To organize the study findings in the following two-way table of counts. Add the group’s totals to your total.

Question

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Answer 1

Question

Chapter 22, Problem 22.1AYK

a.

To determine

To organize the study findings in the following two-way table of counts. Add the group’s totals to your total.

a.

Expert Solution

Explanation of Solution

Given:

The information is given in the book.

Calculation:

Let the attribute

A= nicotine e cigarette

B=patches

C= placebo e cigarette

According to report published verified abstinence;

In A= 21 of 289 that means remaining 289−21=268 are non-abstinence.

In B = 17 of 295 that means remaining 295−17=278 are non-abstinence.

In C = 3 of 73 that means remaining 73−3= 70 are non-abstinence.

	smoking status at 6 months		Total
treatment group	verified abstinence	non abstinence
Nicotine-e cigarette	21	268	289
patches	17	278	295
Placebo-e cigarette	3	70	73

b.

To determine

To organize the cited percent into a similar two-way table.

b.

Expert Solution

Explanation of Solution

Given:

The options are provided in the textbook.

Calculation:

The following is the organized table −

	smoking status at 6 months		Cite percent
treatment group	verified abstinence	non abstinence
Nicotine-e cigarette	21	268	7.2%
patches	17	278	6.11%
Placebo- e cigarette	3	70	4.2%

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Please help me with this statistics question

Please help me with the following statistic question

To evaluate the success of a 1-year experimental program designed to increase the mathematical achievement of underprivileged high school seniors, a random sample of participants in the program will be selected and their mathematics scores will be compared with the previous year’s statewide average of 525 for underprivileged seniors. The researchers want to determine whether the experimental program has increased the mean achievement level over the previous year’s statewide average. If alpha=.05, what sample size is needed to have a probability of Type II error of at most .025 if the actual mean is increased to 550? From previous results, sigma=80.

Answer 2

Question

Chapter 22, Problem 22.1AYK

a.

To determine

To organize the study findings in the following two-way table of counts. Add the group’s totals to your total.

a.

Expert Solution

Explanation of Solution

Given:

The information is given in the book.

Calculation:

Let the attribute

A= nicotine e cigarette

B=patches

C= placebo e cigarette

According to report published verified abstinence;

In A= 21 of 289 that means remaining 289−21=268 are non-abstinence.

In B = 17 of 295 that means remaining 295−17=278 are non-abstinence.

In C = 3 of 73 that means remaining 73−3= 70 are non-abstinence.

	smoking status at 6 months		Total
treatment group	verified abstinence	non abstinence
Nicotine-e cigarette	21	268	289
patches	17	278	295
Placebo-e cigarette	3	70	73

b.

To determine

To organize the cited percent into a similar two-way table.

b.

Expert Solution

Explanation of Solution

Given:

The options are provided in the textbook.

Calculation:

The following is the organized table −

	smoking status at 6 months		Cite percent
treatment group	verified abstinence	non abstinence
Nicotine-e cigarette	21	268	7.2%
patches	17	278	6.11%
Placebo- e cigarette	3	70	4.2%

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Answer 3

Question

Chapter 22, Problem 22.1AYK

a.

To determine

To organize the study findings in the following two-way table of counts. Add the group’s totals to your total.

a.

Expert Solution

Explanation of Solution

Given:

The information is given in the book.

Calculation:

Let the attribute

A= nicotine e cigarette

B=patches

C= placebo e cigarette

According to report published verified abstinence;

In A= 21 of 289 that means remaining 289−21=268 are non-abstinence.

In B = 17 of 295 that means remaining 295−17=278 are non-abstinence.

In C = 3 of 73 that means remaining 73−3= 70 are non-abstinence.

	smoking status at 6 months		Total
treatment group	verified abstinence	non abstinence
Nicotine-e cigarette	21	268	289
patches	17	278	295
Placebo-e cigarette	3	70	73

b.

To determine

To organize the cited percent into a similar two-way table.

b.

Expert Solution

Explanation of Solution

Given:

The options are provided in the textbook.

Calculation:

The following is the organized table −

	smoking status at 6 months		Cite percent
treatment group	verified abstinence	non abstinence
Nicotine-e cigarette	21	268	7.2%
patches	17	278	6.11%
Placebo- e cigarette	3	70	4.2%

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Answer 4

Question

Chapter 22, Problem 22.1AYK

a.

To determine

To organize the study findings in the following two-way table of counts. Add the group’s totals to your total.

a.

Expert Solution

Explanation of Solution

Given:

The information is given in the book.

Calculation:

Let the attribute

A= nicotine e cigarette

B=patches

C= placebo e cigarette

According to report published verified abstinence;

In A= 21 of 289 that means remaining 289−21=268 are non-abstinence.

In B = 17 of 295 that means remaining 295−17=278 are non-abstinence.

In C = 3 of 73 that means remaining 73−3= 70 are non-abstinence.

	smoking status at 6 months		Total
treatment group	verified abstinence	non abstinence
Nicotine-e cigarette	21	268	289
patches	17	278	295
Placebo-e cigarette	3	70	73

b.

To determine

To organize the cited percent into a similar two-way table.

b.

Expert Solution

Explanation of Solution

Given:

The options are provided in the textbook.

Calculation:

The following is the organized table −

	smoking status at 6 months		Cite percent
treatment group	verified abstinence	non abstinence
Nicotine-e cigarette	21	268	7.2%
patches	17	278	6.11%
Placebo- e cigarette	3	70	4.2%

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Answer 5

Chapter 22, Problem 22.1AYK

a.

To determine

To organize the study findings in the following two-way table of counts. Add the group’s totals to your total.

a.

Expert Solution

Explanation of Solution

Given:

The information is given in the book.

Calculation:

Let the attribute

A= nicotine e cigarette

B=patches

C= placebo e cigarette

According to report published verified abstinence;

In A= 21 of 289 that means remaining 289−21=268 are non-abstinence.

In B = 17 of 295 that means remaining 295−17=278 are non-abstinence.

In C = 3 of 73 that means remaining 73−3= 70 are non-abstinence.

	smoking status at 6 months		Total
treatment group	verified abstinence	non abstinence
Nicotine-e cigarette	21	268	289
patches	17	278	295
Placebo-e cigarette	3	70	73

b.

To determine

To organize the cited percent into a similar two-way table.

b.

Expert Solution

Explanation of Solution

Given:

The options are provided in the textbook.

Calculation:

The following is the organized table −

	smoking status at 6 months		Cite percent
treatment group	verified abstinence	non abstinence
Nicotine-e cigarette	21	268	7.2%
patches	17	278	6.11%
Placebo- e cigarette	3	70	4.2%

Answer 6

Chapter 22, Problem 22.1AYK

a.

To determine

To organize the study findings in the following two-way table of counts. Add the group’s totals to your total.

a.

Expert Solution

Explanation of Solution

Given:

The information is given in the book.

Calculation:

Let the attribute

A= nicotine e cigarette

B=patches

C= placebo e cigarette

According to report published verified abstinence;

In A= 21 of 289 that means remaining 289−21=268 are non-abstinence.

In B = 17 of 295 that means remaining 295−17=278 are non-abstinence.

In C = 3 of 73 that means remaining 73−3= 70 are non-abstinence.

	smoking status at 6 months		Total
treatment group	verified abstinence	non abstinence
Nicotine-e cigarette	21	268	289
patches	17	278	295
Placebo-e cigarette	3	70	73

Answer 7

Chapter 22, Problem 22.1AYK

a.

To determine

To organize the study findings in the following two-way table of counts. Add the group’s totals to your total.

Answer 8

a.

Expert Solution

Explanation of Solution

Given:

The information is given in the book.

Calculation:

Let the attribute

A= nicotine e cigarette

B=patches

C= placebo e cigarette

According to report published verified abstinence;

In A= 21 of 289 that means remaining 289−21=268 are non-abstinence.

In B = 17 of 295 that means remaining 295−17=278 are non-abstinence.

In C = 3 of 73 that means remaining 73−3= 70 are non-abstinence.

	smoking status at 6 months		Total
treatment group	verified abstinence	non abstinence
Nicotine-e cigarette	21	268	289
patches	17	278	295
Placebo-e cigarette	3	70	73

Answer 9

a.

Expert Solution

Answer 10

a.

Expert Solution

Answer 11

Expert Solution

Answer 12

b.

To determine

To organize the cited percent into a similar two-way table.

b.

Expert Solution

Explanation of Solution

Given:

The options are provided in the textbook.

Calculation:

The following is the organized table −

	smoking status at 6 months		Cite percent
treatment group	verified abstinence	non abstinence
Nicotine-e cigarette	21	268	7.2%
patches	17	278	6.11%
Placebo- e cigarette	3	70	4.2%

Answer 13

b.

To determine

To organize the cited percent into a similar two-way table.

Answer 14

b.

Expert Solution

Explanation of Solution

Given:

The options are provided in the textbook.

Calculation:

The following is the organized table −

	smoking status at 6 months		Cite percent
treatment group	verified abstinence	non abstinence
Nicotine-e cigarette	21	268	7.2%
patches	17	278	6.11%
Placebo- e cigarette	3	70	4.2%