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Concept explainers
(a)
Interpretation: To determine the magnetic property of the given compounds.
Concept Introduction:
Spectrochemical series: The list of ligands arranged in an ascending order of
Crystal field splitting: The energy gap between the splitting of d-orbitals of the metal ion in presence of ligands is known as the crystal field splitting
To Identify: To determine the magnetic property of the given compounds.
(a)
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Answer to Problem 22.80QP
The
Explanation of Solution
Interpret the given information.
The
(b)
Interpretation: To determine the magnetic property of the given compounds.
Concept Introduction:
Spectrochemical series: The list of ligands arranged in an ascending order of
Crystal field splitting: The energy gap between the splitting of d-orbitals of the metal ion in presence of ligands is known as the crystal field splitting
To Identify: To determine the magnetic property of the given compounds.
(b)
![Check Mark](/static/check-mark.png)
Answer to Problem 22.80QP
The systematic name of the given compound
Explanation of Solution
Interpret the given information.
The systematic name of the given compound
The six ligands around the metal ion give octahedral geometry.
Magnetic property of the compound:
The high field complex ion possesses eight d-electrons and the two electrons are unpaired and exhibits paramagnetic.
(c)
Interpretation: To determine the magnetic property of the given compounds.
Concept Introduction:
Spectrochemical series: The list of ligands arranged in an ascending order of
Crystal field splitting: The energy gap between the splitting of d-orbitals of the metal ion in presence of ligands is known as the crystal field splitting
To Identify: To determine the magnetic property of the given compounds.
(c)
![Check Mark](/static/check-mark.png)
Answer to Problem 22.80QP
The square-planar geometry will be diamagnetic in nature.
Explanation of Solution
Interpret the given information.
In complex ion of
In complex ion of
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Chapter 22 Solutions
Chemistry: Atoms First V1
- 1. Consider a pair of elements with 2p and 4p valence orbitals (e.g., N and Se). Draw their (2p and 4p AO's) radial probability plots, and sketch their angular profiles. Then, consider these orbitals from the two atoms forming a homonuclear л-bond. Which element would have a stronger bond, and why? (4 points)arrow_forwardWrite the reaction and show the mechanism of the reaction. Include the mechanism for formation of the NO2+ 2. Explain, using resonance structures, why the meta isomer is formed. Draw possible resonance structures for ortho, meta and para.arrow_forwardNonearrow_forward
- 3. A molecular form of "dicarbon", C2, can be generated in gas phase. Its bond dissociation energy has been determined at 599 kJ/mol. Use molecular orbital theory to explain why energy of dissociation for C₂+ is 513 kJ/mol, and that for C2² is 818 kJ/mol. (10 points)arrow_forward9.73 g of lead(IV) chloride contains enough Cl- ions to make ____ g of magnesium chloride.arrow_forward6. a) C2's. Phosphorus pentafluoride PF5 belongs to D3h symmetry group. Draw the structure of the molecule, identify principal axis of rotation and perpendicular (4 points) b) assume that the principal axis of rotation is aligned with z axis, assign symmetry labels (such as a1, b2, etc.) to the following atomic orbitals of the P atom. (character table for this group is included in the Supplemental material). 3s 3pz (6 points) 3dz²arrow_forward
- 2. Construct Lewis-dot structures, and draw VESPR models for the ions listed below. a) SiF5 (4 points) b) IOF4 (4 points)arrow_forward5. Complex anion [AuCl2]¯ belongs to Doh symmetry point group. What is the shape of this ion? (4 points)arrow_forward4. Assign the following molecules to proper point groups: Pyridine N 1,3,5-triazine N Narrow_forward
- 7. a) Under normal conditions (room temperature & atmospheric pressure) potassium assumes bcc lattice. Atomic radius for 12-coordinate K atom is listed as 235 pm. What is the radius of potassium atom under normal conditions? (3 points) b) Titanium metal crystallyzes in hcp lattice. Under proper conditions nitrogen can be absorbed into the lattice of titanium resulting in an alloy of stoichiometry TiNo.2. Is this compound likely to be a substitutional or an interstitial alloy? (Radius of Ti (12-coordinate) is 147 pm; radius of N atom is 75 pm. (3 points)arrow_forwardcan someone answer the questions and draw out the complete mechanismarrow_forwardPlease help, draw and me the proper mechanisms.arrow_forward
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