Chapter 2.2, Problem 11E

Give the function f(x)=₁ State what it means. Evaluate the one-sided limit: lim +f(x). x-1

Show that lim(x+¹)=e².

Use the Squeeze Theorem to show that lim x² cos(207TX) = 0. X → 0 Illustrate by graphing the functions f(x) = -x², g(x) = x² cos(207x), and h(x) = x² on the same screen. Let f(x) = -x², g(x) = x² cos(207tx), and h(x) = x². Then [0 ✓≤ cos(207TX) ≤ 1 f(x) V ≤ x² cos(207Tx) ≤ ? S . Since lim f(x) = lim_h(x) : = X → 0 X → 0 , by the Squeeze Theorem we have lim g(x) X → 0 =