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College Physics
- A light ray travels from vacuum into a slab of material with index of refraction n1 at incident angle θ with respect to the surface. It subsequently passes into a second slab of material with index of refraction n2 before passing back into vacuum again. The surfaces of the different materials are all parallel to one another. As the light exits the second slab, what can be said of the final angle ϕ that the outgoing light makes with the normal? (a) ϕ > θ (b) ϕ < θ (c) ϕ = θ (d) The angle depends on the magnitudes of n1 and n2. (e) The angle depends on the wavelength of the light.arrow_forwardLight traveling in a medium of index of refraction n1 is incident on another medium having an index of refraction n2. Under which of the following conditions can total internal reflection occur at the interface of the two media? (a) The indices of refraction have the relation n2 n1. (b) The indices of refraction have the relation n1 n2. (c) Light travels slower in the second medium than in the first. (d) The angle of incidence is less than the critical angle. (e) The angle of incidence must equal the angle of refraction.arrow_forwardConsider a light ray that enters a pane of glass with air on one side and water on the other side as shown in Figure P38.21. The light ray experiences refraction at the first interface when it enters the glass from the water and again at the second interface when it exits the glass into the air. Assume the index of refraction of the glass is 1.54. For a ray of light, find the angle of incidence 1 in the water such that the ray experiences total internal reflection when it strikes the glassair interface on the other side. FIGURE P38.21arrow_forward
- A Lucite slab (n = 1.485) 5.00 cm in thickness forms the bottom of an ornamental fish pond that is 40.0 cm deep. If the pond is completely filled with water, what is the apparent thickness of the Lucite plate when viewed from directly above the pond?arrow_forwardA person looking into an empty container is able to see the far edge of the containers bottom, as shown in Figure P22.23a. The height of the container is h, and its width is d. When the container is completely filled with a fluid of index of refraction n and viewed from the same angle, the person can see the center of a coin at the middle of the containers bottom, as shown in Figure P22.23b. (a) Show that the ratio h/d is given by hd=n214n2 (b) Assuming the container has a width of 8.00 cm and is filled with water, use the expression above to find the height of the container.arrow_forwardPierre de Fermat (16011665) showed that whenever light travels from one point to another, its actual path is the path that requires the smallest time interval. This statement is known as Fermats principle. The simplest example is for light propagating in a homogeneous medium. It moves in a straight line because a straight line is the shortest distance between two points. Derive Snells law of refraction from Fermats principle. Proceed as follows. In Figure P34.54, a light ray travels from point P in medium 1 to point Q in medium 2. The two points are, respectively, at perpendicular distances a and b from the interface. The displacement from P to Q has the component d parallel to the interface, and we let x represent the coordinate of the point where the ray enters the second medium. Let t = 0 be the instant the light starts from P. (a) Show that the time at which the light arrives at Q is t=r1v1+r2v2=n1a2+x2c+n2b2+(dx)2c (b) To obtain the value of x for which t has its minimum value, differentiate t with respect to x and set the derivative equal to zero. Show that the result implies n1xa2+x2=n2(dx)b2+(dx)2 (c) Show that this expression in turn gives Snells law. n1sin1=n2sin2 Figure P34.54 Problems 54 and 55.arrow_forward
- Unpolarized light in vacuum is incident onto a sheet of glass with index of refraction n. The reflected and refracted rays are perpendicular to each other. Find the angle of incidence. This angle is called Brewsters angle or the polarizing angle. In this situation, the reflected light is linearly polarized, with its electric field restricted to be perpendicular to the plane containing the rays and the normal.arrow_forwardProblem 9: A ray of light is incident on an air/water interface. The ray makes an angle of θ1 = 29 degrees with respect to the normal of the surface. The index of the air is n1 = 1 while water is n2 = 1.33. Part (a) Choose an expression for the angle (relative to the normal to the surface) for the ray in the water, θ2. Part (b) Numerically, what is the angle in degrees?arrow_forwardPart (b) Numerically, what is the angle in degrees? θ2= Part (c) Write an expression for the reflection angle ψ, with respect to the surface. ψ = Part (d) Numerically, what is this angle in degrees? ψ =arrow_forward
- A beam of light is incident from the air on a transparent substance at an angle of 56 with respect to the normal, part of the beam is reflected and the other is refracted. It is observed that the reflected and refracted beams are mutually perpendicular. What is the refractive incidence of the transparent substance? What can you say about the reflected beam? Since you know both indices of refraction, suppose a light beam is incident from the medium with the higher index of refraction to the medium with the lower index of refraction. What is the critical angle to achieve total internal reflection?arrow_forwardA beam of light, traveling in air, strikes a plate of transparent material at an angle of incidence of 62.0°. It is observed that the reflected and refracted beams form an angle of 90.0°. What is the index of refraction of this material? O 1.88 O 1.40 O 1.43 O 1.44arrow_forwardA beam of light traveling in air strikes a slab of transparent material. The incident beam makes an angle of 45° with the normal, and the refracted beam make an angle of 22° with the normal. What is the speed of light in the transparent material? (c = 3.0 × 10° m/s) %3Darrow_forward
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