
(a)
Interpretation:
The electron dot structure and the geometrical structure of
Concept introduction:
VSEPR theory stands as Valence Shell Electron Pair Repulsion Theory. It helps to predict the molecular shape or geometry of the molecule with the help of the number of bond pairs or lone pairs present in it. According to the VSEPR theory, the presence of lone pair on the central atom of molecule causes deviation from standard molecular geometry. This is because of the repulsion between lone pairs and bond pairs of the central atom of the molecule. The order of repulsion is:
Lone pair-lone pair > lone pair-bond pair > bond pair-bond pair
Based on the number of lone pairs and bond pairs, the molecular geometry can be determined with the help of the below table.
Number of hybridization | Bond pair | Lone pair | Geometry |
2 | 2 | 0 | Linear |
2 | 1 | 1 | Linear |
3 | 3 | 0 | Trigonal planar |
3 | 2 | 1 | Bent |
4 | 4 | 0 | Tetrahedral |
4 | 3 | 1 | Trigonal pyramidal |
4 | 2 | 2 | Bent |
5 | 5 | 0 | Trigonal bipyramidal |
5 | 4 | 1 | See saw |
5 | 3 | 2 | T shaped |
5 | 2 | 3 | Linear |
6 | 6 | 0 | Octahedral |
(b)
Interpretation:
The electron dot structure and the geometrical structure of
Concept introduction:
VSEPR theory stands as Valence Shell Electron Pair Repulsion Theory. It helps to predict the molecular shape or geometry of the molecule with the help of the number of bond pairs or lone pairs present in it. According to the VSEPR theory, the presence of lone pair on the central atom of molecule causes deviation from standard molecular geometry. This is because of the repulsion between lone pairs and bond pairs of the central atom of the molecule. The order of repulsion is:
Lone pair-lone pair > lone pair-bond pair > bond pair-bond pair
Based on the number of lone pairs and bond pairs, the molecular geometry can be determined with the help of the below table.
Number of hybridization | Bond pair | Lone pair | Geometry |
2 | 2 | 0 | Linear |
2 | 1 | 1 | Linear |
3 | 3 | 0 | Trigonal planar |
3 | 2 | 1 | Bent |
4 | 4 | 0 | Tetrahedral |
4 | 3 | 1 | Trigonal pyramidal |
4 | 2 | 2 | Bent |
5 | 5 | 0 | Trigonal bipyramidal |
5 | 4 | 1 | See saw |
5 | 3 | 2 | T shaped |
5 | 2 | 3 | Linear |
6 | 6 | 0 | Octahedral |
(c)
Interpretation:
The electron dot structure and the geometrical structure of
Concept introduction:
VSEPR theory stands as Valence Shell Electron Pair Repulsion Theory. It helps to predict the molecular shape or geometry of the molecule with the help of the number of bond pairs or lone pairs present in it. According to the VSEPR theory, the presence of lone pair on the central atom of molecule causes deviation from standard molecular geometry. This is because of the repulsion between lone pairs and bond pairs of the central atom of the molecule. The order of repulsion is:
Lone pair-lone pair > lone pair-bond pair > bond pair-bond pair
Based on the number of lone pairs and bond pairs, the molecular geometry can be determined with the help of the below table.
Number of hybridization | Bond pair | Lone pair | Geometry |
2 | 2 | 0 | Linear |
2 | 1 | 1 | Linear |
3 | 3 | 0 | Trigonal planar |
3 | 2 | 1 | Bent |
4 | 4 | 0 | Tetrahedral |
4 | 3 | 1 | Trigonal pyramidal |
4 | 2 | 2 | Bent |
5 | 5 | 0 | Trigonal bipyramidal |
5 | 4 | 1 | See saw |
5 | 3 | 2 | T shaped |
5 | 2 | 3 | Linear |
6 | 6 | 0 | Octahedral |
(d)
Interpretation:
The electron dot structure and the geometrical structure of
Concept introduction:
VSEPR theory stands as Valence Shell Electron Pair Repulsion Theory. It helps to predict the molecular shape or geometry of the molecule with the help of the number of bond pairs or lone pairs present in it. According to the VSEPR theory, the presence of lone pair on the central atom of molecule causes deviation from standard molecular geometry. This is because of the repulsion between lone pairs and bond pairs of the central atom of the molecule. The order of repulsion is:
Lone pair-lone pair > lone pair-bond pair > bond pair-bond pair
Based on the number of lone pair and bond pair, the molecular geometry can be determined with the help of the below table.
Number of hybridization | Bond pair | Lone pair | Geometry |
2 | 2 | 0 | Linear |
2 | 1 | 1 | Linear |
3 | 3 | 0 | Trigonal planar |
3 | 2 | 1 | Bent |
4 | 4 | 0 | Tetrahedral |
4 | 3 | 1 | Trigonal pyramidal |
4 | 2 | 2 | Bent |
5 | 5 | 0 | Trigonal bipyramidal |
5 | 4 | 1 | See saw |
5 | 3 | 2 | T shaped |
5 | 2 | 3 | Linear |
6 | 6 | 0 | Octahedral |

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Chapter 22 Solutions
EBK CHEMISTRY
- Draw the major product of this reaction. Ignore inorganic byproducts. ○ O 1. H₂O, pyridine 2. neutralizing work-up a N W X 人 Parrow_forward✓ Check the box under each molecule that has a total of five ẞ hydrogens. If none of the molecules fit this description, check the box underneath the table. tab OH CI 0 Br xx Br None of these molecules have a total of five ẞ hydrogens. esc Explanation Check caps lock shift 1 fn control 02 F2 W Q A N #3 S 80 F3 E $ t 01 205 % 5 F5 & 7 © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility FT * 8 R T Y U כ F6 9 FIG F11 F D G H J K L C X V B < N M H option command P H + F12 commandarrow_forwardDraw the major product of this reaction. Ignore inorganic byproducts and the carboxylic acid side product. O 1. CHзMgBr (excess) 2. H₂O ✓ W X 人arrow_forward
- If cyclopentyl acetaldehyde reacts with NaOH, state the product (formula).arrow_forwardDraw the major product of this reaction. Ignore inorganic byproducts. N S S HgCl2, H2SO4 く 8 W X Parrow_forwardtab esc く Drawing the After running various experiments, you determine that the mechanism for the following reaction occurs in a step-wise fashion. Br + OH + Using this information, draw the correct mechanism in the space below. 1 Explanation Check F2 F1 @2 Q W A os lock control option T S # 3 80 F3 Br $ 4 0105 % OH2 + Br Add/Remove step X C F5 F6 6 R E T Y 29 & 7 F D G H Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Ce A F7 DII F8 C Ո 8 * 9 4 F10 F C J K L C V Z X B N M H command P ge Coarrow_forward
- Indicate compound A that must react with ethylbenzene to obtain 4-ethylbenzene-1-sulfonic acid. 3-bromo-4-ethylbenzene-1-sulfonic acid.arrow_forwardPart 1 of 2 Draw the structure of A, the minor E1 product of the reaction. esc I Skip Part Check H₂O, D 2 A + Click and drag to start drawing a structure. -0- F1 F2 1 2 # 3 Q A 80 F3 W E S D F4 $ 4 % 5 F5 ㅇ F6 R T Y F G X 5 & 7 + Save 2025 McGraw Hill LLC. All Rights Reserved. DII F7 F8 H * C 80 J Z X C V B N 4 F9 6arrow_forwardFile Preview The following is a total synthesis of the pheromone of the western pine beetle. Such syntheses are interesting both because of the organic chemistry, and because of the possibility of using species specific insecticides, rather than broad band insecticides. Provide the reagents for each step. There is some chemistry from our most recent chapter in this synthesis, but other steps are review from earlier chapters. (8 points) COOEt COOEt A C COOEt COOEt COOH B OH OTS CN D E See the last homework set F for assistance on this one. H+, H₂O G OH OH The last step is just nucleophilic addition reactions, taking the ketone to an acetal, intramolecularly. But it is hard to visualize the three dimensional shape as it occurs. Frontalin, pheromone of the western pine beetlearrow_forward
- For the reaction below: 1. Draw all reasonable elimination products to the right of the arrow. 2. In the box below the reaction, redraw any product you expect to be a major product. C Major Product: Check + ◎ + X ง © Cl I F2 80 F3 I σ F4 I F5 NaOH Click and drawing F6 A 2025 McGraw Hill LLC. All Rights E F7 F8 $ # % & 2 3 4 5 6 7 8 Q W E R T Y U A S D F G H Jarrow_forwardCan I please get help with this graph. If you can show exactly where it needs to pass through.arrow_forwardN Draw the major product of this reaction. Ignore inorganic byproducts. D 1. H₂O, pyridine 2. neutralizing work-up V P W X DE CO e C Larrow_forward
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