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(a)
Interpretation:
The formula of the oxide that in its highest oxidation state should be written.
Concept introduction:
Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.
When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.
All the oxygen in oxides are in
(b)
Interpretation:
Each oxide should be classified as basic, acidic or amphoteric.
Concept introduction:
Oxides can be categorized as basic, acidic or amphoteric. Basic oxides are ionic and are formed by metals on the left side of the periodic table. Acidic oxides are covalent and are formed by nonmetals on the right side of the periodic table. Amphoteric oxides can react with both acids and bases.
(c)
Interpretation:
Which oxide is the most ionic and which oxide is the most covalent should be discussed.
Concept introduction:
When electronegativity difference between atoms in a bond is larger than two units, that bond is said to be ionic and when the difference is less than two, it is said to be a covalent bond.
(d)
Interpretation:
Which oxides are molecular and which are solids with an infinitely extended three-dimensional crystal structure should be determined.
Concept introduction:
Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.
When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.
(e)
Interpretation:
Which oxide has the highest melting point and which has the lowest melting point should be determined.
Concept introduction:
Most of ionic oxides form crystal lattice structures. Lattice energies are very high, so, the bonds between atoms are difficult to break. So, ionic oxides have higher melting points. Most first row and second row nonmetal oxides have lower melting points, so, most of them exists as gas or liquid at room temperature.
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Chapter 22 Solutions
EBK CHEMISTRY
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- please helparrow_forwardExperiment 1 Data Table 1: Conservation of Mass - Initial Mass Data Table 1 Data Table 2 Data Table 3 Data Table 4 Panel 1 Photo 1 Data Table 5 Reaction Mass of test tube and 5.0% HC₂H₂O2 (g) # (A) (B) Mass of NaHCO, (g) Mass of balloon and NaHCO, (g) (C) 0.10 1 0829 14.38g 0.20 2 0.929 14.29g 0.35 1.00g 3 14.25g 0.50 1.14g 14.29 Experiment 1 Data Table 2: Moles of HC2H3O2 Reaction Volume of Mass of Moles of HC₂H₂O₂ 5.0% Vinegar (g) (ML) 5.0 0.25 0042 mol 2 5.0 0.25 0042 mol 3 5.0 0.25 0042 mol 5.0 0.25 0042 mol Experiment 1 Data Table 3: Moles of NaHCO3 Reaction Mass of NaHCO (g) 10g 20g 35g 50g Experiment 1 Data Table 4: Theoretical Yield of CO₂ Reaction # 1 2 3 Experiment 1 Total mass before reaction (g) (D=A+C) 15.29 15.21g 15.25g 15.349 Exercise 1 Data Table 1 Data Table 2 Data Table 3 Data Table 4 Panel 1 Photo 1 Data Table 5 Exercise 1- Data Table 1 Data Table 2 DataTable 3 Data Table 4 Panel 1 Photo 1 Data Table 5 Exercise 1- Moles of NaHCO 0012 mol 0025 mol 0044 mol 0062 mol…arrow_forwardThe chemical reaction you investigated is a two-step reaction. What type of reaction occurs in each step? How did you determine your answer?arrow_forward
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