(a) Interpretation: The product that is formed from a Michael reaction of the given starting materials by using − OEt , EtOH is to be drawn. Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β − carbon of the other α , β − unsaturated carbonyl compound is known as Michael reaction. The α , β − unsaturated carbonyl compounds are also called as Michael acceptors.

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Answer 1

Question

Chapter 22, Problem 43P

Interpretation Introduction

(a)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

Interpretation Introduction

(b)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

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14 Question (1 point) Disiamylborane adds to a triple bond to give an alkenylborane. Upon oxidation with OH, H2O2, the alkenylborane will form an enol that tautomerizes to an aldehyde. In the first box below, draw the mechanism arrows for the reaction of disiamylborane with the alkyne, and in the last box draw the structure of the aldehyde. 4th attempt Feedback i > 3rd attempt OH, H2O2 i See Periodic Table See Hint

answer with mechanisms and steps. handwritten please!

Hello I need some help with Smartwork. For drawing structure B, I know the correct answer is CH₃B₂, but when I try to type it in, it keeps giving me CH₄BH₃ instead. Do you know how I should write it properly? Should I use a bond or something else?

Answer 2

Question

Chapter 22, Problem 43P

Interpretation Introduction

(a)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

Interpretation Introduction

(b)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

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Answer 3

Question

Chapter 22, Problem 43P

Interpretation Introduction

(a)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

Interpretation Introduction

(b)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

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Answer 4

Question

Chapter 22, Problem 43P

Interpretation Introduction

(a)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

Interpretation Introduction

(b)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

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Answer 5

Chapter 22, Problem 43P

Interpretation Introduction

(a)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

Interpretation Introduction

(b)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

Answer 6

Chapter 22, Problem 43P

Interpretation Introduction

(a)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

Answer 7

Chapter 22, Problem 43P

Interpretation Introduction

(a)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

Answer 8

Interpretation Introduction

(b)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

Answer 9

Interpretation Introduction

(b)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

Answer 10

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Answer 13

Ch. 22.1 - Prob. 1P Ch. 22.1 - Prob. 2P Ch. 22.1 - Problem 24.3 What unsaturated carbonyl compound is...Ch. 22.1 - Prob. 4P Ch. 22.1 - Prob. 5P Ch. 22.2 - Prob. 6P Ch. 22.2 - Problem 24.7 Draw the products formed in each...Ch. 22.4 - Prob. 15P Ch. 22.4 - Prob. 16P Ch. 22.5 - Problem 24.16 What ester is formed when each...

Solution Summary: The author explains that the product that is formed from a Michael reaction of the given starting materials by using -OEt is shown.

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Chapter 22 Solutions