Introduction to Algorithms
Introduction to Algorithms
3rd Edition
ISBN: 9780262033848
Author: Thomas H. Cormen, Ronald L. Rivest, Charles E. Leiserson, Clifford Stein
Publisher: MIT Press
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Chapter 22, Problem 2P

(a)

Program Plan Intro

To show that the graph Gp is an articulation point if it contains at least two children.

(b)

Program Plan Intro

To show that vertex v belongs to V is an articulation point of graph that contains child s having no back edge.

(c)

Program Plan Intro

To evaluate v .low for every vertices of the graph G in O ( E ) time.

(d)

Program Plan Intro

To compute all possible articulation points in O ( E ) time.

(e)

Program Plan Intro

To show that an edge of the graph G is a bridge if it does not contains any simple cycle.

(f)

Program Plan Intro

To configure all possible bridges of the graph G in O ( E ) time.

(g)

Program Plan Intro

To show that the graph Gbi -connected components can be partition the non-bridge edges of the graph G .

(h)

Program Plan Intro

To show that in the graph G with the edge eand e’ such that e .bcc = e’ .bcc, only possible if an edge e and e’ contains similar bi-connected component.

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Specifications: Part-1Part-1: DescriptionIn this part of the lab you will build a single operation ALU. This ALU will implement a bitwise left rotation. Forthis lab assignment you are not allowed to use Digital's Arithmetic components.IF YOU ARE FOUND USING THEM, YOU WILL RECEIVE A ZERO FOR LAB2!The ALU you will be implementing consists of two 4-bit inputs (named inA and inB) and one 4-bit output (named out). Your ALU must rotate the bits in inA by the amount given by inB (i.e. 0-15).Part-1: User InterfaceYou are provided an interface file lab2_part1.dig; start Part-1 from this file.NOTE: You are not permitted to edit the content inside the dotted lines rectangle.Part-1: ExampleIn the figure above, the input values that we have selected to test are inA = {inA_3, inA_2, inA_1, inA_0} = {0, 1, 0,0} and inB = {inB_3, inB_2, inB_1, inB_0} = {0, 0, 1, 0}. Therefore, we must rotate the bus 0100 bitwise left by00102, or 2 in base 10, to get {0, 0, 0, 1}. Please note that a rotation left is…
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