Physical Chemistry
Physical Chemistry
2nd Edition
ISBN: 9781285969770
Author: Ball
Publisher: Cengage
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Chapter 22, Problem 22.5E
Interpretation Introduction

(a)

Interpretation:

The work done needed to increase the surface area of a pool of chloroform by 50.0cm2 is to be calculated.

Concept introduction:

The atoms or molecules at the surface of the liquid are considered as a film. The atoms or molecules in bulk imply a force on the atoms or molecules at the surface of the liquid and tends to minimize the surface area of the liquid. This phenomenon is known as the surface tension of the liquid.

Expert Solution
Check Mark

Answer to Problem 22.5E

The work done required to increase the surface area of a pool of chloroform by 50.0cm2 is 1.355×104J.

Explanation of Solution

The work done to increase the surface area is calculated by the formula shown below.

w=γΔA …(1)

Where,

γ is the surface tension.

ΔA is the change in surface area.

The conversion of dyncm1 into ergcm2 is shown below.

1dyncm1=1ergcm2

Therefore, conversion of 27.1dyncm1 into ergcm2 is shown below.

27.1dyncm1=27.1ergcm2

The value of γ and ΔA are 27.1ergcm2 and 50.0cm2.

Substitute the values of γ and ΔA in equation (1).

w=27.1ergcm2×50.0cm2=1355erg

The conversion of erg into J is shown below.

1erg=107J

Therefore,

1355erg=1355×107J=1.355×104J

Conclusion

The work done to increase the surface area of pool of chloroform by 50.0cm2 is 1.355×104J.

Interpretation Introduction

(b)

Interpretation:

The work done to make the film of chloroform having area of 0.010m2 is to be calculated.

Concept introduction:

The atoms or molecules at the surface of the liquid are considered as a film. The atoms or molecules in bulk imply a force on the atoms or molecules at the surface of the liquid and tends to minimize the surface area of the liquid. This phenomenon is known as the surface tension of the liquid.

Expert Solution
Check Mark

Answer to Problem 22.5E

The work done to make the film of chloroform having area of 0.010m2 is 2.71×104J.

Explanation of Solution

The making of film is same as increasing the surface area of a liquid. Therefore, the work done to make the film of chloroform is calculated by the formula given below.

w=γΔA …(1)

Where,

γ is the surface tension.

ΔA is the change in surface area.

The conversion of dyncm1 into ergcm2 is shown below.

1dyncm1=1ergcm2

Therefore, the conversion of 27.1dyncm1 into ergcm2 is shown below.

27.1dyncm1=27.1ergcm2

The conversion of m2 into cm2 is done as shown below.

1m2=104cm2

Therefore, the conversion of 0.010m2 into cm2 is done as shown below.

0.010m2=0.010×104cm2=102cm2

The value of γ and ΔA are 27.1ergcm2 and 102cm2.

Substitute the values of γ and ΔA in equation (1).

w=γΔA=27.1ergcm2×102cm2=2710erg

The conversion of erg into J is shown below.

1erg=107J

Therefore,

2710erg=2710×107J=2.71×104J

Conclusion

The work done to make the film of chloroform having area of 0.010m2 is 2.71×104J.

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