CHEM 212:STUDENT SOLUTION MANUAL
8th Edition
ISBN: 9781260304473
Author: SILBERBERG
Publisher: MCGRAW-HILL CUSTOM PUBLISHING
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Question
Chapter 22, Problem 22.68P
(a)
Interpretation Introduction
Interpretation:
The cell potential for the oxidation of air of gold to gold ion has to be calculated. Also, the spontaneity of given reaction has to be predicted.
Concept Introduction:
The cell potential of an
(b)
Interpretation Introduction
Interpretation:
The formation of complex ion changes cell potential has to be explained.
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Instructions: Complete the questions in the space provided. Show all your work
1. You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure
the initial reaction rate and the starting concentrations of the reactions for 4 trials.
BrO³¯ (aq) + 5Br¯ (aq) + 6H* (aq) → 3Br₂ (l) + 3H2O (l)
Initial rate
Trial
[BrO3]
[H*]
[Br]
(mol/L)
(mol/L) | (mol/L)
(mol/L.s)
1
0.10
0.10
0.10
8.0
2
0.20
0.10
0.10
16
3
0.10
0.20
0.10
16
4
0.10
0.10
0.20
32
a.
Based on the above data what is the rate law expression?
b. Solve for the value of k (make sure to include proper units)
2. The proposed reaction mechanism is as follows:
i.
ii.
BrО¸¯ (aq) + H+ (aq) → HBrO3 (aq)
HBrO³ (aq) + H* (aq) → H₂BrO3* (aq)
iii.
H₂BrO³* (aq) + Br¯ (aq) → Br₂O₂ (aq) + H2O (l)
[Fast]
[Medium]
[Slow]
iv.
Br₂O₂ (aq) + 4H*(aq) + 4Br(aq) → 3Br₂ (l) + H2O (l)
[Fast]
Evaluate the validity of this proposed reaction. Justify your answer.
е.
Д
CH3
D*, D20
C.
NaOMe,
Br
Br
Chapter 22 Solutions
CHEM 212:STUDENT SOLUTION MANUAL
Ch. 22 - Prob. 22.1PCh. 22 - Prob. 22.2PCh. 22 - Prob. 22.3PCh. 22 - Prob. 22.4PCh. 22 - Prob. 22.5PCh. 22 - Prob. 22.6PCh. 22 - Prob. 22.7PCh. 22 - Prob. 22.8PCh. 22 - Prob. 22.9PCh. 22 - Prob. 22.10P
Ch. 22 - Prob. 22.11PCh. 22 - Prob. 22.12PCh. 22 - Prob. 22.13PCh. 22 - Prob. 22.14PCh. 22 - Prob. 22.15PCh. 22 - Prob. 22.16PCh. 22 - Prob. 22.17PCh. 22 - Prob. 22.18PCh. 22 - Define: (a) ore; (b) mineral; (c) gangue; (d)...Ch. 22 - Define: (a) roasting; (b) smelting; (c) flotation;...Ch. 22 - What factors determine which reducing agent is...Ch. 22 - Prob. 22.22PCh. 22 - Prob. 22.23PCh. 22 - Prob. 22.24PCh. 22 - Prob. 22.25PCh. 22 - Prob. 22.26PCh. 22 - Prob. 22.27PCh. 22 - Why is cryolite used in the electrolysis of...Ch. 22 - Prob. 22.29PCh. 22 - How is Le Châtelier’s principle involved in the...Ch. 22 - Elemental Li and Na are prepared by electrolysis...Ch. 22 - A Downs cell operating at 77.0 A produces 31.0 kg...Ch. 22 - Prob. 22.33PCh. 22 - Prob. 22.34PCh. 22 - The last step in the Dow process for the...Ch. 22 - Prob. 22.36PCh. 22 - Prob. 22.37PCh. 22 - Prob. 22.38PCh. 22 - Prob. 22.39PCh. 22 - Prob. 22.40PCh. 22 - Prob. 22.41PCh. 22 - Prob. 22.42PCh. 22 - Prob. 22.43PCh. 22 - Prob. 22.44PCh. 22 - Prob. 22.45PCh. 22 - Prob. 22.46PCh. 22 - Prob. 22.47PCh. 22 - Prob. 22.48PCh. 22 - Prob. 22.49PCh. 22 - Prob. 22.50PCh. 22 - Prob. 22.51PCh. 22 - Prob. 22.52PCh. 22 - Prob. 22.53PCh. 22 - Prob. 22.54PCh. 22 - Prob. 22.55PCh. 22 - Prob. 22.56PCh. 22 - Prob. 22.57PCh. 22 - Prob. 22.58PCh. 22 - Prob. 22.59PCh. 22 - In the production of magnesium, Mg(OH)2 is...Ch. 22 - Prob. 22.61PCh. 22 - Prob. 22.62PCh. 22 - The production of S8 from the H2S(g) found in...Ch. 22 - Prob. 22.64PCh. 22 - Prob. 22.65PCh. 22 - Prob. 22.66PCh. 22 - Prob. 22.67PCh. 22 - Prob. 22.68PCh. 22 - Prob. 22.69PCh. 22 - Prob. 22.70PCh. 22 - Prob. 22.71PCh. 22 - Prob. 22.72PCh. 22 - Prob. 22.73PCh. 22 - Prob. 22.74PCh. 22 - Prob. 22.75PCh. 22 - Prob. 22.76PCh. 22 - Prob. 22.77PCh. 22 - Prob. 22.78PCh. 22 - Prob. 22.79PCh. 22 - Prob. 22.80PCh. 22 - Prob. 22.81PCh. 22 - Prob. 22.82PCh. 22 - Prob. 22.83PCh. 22 - Prob. 22.84PCh. 22 - Prob. 22.85PCh. 22 - Prob. 22.86P
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