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(a)
Interpretation:
The formula of the oxide that in its highest oxidation state should be written.
Concept introduction:
Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.
When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.
All the oxygen in oxides are in
(b)
Interpretation:
Each oxide should be classified as basic, acidic or amphoteric.
Concept introduction:
Oxides can be categorized as basic, acidic or amphoteric. Basic oxides are ionic and are formed by metals on the left side of the periodic table. Acidic oxides are covalent and are formed by nonmetals on the right side of the periodic table. Amphoteric oxides can react with both acids and bases.
(c)
Interpretation:
Which oxide is the most ionic and which oxide is the most covalent should be discussed.
Concept introduction:
When electronegativity difference between atoms in a bond is larger than two units, that bond is said to be ionic and when the difference is less than two, it is said to be a covalent bond.
(d)
Interpretation:
Which oxides are molecular and which are solids with an infinitely extended three-dimensional crystal structure should be determined.
Concept introduction:
Oxygen has six valence electrons in its valence shell, therefore, oxygen can achieve an octet by accepting two electrons from an active metal or by sharing two additional electrons through covalent bonding.
When oxygen reacts with active metals, it gives ionic oxides. With nonmetals, oxygen forms covalent oxides.
(e)
Interpretation:
Which oxide has the highest melting point and which has the lowest melting point should be determined.
Concept introduction:
Most of ionic oxides form crystal lattice structures. Lattice energies are very high, so, the bonds between atoms are difficult to break. So, ionic oxides have higher melting points. Most first row and second row nonmetal oxides have lower melting points, so, most of them exists as gas or liquid at room temperature.
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Chapter 22 Solutions
Chemistry, Loose-leaf Edition (8th Edition)
- Predict the major organic product(s), if any, of the following reactions. Assume all reagents are in excess unless otherwise indicated.arrow_forwardHow many signals would you expect to find in the 1 H NMR spectrum of each given compound? Part 1 of 2 2 Part 2 of 2 HO 5 ☑ Х IIIIII***** §arrow_forwardA carbonyl compound has a molecular ion with a m/z of 86. The mass spectra of this compound also has a base peak with a m/z of 57. Draw the correct structure of this molecule. Drawingarrow_forward
- Can you draw this using Lewis dot structures and full structures in the same way they are so that I can better visualize them and then determine resonance?arrow_forwardSynthesize the following compound from cyclohexanol, ethanol, and any other needed reagentsarrow_forwardFor a titration of 20.00 mL of 0.0500 M H2SO4 with 0.100 M KOH, calculate the pH at each of the following volume of KOH used in the titration: 1) before the titration begin; 2) 10.00 mL; 3) 20.00 mL; 4) 30.00 mL. Ka2 = 1.20×10-2 for H2SO4.arrow_forward
- Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s) Be sure to account for all bond-breaking and bond-making steps Problem 73 of 10 Drawing Amows ro HO Donearrow_forward12. Synthesize the following target molecules (TMs) using the specified starting materials. .CI a) HO3S SM TM b) HO- SMarrow_forwardFor a titration of 20.00 mL of 0.0500 M H2SO4 with 0.100 M KOH, calculate the pH at each of the following volume of KOH used in the titration: 1) before the titration begin; 2) 10.00 mL; 3) 20.00 mL; 4) 30.00 mL. Ka2 = 1.20×10-2 for H2SO4.arrow_forward
- Write the systematic name of each organic molecule: structure name show work. don't give Ai generated solutionarrow_forwardShow work with explanation needed. Don't give Ai generated solutionarrow_forwardA Elschboard Part of SpeechT-D Alt Leaming App app.aktiv.com Curved arrows are used to illustrate the flow of electrons. Using the provided resonance structures, draw the curved electron- pushing arrows to show the interconversion between resonance hybrid contributors. Be sure to account for all bond-breaking and bond-making steps. Include all lone pairs and formal charges in the structures. Problem 45 of 10 I Select to Add Arrows N Please selarrow_forward
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