GENETICS(LL)-W/CONNECT >CUSTOM<
GENETICS(LL)-W/CONNECT >CUSTOM<
6th Edition
ISBN: 9781260571561
Author: HARTWELL
Publisher: MCG CUSTOM
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Chapter 22, Problem 19P

Canavan disease, caused by homozygosity for a recessive allele, is a severe neurodegenerative syndrome usually resulting in death by the age of 18 months. The frequency of Canavan disease is particularly high in Jewish populations. In an effort to map the gene causing this condition, researchers looked at 10 SNPs (1–10) spaced at roughly 100 kb distances along chromosome 17 in five affected Jewish patients (Cases) and four unaffected Jewish individuals (Controls). In the accompanying table, each row depicts a single haplotype. (Every individual is diploid and therefore has two haplotypes, although only one is shown in the table.) G, C, A, and T represent the actual nucleotide at the indicated SNP location.

Case SNP1 SNP2 SNP3 SNP4 SNP5 SNP6 SNP7 SNP8 SNP9 SNP10
1 G T G T T T C A G T
2 A T G T T T C A G T
3 G T G T T T C A G C
4 A A G T T T C T C C
5 G A G C C T G A C C
Control
6 A A G T T T C A G T
7 G T G G C T G A G T
8 A T C T C G C T C C
9 G T C G T G G A C T
a. Does the disease-causing mutation appear to be in linkage disequilibrium with any of the SNP alleles? If so, which ones?
b. Where is the most likely location for the Canavan disease gene? About how long is the region to which you can ascribe the gene?
c. How many independent mutations of the Canavan gene are suggested by these data?
d. Suppose that individuals 2–9 are Ashkenazic (whose ancestors lived in the Rhine river basin of Germany and France after the Jews were expelled from Judea in 70 A.D.) while individual 1 is Sephardic (a non-Ashkenazic Jew). Would these facts provide any information about the history of the mutations causing Canavan disease?
e. For mapping genes by haplotype association, why is it often helpful to focus on certain subpopulations? Does this strategy have any disadvantages?
f. Human chromosome 17 is an autosome, so each person has two copies of each region along the chromosome. With this in mind, explain the practical difficulty in determining haplotypes. (Hint: Consider heterozygosity.) In light of this difficulty, how could the researchers determine any individual haplotype, such as any of those shown in the table?
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After you feel comfortable with your counting method and identifying cells in the various stages of mitosis, use the four images below of whitefish blastula to count the cells in each stage until you reach 100 total cells, recording your data below in Data Table 1. (You may not need to use all four images. Stop counting when you reach 100 total cells.) After totaling the cells in each stage, calculate the percent of cells in each stage. (Divide total of stage by overall total of 100 and then multiply by 100 to obtain percentage.)   Data Table 1Stage    Totals    PercentInterphase        Mitosis:        Prophase        Metaphase        Anaphase        Telophase        Cytokinesis        Totals    100    100% To find the length of time whitefish blastula cells spend in each stage, multiply the percent (recorded as a decimal, in other words take the percent number and divide by 100) by 24 hours. (Example: If percent is 20%, then Time in Hours = .2 * 24 = 4.8) Record your data in Data…

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