‘Crystal field splitting energy’ should be identified. Concept introduction: Weak field ligand is present in the given complex which results in unpaired electron because very less energy is absorbed by these complex and the CFSE can be calculated with the wavelength as follows; E = hc λ where, h is planks constant c is speed of light λ is wavelength. Given: Wavelength of 295 nm for [Rh(NH 3 ) 6 ] 3+ ion.

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Answer 1

Question

Chapter 22, Problem 44E

Interpretation Introduction

Interpretation:

‘Crystal field splitting energy’ should be identified.

Concept introduction:

Weak field ligand is present in the given complex which results in unpaired electron because very less energy is absorbed by these complex and the CFSE can be calculated with the wavelength as follows;

$E = \frac{hc}{λ}$

where,

h is planks constant

c is speed of light

λ is wavelength.

Given:

Wavelength of 295 nm for [Rh(NH₃)₆]³⁺ ion.

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Answer 2

Question

Chapter 22, Problem 44E

Interpretation Introduction

Interpretation:

‘Crystal field splitting energy’ should be identified.

Concept introduction:

Weak field ligand is present in the given complex which results in unpaired electron because very less energy is absorbed by these complex and the CFSE can be calculated with the wavelength as follows;

$E = \frac{hc}{λ}$

where,

h is planks constant

c is speed of light

λ is wavelength.

Given:

Wavelength of 295 nm for [Rh(NH₃)₆]³⁺ ion.

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 3

Question

Chapter 22, Problem 44E

Interpretation Introduction

Interpretation:

‘Crystal field splitting energy’ should be identified.

Concept introduction:

Weak field ligand is present in the given complex which results in unpaired electron because very less energy is absorbed by these complex and the CFSE can be calculated with the wavelength as follows;

$E = \frac{hc}{λ}$

where,

h is planks constant

c is speed of light

λ is wavelength.

Given:

Wavelength of 295 nm for [Rh(NH₃)₆]³⁺ ion.

Expert Solution & Answer

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Answer 4

Question

Chapter 22, Problem 44E

Interpretation Introduction

Interpretation:

‘Crystal field splitting energy’ should be identified.

Concept introduction:

Weak field ligand is present in the given complex which results in unpaired electron because very less energy is absorbed by these complex and the CFSE can be calculated with the wavelength as follows;

$E = \frac{hc}{λ}$

where,

h is planks constant

c is speed of light

λ is wavelength.

Given:

Wavelength of 295 nm for [Rh(NH₃)₆]³⁺ ion.

Expert Solution & Answer

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Answer 5

Chapter 22, Problem 44E

Interpretation Introduction

Interpretation:

‘Crystal field splitting energy’ should be identified.

Concept introduction:

Weak field ligand is present in the given complex which results in unpaired electron because very less energy is absorbed by these complex and the CFSE can be calculated with the wavelength as follows;

$E = \frac{hc}{λ}$

where,

h is planks constant

c is speed of light

λ is wavelength.

Given:

Wavelength of 295 nm for [Rh(NH₃)₆]³⁺ ion.

Answer 6

Chapter 22, Problem 44E

Interpretation Introduction

Interpretation:

‘Crystal field splitting energy’ should be identified.

Concept introduction:

Weak field ligand is present in the given complex which results in unpaired electron because very less energy is absorbed by these complex and the CFSE can be calculated with the wavelength as follows;

$E = \frac{hc}{λ}$

where,

h is planks constant

c is speed of light

λ is wavelength.

Given:

Wavelength of 295 nm for [Rh(NH₃)₆]³⁺ ion.

Answer 7

Chapter 22, Problem 44E

Interpretation Introduction

Interpretation:

‘Crystal field splitting energy’ should be identified.

Concept introduction:

Weak field ligand is present in the given complex which results in unpaired electron because very less energy is absorbed by these complex and the CFSE can be calculated with the wavelength as follows;

$E = \frac{hc}{λ}$

where,

h is planks constant

c is speed of light

λ is wavelength.

Given:

Wavelength of 295 nm for [Rh(NH₃)₆]³⁺ ion.

Answer 8

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Answer 9

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Answer 10

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Answer 11

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Solution Summary: The author explains that the crystal field splitting energy (CFSE) is 40.610 4 kJ/mol.

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