EBK ORGANIC CHEMISTRY: PRINCIPLES AND M
2nd Edition
ISBN: 9780393630817
Author: KARTY
Publisher: W.W.NORTON+CO. (CC)
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Question
Chapter 22, Problem 22.27P
Interpretation Introduction
(a)
Interpretation:
In the given reaction, the
Concept introduction:
In Friedel Craft’s acylation reaction, the aromatic species is treated with acyl chloride. The product of Friedel Craft’s acylation reaction is
Interpretation Introduction
(b)
Interpretation:
In the given reaction, the aromatic ring has just one chemically distinct, aromatic H, so a single electrophilic aromatic substitution will lead to a just a single product. The product of the given reaction is to be determined.
Concept introduction:
Electrophiles in electrophilic aromatic substitution reactions typically must be generated in situ from more stable precursors that can be added as starting materials. The aluminum chloride acts as Lewis acid and forms a complex with chlorine. After heterolysis, electrophilic aromatic substitution reaction takes place. The arenium ion intermediate is a carbocation intermediate consisting of five
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Draw the anti-Markovnikov product of the hydration of this alkene.
this problem.
Note for advanced students: draw only one product, and don't worry about showing any stereochemistry. Drawing dash and wedge bonds has been disabled for
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Explanation
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AG/F-2° V
3. Before proceeding with this problem you may want to glance at p. 466 of your textbook
where various oxo-phosphorus derivatives and their oxidation states are summarized.
Shown below are Latimer diagrams for phosphorus at pH values at 0 and 14:
-0.93
+0.38
-0.50
-0.51 -0.06
H3PO4 →H4P206 →H3PO3 →→H3PO₂ → P → PH3
Acidic solution
Basic solution
-0.28
-0.50
3--1.12
-1.57
-2.05 -0.89
PO HPO H₂PO₂ →P → PH3
-1.73
a) Under acidic conditions, H3PO4 can be reduced into H3PO3 directly (-0.28V), or via the
formation and reduction of H4P206 (-0.93/+0.38V). Calculate the values of AG's for both
processes; comment.
(3 points)
0.5
PH
P
0.0
-0.5
-1.0-
-1.5-
-2.0
H.PO,
-2.3+
-3 -2
-1
1
2
3
2
H,PO,
b) Frost diagram for phosphorus under acidic
conditions is shown. Identify possible
disproportionation and comproportionation processes;
write out chemical equations describing them. (2 points)
H,PO
4
S
Oxidation stale, N
Chapter 22 Solutions
EBK ORGANIC CHEMISTRY: PRINCIPLES AND M
Ch. 22 - Prob. 22.1PCh. 22 - Prob. 22.2PCh. 22 - Prob. 22.3PCh. 22 - Prob. 22.4PCh. 22 - Prob. 22.5PCh. 22 - Prob. 22.6PCh. 22 - Prob. 22.7PCh. 22 - Prob. 22.8PCh. 22 - Prob. 22.9PCh. 22 - Prob. 22.10P
Ch. 22 - Prob. 22.11PCh. 22 - Prob. 22.12PCh. 22 - Prob. 22.13PCh. 22 - Prob. 22.14PCh. 22 - Prob. 22.15PCh. 22 - Prob. 22.16PCh. 22 - Prob. 22.17PCh. 22 - Prob. 22.18PCh. 22 - Prob. 22.19PCh. 22 - Prob. 22.20PCh. 22 - Prob. 22.21PCh. 22 - Prob. 22.22PCh. 22 - Prob. 22.23PCh. 22 - Prob. 22.24PCh. 22 - Prob. 22.25PCh. 22 - Prob. 22.26PCh. 22 - Prob. 22.27PCh. 22 - Prob. 22.28PCh. 22 - Prob. 22.29PCh. 22 - Prob. 22.30PCh. 22 - Prob. 22.31PCh. 22 - Prob. 22.32PCh. 22 - Prob. 22.33PCh. 22 - Prob. 22.34PCh. 22 - Prob. 22.35PCh. 22 - Prob. 22.36PCh. 22 - Prob. 22.37PCh. 22 - Prob. 22.38PCh. 22 - Prob. 22.39PCh. 22 - Prob. 22.40PCh. 22 - Prob. 22.41PCh. 22 - Prob. 22.42PCh. 22 - Prob. 22.43PCh. 22 - Prob. 22.44PCh. 22 - Prob. 22.45PCh. 22 - Prob. 22.46PCh. 22 - Prob. 22.47PCh. 22 - Prob. 22.48PCh. 22 - Prob. 22.49PCh. 22 - Prob. 22.50PCh. 22 - Prob. 22.51PCh. 22 - Prob. 22.52PCh. 22 - Prob. 22.53PCh. 22 - Prob. 22.54PCh. 22 - Prob. 22.55PCh. 22 - Prob. 22.56PCh. 22 - Prob. 22.57PCh. 22 - Prob. 22.58PCh. 22 - Prob. 22.59PCh. 22 - Prob. 22.60PCh. 22 - Prob. 22.61PCh. 22 - Prob. 22.62PCh. 22 - Prob. 22.63PCh. 22 - Prob. 22.64PCh. 22 - Prob. 22.65PCh. 22 - Prob. 22.66PCh. 22 - Prob. 22.67PCh. 22 - Prob. 22.1YTCh. 22 - Prob. 22.2YTCh. 22 - Prob. 22.3YTCh. 22 - Prob. 22.4YTCh. 22 - Prob. 22.5YTCh. 22 - Prob. 22.6YTCh. 22 - Prob. 22.7YTCh. 22 - Prob. 22.8YTCh. 22 - Prob. 22.9YTCh. 22 - Prob. 22.10YTCh. 22 - Prob. 22.11YTCh. 22 - Prob. 22.12YT
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