Bundle: Refrigeration And Air Conditioning Technology, 8th + Lab Manual + Lms Integrated For Mindtap Hvac-r, 4 Terms (24 Months) Printed Access Card
8th Edition
ISBN: 9781337087315
Author: John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson
Publisher: Cengage Learning
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Textbook Question
Chapter 22, Problem 18RQ
Briefly explain what is meant by condenser splitting, and list its main advantage.
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Q2. Determine the safety factors for the bracket rod shown in Figure 2 based on both the
distortion-energy theory and the maximum shear theory and compare them.
Given: The material is 2024-T4 aluminum with a yield strength of 47 000 psi.
The rod length /= 6 in. and arm a = 8 in. The rod outside diameter od 1.5 in., id = 1 in, h=2 in.,
t=0.5 in., Load F= 1000 lb.
Assumptions: The load is static and the assembly is at room temperature. Consider
shear due to transverse loading as well as other stresses. (Note: solve in SI units)
wall
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Figure 2
arm
The question has been set up with all the cuts needed to accurately derive expressions for V(x) and M(x). Using the cuts free body diagrams set up below, derive expressions for V(x) and M(x). If you use the method of cuts then validate your answers using calculus or vice versa.
It is required to treat 130 kmol/hr of chloroform-air feed gas mixture that contains
12% chloroform. It is required to remove 93% of chloroform using 150 kmol/hr of
solvent that contains 99.6% water and 0.4% chloroform. The cross sectional area of the
column is 0.8 m². Calculate the column height using the following data; kx'.a = 1.35
(kmol/m³.s (Ax)), and ky'.a = 0.06 (kmol/m³.s (Ay)), kx/ky = 1.35, and the equilibrium
data are:
X 0 0.0133 0.033
y 0 0.01 0.0266
0.049 0.064 0.0747 0.0933 0.1053
0.0433 0.06 0.0733
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0.12
0.14
Chapter 22 Solutions
Bundle: Refrigeration And Air Conditioning Technology, 8th + Lab Manual + Lms Integrated For Mindtap Hvac-r, 4 Terms (24 Months) Printed Access Card
Ch. 22 - Why do some condensers have to be cleaned with...Ch. 22 - The three materials of which condensers are...Ch. 22 - Who should be consulted when condenser cleaning is...Ch. 22 - When is the most heat removed from the refrigerant...Ch. 22 - After heat is absorbed into a condenser medium in...Ch. 22 - A water-cooling tower capacity is governed by what...Ch. 22 - When a standard-efficiency air-cooled condenser is...Ch. 22 - Four methods for controlling head pressure in an...Ch. 22 - The prevailing winds can affect which of the...Ch. 22 - True or False: Air-cooled condensers are much more...
Ch. 22 - The type of condenser that has the lowest...Ch. 22 - Compare the standard conditions of high-efficiency...Ch. 22 - Name two ways in which the heat from an air-cooled...Ch. 22 - Briefly describe what is meant by floating head...Ch. 22 - Explain how to flush impurities from a...Ch. 22 - Explain the basic operation of a combination ORI...Ch. 22 - Name two problems a refrigeration system may have...Ch. 22 - Briefly explain what is meant by condenser...
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- ४ B: Find the numerical solution for the 2D equation below and calculate the temperature values for each grid point shown in Fig. 2 (show all steps). (Do only one trail using following initial values and show the final matrix) [T1] T₂ T3 [T] 1 = [0] 0 0 d dx dx) (ka)+4(ka) = dy -20xy, k = 1 + 0.3 T ge L=3cm, 4x= Ay B.Cs.: at x=0=LT=0°C at y=0-L T=10°C Fig. (2)arrow_forward: +0 العنوان use only Two rods fins) having same dimensions, one made orass (k = 85 Wm K) and the mer of copper (k = 375 W/m K), having of their ends inserted into a furna. At a section 10.5 cm a way from furnace, the temperature of brass rod 120 Find the distance at which the ame temperature would be reached in the per rod ? both ends are ex osed to the same environment. ns 2.05 ۲/۱ ostrararrow_forwardFor the beam show below, draw A.F.D, S.F.D, B.M.D 6 kN/m 1 M B. 3 M Marrow_forward
- 1. Two long rods of the same diameter-one made of brass (k=85w/m.k) and the other made of copper (k=375 w/m.k) have one of their ends inserted into a furnace (as shown in the following figure). Both rods are exposed to the same environment. At a distance of 105 mm from the furnace, the temperature of the brass rod is 120°C. At what distance from the furnace will the same temperature be reached in the copper rod? Furnace 105 mm T₁ Brass rod ⑪ h Too- x2- Ti Copper rodarrow_forward: +0 العنوان use only Two rods fins) having same dimensions, one made orass (k = 85 Wm K) and the mer of copper (k = 375 W/m K), having of their ends inserted into a furna. At a section 10.5 cm a way from furnace, the temperature of brass rod 120 Find the distance at which the ame temperature would be reached in the per rod ? both ends are ex osed to the same environment. ns 2.05 ۲/۱ ostrararrow_forwardمشر on ۲/۱ Two rods (fins) having same dimensions, one made of brass(k=85 m K) and the other of copper (k = 375 W/m K), having one of their ends inserted into a furnace. At a section 10.5 cm a way from the furnace, the temperature brass rod 120°C. Find the distance at which the same temperature would be reached in the copper rod ? both ends are exposed to the same environment. 22.05 ofthearrow_forward
- The composite wall of oven with A= 1m² as in Fig.1 consists of three materials, two of with kA = 20 W/m K and kc = 50 W/m K with thickness, LA=0.3 m, L= 0.15 m and Lc 0.15 m. The inner surface temperature T1=900 K and the outer surface temperature T4 300 K, and an oven air temperature of To=1100 K, h=25 W/m². K. Determine kɛ and the temperatures T2 and T3 also draw the thermal resistance networkarrow_forwardTwo rods (fins) having same dimensions, one made of brass (k = 85 Wm K) and the other of copper (k = 375 W/m K), having one of their ends inserted into a furnace. At a section 10.5 cm a way from the furnace, the temperature of brass rod 120°C. Find the distance at which the same temperature would be reached in the copper rod ? both ends are exposed to the same environment. Ans 22.05arrow_forwardA long wire (k-8 W/m °C.) with ro 5 mm and surface temperature Ts=180°C as shown in Fig.2. Heat is generated in the wire uniformly at a rate of 5 x107 W/m³. If the energy equation is given by: d 11(77) + - =0 k r dr dr Derive an expression for T(r) and determine the temperature at the center of the wire and at r=2 mm. Air Th T KA LA T2 T3 T Fig.1 KB kc 180°C Го Fig.2arrow_forward
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