Chemistry, Books a la Carte Edition and Modified Mastering Chemistry with Pearson eText & ValuePack Access Card (7th Edition)
7th Edition
ISBN: 9780134172514
Author: John E. McMurry
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 22, Problem 22.90SP
Interpretation Introduction
Interpretation:
“What is the most common oxidation state for each of the group 3A element” should be explained
Concept introduction:
- Group 3A or 13: The elements of this group 13 are also known as boron family. The elements of this group are following:
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Complete the mechanism for the E1 reaction below by following the directions written above each of the five boxes. Be sure to include lone pair
electrons and nonzero formal charges.
2nd attempt
1 Provide the missing curved arrow notation.
E+
RUDDA
1st attempt
Feedback
See Periodic Table
See Hint
Iir
See Periodic Table See Hint
Heating an alcohol in the presence of sulfuric or phosphoric acid will cause a dehydration to occur: the removal of the elements of water from a
molecule, forming an alkene. The reaction usually follows an E1 mechanism. The SN1 pathway is suppressed by using a strong acid whose conjugate
base is a poor nucleophile. Further, heating the reaction mixture causes a greater increase in the rate of E1 compared to the rate of Sy1.
3rd attempt
h
Draw curved arrow(s) to show how the alcohol reacts with phosphoric acid.
TH
© 1 0 0 +1% #
2nd attempt
Feedback
H
Ju See Periodic Table See Hint
H
Jud See Periodic Table See Hint
Part 2 (0.5 point)
0-
Draw the major organic product with the correct geometry.
10
1:
70000 х
く
1st attempt
Part 1 (0.5 point) Feedback
Please draw all four bonds at chiral centers.
P
See Periodic Table See Hint
Chapter 22 Solutions
Chemistry, Books a la Carte Edition and Modified Mastering Chemistry with Pearson eText & ValuePack Access Card (7th Edition)
Ch. 22 - Prob. 22.1PCh. 22 - Prob. 22.2ACh. 22 - Prob. 22.3PCh. 22 - Prob. 22.4CACh. 22 - Prob. 22.5PCh. 22 - Prob. 22.6PCh. 22 - Prob. 22.7ACh. 22 - Prob. 22.8CPCh. 22 - Prob. 22.9ACh. 22 - Prob. 22.10P
Ch. 22 - Prob. 22.11PCh. 22 - Prob. 22.12PCh. 22 - Prob. 22.13PCh. 22 - Prob. 22.14PCh. 22 - Prob. 22.15PCh. 22 - Prob. 22.16PCh. 22 - Prob. 22.17CPCh. 22 - Prob. 22.18CACh. 22 - Prob. 22.19PCh. 22 - Prob. 22.20PCh. 22 - Prob. 22.21PCh. 22 - Conceptual PRACTICE 22.22 Look at the location of...Ch. 22 - Prob. 22.23ACh. 22 - Prob. 22.24CPCh. 22 - Prob. 22.25PCh. 22 - Prob. 22.26PCh. 22 - Prob. 22.27PCh. 22 - Prob. 22.28PCh. 22 - Prob. 22.29PCh. 22 - Prob. 22.30PCh. 22 - Prob. 22.31PCh. 22 - Prob. 22.32PCh. 22 - Prob. 22.33CPCh. 22 - Prob. 22.34CPCh. 22 - Prob. 22.35CPCh. 22 - Prob. 22.36CPCh. 22 - Prob. 22.37CPCh. 22 - Prob. 22.38CPCh. 22 - Prob. 22.39CPCh. 22 - Prob. 22.40CPCh. 22 - Prob. 22.41CPCh. 22 - Prob. 22.42CPCh. 22 - Prob. 22.43CPCh. 22 - Prob. 22.44CPCh. 22 - Prob. 22.45CPCh. 22 - Prob. 22.46CPCh. 22 - Prob. 22.47CPCh. 22 - Prob. 22.48SPCh. 22 - Prob. 22.49SPCh. 22 - Prob. 22.50SPCh. 22 - Prob. 22.51SPCh. 22 - Prob. 22.52SPCh. 22 - Prob. 22.53SPCh. 22 - Prob. 22.54SPCh. 22 - Prob. 22.55SPCh. 22 - Prob. 22.56SPCh. 22 - Prob. 22.57SPCh. 22 - Prob. 22.58SPCh. 22 - Prob. 22.59SPCh. 22 - Prob. 22.60SPCh. 22 - Prob. 22.61SPCh. 22 - Prob. 22.62SPCh. 22 - Prob. 22.63SPCh. 22 - Prob. 22.64SPCh. 22 - Prob. 22.65SPCh. 22 - Prob. 22.66SPCh. 22 - Prob. 22.67SPCh. 22 - Prob. 22.68SPCh. 22 - Prob. 22.69SPCh. 22 - Prob. 22.70SPCh. 22 - Prob. 22.71SPCh. 22 - Prob. 22.72SPCh. 22 - Prob. 22.73SPCh. 22 - Prob. 22.74SPCh. 22 - Prob. 22.75SPCh. 22 - Prob. 22.76SPCh. 22 - Prob. 22.77SPCh. 22 - Prob. 22.78SPCh. 22 - Prob. 22.79SPCh. 22 - Prob. 22.80SPCh. 22 - Prob. 22.81SPCh. 22 - Prob. 22.82SPCh. 22 - Prob. 22.83SPCh. 22 - Prob. 22.84SPCh. 22 - Prob. 22.85SPCh. 22 - Magnesium metal is produced by electrolysis of...Ch. 22 - Prob. 22.87SPCh. 22 - Prob. 22.88SPCh. 22 - Prob. 22.89SPCh. 22 - Prob. 22.90SPCh. 22 - Prob. 22.91SPCh. 22 - Prob. 22.92SPCh. 22 - Prob. 22.93SPCh. 22 - Prob. 22.94SPCh. 22 - Prob. 22.95SPCh. 22 - Prob. 22.96SPCh. 22 - Prob. 22.97SPCh. 22 - Prob. 22.98SPCh. 22 - Prob. 22.99SPCh. 22 - Prob. 22.100SPCh. 22 - Prob. 22.101SPCh. 22 - Prob. 22.102SPCh. 22 - Prob. 22.103SPCh. 22 - Prob. 22.104SPCh. 22 - Prob. 22.105SPCh. 22 - Prob. 22.106SPCh. 22 - Prob. 22.107SPCh. 22 - Prob. 22.108SPCh. 22 - Prob. 22.109SPCh. 22 - Prob. 22.110SPCh. 22 - Prob. 22.111SPCh. 22 - Prob. 22.112SPCh. 22 - Prob. 22.113SPCh. 22 - Prob. 22.114SPCh. 22 - Prob. 22.115SPCh. 22 - Prob. 22.116SPCh. 22 - Prob. 22.117SPCh. 22 - Prob. 22.118SPCh. 22 - Prob. 22.119SPCh. 22 - Prob. 22.120SPCh. 22 - Prob. 22.121SPCh. 22 - Prob. 22.122SPCh. 22 - Prob. 22.123SPCh. 22 - Prob. 22.124SPCh. 22 - Prob. 22.125SPCh. 22 - Prob. 22.126SPCh. 22 - Prob. 22.127SPCh. 22 - Prob. 22.128SPCh. 22 - Prob. 22.129SPCh. 22 - Prob. 22.130SPCh. 22 - Prob. 22.131SPCh. 22 - Prob. 22.132SPCh. 22 - Prob. 22.133SPCh. 22 - Prob. 22.134SPCh. 22 - Prob. 22.135SPCh. 22 - Prob. 22.136SPCh. 22 - Prob. 22.137SPCh. 22 - Prob. 22.138SPCh. 22 - Prob. 22.139SPCh. 22 - Prob. 22.140SPCh. 22 - Prob. 22.141SPCh. 22 - Prob. 22.142SPCh. 22 - Prob. 22.143SPCh. 22 - Prob. 22.144SPCh. 22 - Prob. 22.145SPCh. 22 - Prob. 22.146SPCh. 22 - Prob. 22.147SPCh. 22 - Prob. 22.148SPCh. 22 - Prob. 22.149SPCh. 22 - Prob. 22.150SPCh. 22 - Prob. 22.151SPCh. 22 - Prob. 22.152SPCh. 22 - Prob. 22.153SPCh. 22 - Prob. 22.154SPCh. 22 - Prob. 22.155SPCh. 22 - Prob. 22.156SPCh. 22 - Prob. 22.157SPCh. 22 - Prob. 22.158CPCh. 22 - Prob. 22.159CPCh. 22 - Prob. 22.160CPCh. 22 - Prob. 22.161CPCh. 22 - Prob. 22.162CPCh. 22 - Prob. 22.163CPCh. 22 - Prob. 22.164CPCh. 22 - Prob. 22.165CPCh. 22 - Prob. 22.166CPCh. 22 - Prob. 22.167CPCh. 22 - Prob. 22.168CPCh. 22 - Prob. 22.169CPCh. 22 - Prob. 22.170CPCh. 22 - Prob. 22.171CPCh. 22 - Prob. 22.172CPCh. 22 - Prob. 22.173CPCh. 22 - Prob. 22.174CPCh. 22 - Prob. 22.175MPCh. 22 - Prob. 22.176MPCh. 22 - Prob. 22.177MPCh. 22 - Prob. 22.178MPCh. 22 - Prob. 22.179MP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Heating an alcohol in the presence of sulfuric or phosphoric acid will cause a dehydration to occur: the removal of the elements of water from a molecule, forming an alkene. The reaction usually follows an E1 mechanism. The SN1 pathway is suppressed by using a strong acid whose conjugate base is a poor nucleophile. Further, heating the reaction mixture causes a greater increase in the rate of E1 compared to the rate of S№1. 2nd attempt 0 See Periodic Table See Hint Draw the organic intermediate from the first step (no byproducts) and draw curved arrow(s) to show how it reacts. TH +11: 1st attempt Feedback H H H C F F See Periodic Table See Hintarrow_forwardThis molecule undergoes an E1 mechanism when stirred in methanol. 3rd attempt CH₂OH CH₂OH 6148 O See Periodic Table. See Hint Draw 3 chemical species including formal charges and lone pairs of electrons. Add the missing curved arrow notation. H N O O SA 3 Br Iarrow_forwardComplete the mechanism for the E1 reaction below by following the directions written above each of the five boxes. Be sure to include lone pair electrons and nonzero formal charges. 1st attempt Y 0 + Provide the missing curved arrow notation. 01: See Periodic Table See Hint H C Br Iarrow_forward
- Please help answer number 2. Thanks in advance.arrow_forwardHow do I explain this? Thank you!arrow_forwardWhen an unknown amine reacts with an unknown acid chloride, an amide with a molecular mass of 163 g/mol (M* = 163 m/z) is formed. In the infrared spectrum, important absorptions appear at 1661, 750 and 690 cm. The 13C NMR and DEPT spectra are provided. Draw the structure of the product as the resonance contributor lacking any formal charges. 13C NMR DEPT 90 200 160 120 80 40 0 200 160 120 80 40 0 DEPT 135 T 200 160 120 80 40 0 Draw the unknown amide. Select Dow Templates More Fragearrow_forward
- Identify the unknown compound from its IR and proton NMR spectra. C4H6O: 'H NMR: 82.43 (1H, t, J = 2 Hz); 8 3.41 (3H, s); 8 4.10 (2H, d, J = 2 Hz) IR: 2125, 3300 cm¹ The C4H6O compound liberates a gas when treated with C2H5 MgBr. Draw the unknown compound. Select Draw с H Templates Morearrow_forwardPlease help with number 6 I got a negative number could that be right?arrow_forward1,4-Dimethyl-1,3-cyclohexadiene can undergo 1,2- or 1,4-addition with hydrogen halides. (a) 1,2-Addition i. Draw the carbocation intermediate(s) formed during the 1,2-addition of hydrobromic acid to 1,4-dimethyl-1,3-cyclohexadiene. ii. What is the major 1,2-addition product formed during the reaction in (i)? (b) 1,4-Addition i. Draw the carbocation intermediate(s) formed during the 1,4-addition of hydrobromic acid to 1,4-dimethyl-1,3-cyclohexadiene. ii. What is the major 1,4-addition product formed from the reaction in (i)? (c) What is the kinetic product from the reaction of one mole of hydrobromic acid with 1,4-dimethyl-1,3-cyclohexadiene? Explain your reasoning. (d) What is the thermodynamic product from the reaction of one mole of hydrobro-mic acid with 1,4-dimethyl-1,3-cyclohexadiene? Explain your reasoning. (e) What major product will result when 1,4-dimethyl-1,3-cyclohexadiene is treated with one mole of hydrobromic acid at - 78 deg * C ? Explain your reasoning.arrow_forward
- Give the product of the bimolecular elimination from each of the isomeric halogenated compounds. Reaction A Reaction B. КОВ CH₂ HotBu +B+ ко HOIBU +Br+ Templates More QQQ Select Cv Templates More Cras QQQ One of these compounds undergoes elimination 50x faster than the other. Which one and why? Reaction A because the conformation needed for elimination places the phenyl groups and to each other Reaction A because the conformation needed for elimination places the phenyl groups gauche to each other. ◇ Reaction B because the conformation needed for elimination places the phenyl groups gach to each other. Reaction B because the conformation needed for elimination places the phenyl groups anti to each other.arrow_forwardFive isomeric alkenes. A through each undergo catalytic hydrogenation to give 2-methylpentane The IR spectra of these five alkenes have the key absorptions (in cm Compound Compound A –912. (§), 994 (5), 1643 (%), 3077 (1) Compound B 833 (3), 1667 (W), 3050 (weak shoulder on C-Habsorption) Compound C Compound D) –714 (5), 1665 (w), 3010 (m) 885 (3), 1650 (m), 3086 (m) 967 (5), no aharption 1600 to 1700, 3040 (m) Compound K Match each compound to the data presented. Compound A Compound B Compound C Compound D Compoundarrow_forward7. The three sets of replicate results below were accumulated for the analysis of the same sample. Pool these data to obtain the most efficient estimate of the mean analyte content and the standard deviation. Lead content/ppm: Set 1 Set 2 Set 3 1. 9.76 9.87 9.85 2. 9.42 9.64 9.91 3. 9.53 9.71 9.42 9.81 9.49arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
ChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill Education
Principles of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill Education
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY
Lanthanoids and its Position in Periodic Table - D and F Block Elements - Chemistry Class 12; Author: Ekeeda;https://www.youtube.com/watch?v=ZM04kRxm6tY;License: Standard YouTube License, CC-BY