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.