BSC 1005 PKG-W/MOD. MAST. ACCESS >CI<
BSC 1005 PKG-W/MOD. MAST. ACCESS >CI<
17th Edition
ISBN: 9781269683364
Author: Reece
Publisher: Pearson Custom Publishing
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Chapter 22, Problem 13TYK
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A dissociation curve for hemoglobin and adaptation to living where air is “thin”. The curve showing the percentage of saturation (the amount of O2 bound to hemoglobin) at increasing values of P02. Partial pressure reflects the relative amount of gas in a mixture and is measured in millimeters of mercury 9mmHg). Llamas are native to the Andes Mountains in South America. The partial pressure of O2 in the atmosphere where live is about half of the PO2 at sea level. As a result, the PO2 in the lungs of llamas is about 50mm Hg, whereas that in human lungs at sea level is about 100mm Hg.

Concept introduction:

The hemoglobin pigment act as a vehicle for transport of oxygen in blood. The oxygen-hemoglobin dissociative curve is a curve that shows the percentage of saturated hemoglobin on the y- axis and succeeding oxygen tension on the x-axis. This curve helps in understanding the carrying and release of oxygen by blood.

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After you feel comfortable with your counting method and identifying cells in the various stages of mitosis, use the four images below of whitefish blastula to count the cells in each stage until you reach 100 total cells, recording your data below in Data Table 1. (You may not need to use all four images. Stop counting when you reach 100 total cells.) After totaling the cells in each stage, calculate the percent of cells in each stage. (Divide total of stage by overall total of 100 and then multiply by 100 to obtain percentage.)   Data Table 1Stage    Totals    PercentInterphase        Mitosis:        Prophase        Metaphase        Anaphase        Telophase        Cytokinesis        Totals    100    100% To find the length of time whitefish blastula cells spend in each stage, multiply the percent (recorded as a decimal, in other words take the percent number and divide by 100) by 24 hours. (Example: If percent is 20%, then Time in Hours = .2 * 24 = 4.8) Record your data in Data…
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