
Concept explainers
(a)
Interpretation:
The type of isomerism that could be exhibited by the given formulae and an example that illustrates the specific type of isomerism has to be stated.
Concept introduction:
Organic compounds which have similar chemical formula but different structures, i.e., the atoms are in a different spatial arrangement, they are known as structural isomers. Cis and Trans isomers are also structural or geometrical isomers.
(a)

Answer to Problem 2Q
Explanation of Solution
The type of isomerism that could be exhibited by
The structural isomer of
The given formula,
The root word hexene indicates that six carbon atoms are present in the parent chain. Double bond is present between first and second carbon.
The structure of 1-hexene is shown
The structural isomer of
The given formula,
The root word hexene indicates that six carbon atoms are present in the parent chain. The number
The structure of 2-hexene is shown
The structural isomer of
The given formula,
The root word hexene indicates that six carbon atoms are present in the parent chain. The number
The structure of 3-hexene is shown
The structural isomer of
The given formula,
The root word pentene indicates that five carbon atoms are present in the parent chain. The number
The structure of
The structural isomer of
The given formula,
The root word butene indicates that six carbon atoms are present in the parent chain. The double bond is present between second and third carbon. Two methyl groups are attached at second and third carbon.
The structure of
The geometric isomer of
The structure of cis-2-hexene is,
The structure of trans-2-hexene is,
In the cis isomer, the two hydrogen of the double bonded carbons are adjacent to each other while in trans isomer, they are opposite to each other.
The geometric isomer of
The structure of cis-3-hexene is,
The structure of trans-3-hexene is,
In the cis isomer, the two hydrogen of the double bonded carbons are adjacent to each other while in trans isomer, they are opposite to each other.
(b)
Interpretation:
The type of isomerism that could be exhibited by the given formulae and an example that illustrates the specific type of isomerism has to be stated.
Concept introduction:
Organic compounds which have similar chemical formula but different structures, i.e., the atoms are in a different spatial arrangement, they are known as structural isomers. Cis and Trans isomers are also structural or geometrical isomers.
(b)

Answer to Problem 2Q
Explanation of Solution
The type of isomerism that could be exhibited by
The structural isomer of
The root word pentane indicates that five carbon atoms are present in the parent chain. Hydroxyl group is attached to first carbon.
The structure of pentan-1-ol is shown,
The structural isomer of
The root word butane indicates that four carbon atoms are present in the parent chain.
The structure of
The structural isomer of
The root word propane indicates that three carbon atoms are present in the parent chain.
The structure of 2-ethoxypropane is shown
The structural isomer of
The root word butane indicates that four carbon atoms are present in the parent chain.
The structure of 2-methoxybutane is shown
The structural isomer of
The root word pentane indicates that five carbon atoms are present in the parent chain. Hydroxyl group is attached to third carbon.
The structure of pentan-
The structural isomer of
The root word pentane indicates that five carbon atoms are present in the parent chain. Hydroxyl group is attached to second carbon.
The structure of pentan-
(c)
Interpretation:
The type of isomerism that could be exhibited by the given formulae and an example that illustrates the specific type of isomerism has to be stated.
Concept introduction:
Organic compounds which have similar chemical formula but different structures, i.e., the atoms are in a different spatial arrangement, they are known as structural isomers. Cis and Trans isomers are also structural or geometrical isomers.
(c)

Answer to Problem 2Q
Explanation of Solution
The type of isomerism that could be exhibited by
The structural isomer of
In
The structural isomer of
In
The structural isomer of
In
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Chapter 22 Solutions
Chemistry (AP Edition)
- A concentration cell consists of two Sn/Sn2+ half-cells. The cell has a potential of 0.10 V at 25 °C. What is the ratio of [Sn2+] (i.e., [Sn2+left-half] / [Sn2+right-half])?arrow_forwardElectrochemical cell potentials can be used to determine equilibrium constants that would be otherwise difficult to determine because concentrations are small. What is Κ for the following balanced reaction if E˚ = +0.0218 V? 3 Zn(s) + 2 Cr3+(aq) → 3 Zn2+(aq) + Cr(s) E˚ = +0.0218 Varrow_forwardConsider the following half-reactions: Hg2+(aq) + 2e– → Hg(l) E°red = +0.854 V Cu2+(aq) + 2e– → Cu(s)E°red = +0.337 V Ni2+(aq) + 2e– → Ni(s) E°red = -0.250 V Fe2+(aq) + 2e– → Fe(s) E°red = -0.440 V Zn2+(aq) + 2e– → Zn(s) E°red = -0.763 V What is the best oxidizing agent shown above (i.e., the substance that is most likely to be reduced)?arrow_forward
- Calculate the equilibrium constant, K, for MnO2(s) + 4 H+(aq) + Zn(s) → Mn2+(aq) + 2 H2O(l) + Zn2+(aq)arrow_forwardIn the drawing area below, draw the condensed structures of formic acid and ethyl formate. You can draw the two molecules in any arrangement you like, so long as they don't touch. Click anywhere to draw the first atom of your structure. A C narrow_forwardWrite the complete common (not IUPAC) name of each molecule below. Note: if a molecule is one of a pair of enantiomers, be sure you start its name with D- or L- so we know which enantiomer it is. molecule Ο C=O common name (not the IUPAC name) H ☐ H3N CH₂OH 0- C=O H NH3 CH₂SH H3N ☐ ☐ X Garrow_forward
- (Part A) Provide structures of the FGI products and missing reagents (dashed box) 1 eq Na* H* H -H B1 B4 R1 H2 (gas) Lindlar's catalyst A1 Br2 MeOH H2 (gas) Lindlar's catalyst MeO. OMe C6H1402 B2 B3 A1 Product carbons' origins Draw a box around product C's that came from A1. Draw a dashed box around product C's that came from B1.arrow_forwardClassify each of the amino acids below. Note for advanced students: none of these amino acids are found in normal proteins. X CH2 H3N-CH-COOH3N-CH-COO- H3N-CH-COO CH2 CH3-C-CH3 CH2 NH3 N NH (Choose one) ▼ (Choose one) S CH2 OH (Choose one) ▼ + H3N-CH-COO¯ CH2 H3N CH COO H3N-CH-COO CH2 오오 CH CH3 CH2 + O C CH3 O= O_ (Choose one) (Choose one) ▼ (Choose one) Garrow_forwardAnother standard reference electrode is the standard calomel electrode: Hg2Cl2(s) (calomel) + 2e2 Hg() +2 Cl(aq) This electrode is usually constructed with saturated KCI to keep the Cl- concentration constant (similar to what we discussed with the Ag-AgCl electrode). Under these conditions the potential of this half-cell is 0.241 V. A measurement was taken by dipping a Cu wire and a saturated calomel electrode into a CuSO4 solution: saturated calomel electrode potentiometer copper wire CuSO4 a) Write the half reaction for the Cu electrode. b) Write the Nernst equation for the Cu electrode, which will include [Cu2+] c) If the voltage on the potentiometer reads 0.068 V, solve for [Cu²+].arrow_forward
- 2. (Part B). Identify a sequence of FGI that prepares the Synthesis Target 2,4-dimethoxy- pentane. All carbons in the Synthesis Target must start as carbons in either ethyne, propyne or methanol. Hint: use your analysis of Product carbons' origins (Part A) to identify possible structure(s) of a precursor that can be converted to the Synthesis Target using one FGI. All carbons in the Synthesis Target must start as carbons in one of the three compounds below. H = -H H = -Me ethyne propyne Synthesis Target 2,4-dimethoxypentane MeOH methanol OMe OMe MeO. OMe C₂H₁₂O₂ Product carbons' origins Draw a box around product C's that came from A1. Draw a dashed box around product C's that came from B1.arrow_forwardDraw the skeletal ("line") structure of the smallest organic molecule that produces potassium 3-hydroxypropanoate when reacted with KOH. Click and drag to start drawing a structure. Sarrow_forwardDraw the skeleatal strucarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning


