Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine Concept Introduction : A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows: a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide b) Alkyl bromide in azide synthesis produces primary amine c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton e) Alkene on ozonolysis produces carbonyl compounds f) Alkyl halides with strong base gives alkene g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines . Using these concepts, we can transfer 1-hexanol into the given compounds.

Question

Want to see the full answer?

Answer 1

Question

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Please answer the questions and provide detailed explanation. Please also include the Hydrogens that are on the molecule to show how many signals there are.

Capp aktiv.com Part of Speech Table for Assi x Aktiv Learning App K Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. Problem 232 of 10 10: Mg Select to Add Arrows Br O H :0 CI:O H Mg THE + dy Undo Reset Done Br

Please answer the question and provide a detailed drawing of the structure. If there will not be a new C – C bond, then the box under the drawing area will be checked. Will the following reaction make a molecule with a new C – C bond as its major product: Draw the major organic product or products, if the reaction will work. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry.

Answer 2

Question

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 6

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 7

Chapter 22, Problem 45PP

(a)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 8

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 9

(b)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 10

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 11

(c)

Interpretation Introduction

Interpretation: Using a different type of reactions, 1-hexanol is to be prepared from hexyl amine, heptyl amine and pentyl amine

Concept Introduction: A number of transformations are used to prepare 1-hexanol. Some of them are listed as follows:

a) Alcohol on treatment with phosphorous tribromide gives alkyl bromide

b) Alkyl bromide in azide synthesis produces primary amine

c) Alkyl halide on treatment with sodium cyanide gives alkyl cyanide

d) Cyanide on reduction gives alkyl amine with an increment of one carbon atom skeleton

e) Alkene on ozonolysis produces carbonyl compounds

f) Alkyl halides with strong base gives alkene

g) Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Using these concepts, we can transfer 1-hexanol into the given compounds.

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 15

Ch. 22.2 - Prob. 1LTS Ch. 22.2 - Prob. 1PTS Ch. 22.2 - Prob. 2PTS Ch. 22.2 - Prob. 3ATS Ch. 22.3 - Prob. 4CC Ch. 22.3 - Prob. 5CC Ch. 22.3 - Prob. 6CC Ch. 22.3 - Prob. 7CC Ch. 22.3 - Prob. 8CC Ch. 22.3 - Prob. 9CC

Want to see the full answer?

Chapter 22 Solutions