Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine Concept Introduction : A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows: a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide b) Alkyl bromide in azide synthesis produces primary amine c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton e) Alkene on ozonolysis produces carbonyl compounds f) Alkyl halides with strong base gives alkene g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines . Using these concepts, we can transfer 1-hexanol into the given compounds.

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Answer 1

Question

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

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There is an instrument in Johnson 334 that measures total-reflectance x-ray fluorescence (TXRF) to do elemental analysis (i.e., determine what elements are present in a sample). A researcher is preparing a to measure calcium content in a series of well water samples by TXRF with an internal standard of vanadium (atomic symbol: V). She has prepared a series of standard solutions to ensure a linear instrument response over the expected Ca concentration range of 40-80 ppm. The concentrations of Ca and V (ppm) and the instrument response (peak area, arbitrary units) are shown below. Also included is a sample spectrum. Equation 1 describes the response factor, K, relating the analyte signal (SA) and the standard signal (SIS) to their respective concentrations (CA and CIS). Ca, ppm V, ppm SCa, arb. units SV, arb. units 20.0 10.0 14375.11 14261.02 40.0 10.0 36182.15 17997.10 60.0 10.0 39275.74 12988.01 80.0 10.0 57530.75 14268.54 100.0…

A mixture of 0.568 M H₂O, 0.438 M Cl₂O, and 0.710 M HClO are enclosed in a vessel at 25 °C. H₂O(g) + C₁₂O(g) = 2 HOCl(g) K = 0.0900 at 25°C с Calculate the equilibrium concentrations of each gas at 25 °C. [H₂O]= [C₁₂O]= [HOCI]= M Σ M

What units (if any) does the response factor (K) have? Does the response factor (K) depend upon how the concentration is expressed (e.g. molarity, ppm, ppb, etc.)?

Answer 2

Question

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

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Answer 3

Question

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 6

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 7

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 8

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 9

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 10

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 11

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 22.2 - Prob. 1LTS Ch. 22.2 - Prob. 1PTS Ch. 22.2 - Prob. 2PTS Ch. 22.2 - Prob. 3ATS Ch. 22.3 - Prob. 4CC Ch. 22.3 - Prob. 5CC Ch. 22.3 - Prob. 6CC Ch. 22.3 - Prob. 7CC Ch. 22.3 - Prob. 8CC Ch. 22.3 - Prob. 9CC

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Chapter 22 Solutions