The percentage of α-amino group of lysine will be protonated at its p I has to be calculated. Concept introduction: The isoelectric point ( p I ) is the pH at which the amount of positive charge and negative charge on an amino acid becomes balanced. The value of p I is depends upon the p K a value of protonated amino group and p K a value of carboxyl group of an amino acid. If the amino acid has no ionizable side chain, then the p I value is the average of p K a value of protonated amino group and p K a value of carboxyl group of that amino acid. If the amino acid has ionizable side chain, then the p I value is the average of p K a value of similarly ionizing groups. The p I value of lysine is 9.87.

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Answer 1

Question

Chapter 21.4, Problem 13P

(a)

Interpretation Introduction

Interpretation:

The percentage of α-amino group of lysine will be protonated at its pI has to be calculated.

Concept introduction:

The isoelectric point (pI) is the pH at which the amount of positive charge and negative charge on an amino acid becomes balanced.

The value of pI is depends upon the pKa value of protonated amino group and pKa value of carboxyl group of an amino acid.

If the amino acid has no ionizable side chain, then the pI value is the average of pKa value of protonated amino group and pKa value of carboxyl group of that amino acid.

If the amino acid has ionizable side chain, then the pI value is the average of pKa value of similarly ionizing groups.

The pI value of lysine is 9.87.

(b)

Interpretation Introduction

Interpretation:

The percentage of β-amino group of lysine will be protonated at its pI has to be calculated.

Concept introduction:

The isoelectric point (pI) is the pH at which the amount of positive charge and negative charge on an amino acid becomes balanced.

The value of pI is depends upon the pKa value of protonated amino group and pKa value of carboxyl group of an amino acid.

If the amino acid has no ionizable side chain, then the pI value is the average of pKa value of protonated amino group and pKa value of carboxyl group of that amino acid.

If the amino acid has ionizable side chain, then the pI value is the average of pKa value of similarly ionizing groups.

The pI value of lysine is 9.87.

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Students have asked these similar questions

Lysine and tryptophan are two amino acids that contain an additional Natom in the R group bonded to the a carbon. While lysine is classified asa basic amino acid because it contains an additional basic N atom,tryptophan is classified as a neutral amino acid. Explain why thisdifference in classification occurs.

Amino Acids and proteins N- H. 1. What is the structure above? RIOIH

Lysine and tryptophan are two amino acids that contain an additional N atom in the R group bonded to the α carbon. While lysine is classified as a basic amino acid because it contains an additional basic N atom, tryptophan is classified as a neutral amino acid. Explain why this difference in classification occurs.

Answer 2

Question

Chapter 21.4, Problem 13P

(a)

Interpretation Introduction

Interpretation:

The percentage of α-amino group of lysine will be protonated at its pI has to be calculated.

Concept introduction:

The isoelectric point (pI) is the pH at which the amount of positive charge and negative charge on an amino acid becomes balanced.

The value of pI is depends upon the pKa value of protonated amino group and pKa value of carboxyl group of an amino acid.

If the amino acid has no ionizable side chain, then the pI value is the average of pKa value of protonated amino group and pKa value of carboxyl group of that amino acid.

If the amino acid has ionizable side chain, then the pI value is the average of pKa value of similarly ionizing groups.

The pI value of lysine is 9.87.

(b)

Interpretation Introduction

Interpretation:

The percentage of β-amino group of lysine will be protonated at its pI has to be calculated.

Concept introduction:

The isoelectric point (pI) is the pH at which the amount of positive charge and negative charge on an amino acid becomes balanced.

The value of pI is depends upon the pKa value of protonated amino group and pKa value of carboxyl group of an amino acid.

If the amino acid has no ionizable side chain, then the pI value is the average of pKa value of protonated amino group and pKa value of carboxyl group of that amino acid.

If the amino acid has ionizable side chain, then the pI value is the average of pKa value of similarly ionizing groups.

The pI value of lysine is 9.87.

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Answer 3

Question

Chapter 21.4, Problem 13P

(a)

Interpretation Introduction

Interpretation:

The percentage of α-amino group of lysine will be protonated at its pI has to be calculated.

Concept introduction:

The isoelectric point (pI) is the pH at which the amount of positive charge and negative charge on an amino acid becomes balanced.

The value of pI is depends upon the pKa value of protonated amino group and pKa value of carboxyl group of an amino acid.

If the amino acid has no ionizable side chain, then the pI value is the average of pKa value of protonated amino group and pKa value of carboxyl group of that amino acid.

If the amino acid has ionizable side chain, then the pI value is the average of pKa value of similarly ionizing groups.

The pI value of lysine is 9.87.

(b)

Interpretation Introduction

Interpretation:

The percentage of β-amino group of lysine will be protonated at its pI has to be calculated.

Concept introduction:

The isoelectric point (pI) is the pH at which the amount of positive charge and negative charge on an amino acid becomes balanced.

The value of pI is depends upon the pKa value of protonated amino group and pKa value of carboxyl group of an amino acid.

If the amino acid has no ionizable side chain, then the pI value is the average of pKa value of protonated amino group and pKa value of carboxyl group of that amino acid.

If the amino acid has ionizable side chain, then the pI value is the average of pKa value of similarly ionizing groups.

The pI value of lysine is 9.87.

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Answer 4

Question

Chapter 21.4, Problem 13P

(a)

Interpretation Introduction

Interpretation:

The percentage of α-amino group of lysine will be protonated at its pI has to be calculated.

Concept introduction:

The isoelectric point (pI) is the pH at which the amount of positive charge and negative charge on an amino acid becomes balanced.

The value of pI is depends upon the pKa value of protonated amino group and pKa value of carboxyl group of an amino acid.

If the amino acid has no ionizable side chain, then the pI value is the average of pKa value of protonated amino group and pKa value of carboxyl group of that amino acid.

If the amino acid has ionizable side chain, then the pI value is the average of pKa value of similarly ionizing groups.

The pI value of lysine is 9.87.

(b)

Interpretation Introduction

Interpretation:

The percentage of β-amino group of lysine will be protonated at its pI has to be calculated.

Concept introduction:

The isoelectric point (pI) is the pH at which the amount of positive charge and negative charge on an amino acid becomes balanced.

The value of pI is depends upon the pKa value of protonated amino group and pKa value of carboxyl group of an amino acid.

If the amino acid has no ionizable side chain, then the pI value is the average of pKa value of protonated amino group and pKa value of carboxyl group of that amino acid.

If the amino acid has ionizable side chain, then the pI value is the average of pKa value of similarly ionizing groups.

The pI value of lysine is 9.87.

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Answer 5

Chapter 21.4, Problem 13P

(a)

Interpretation Introduction

Interpretation:

The percentage of α-amino group of lysine will be protonated at its pI has to be calculated.

Concept introduction:

The isoelectric point (pI) is the pH at which the amount of positive charge and negative charge on an amino acid becomes balanced.

The value of pI is depends upon the pKa value of protonated amino group and pKa value of carboxyl group of an amino acid.

If the amino acid has no ionizable side chain, then the pI value is the average of pKa value of protonated amino group and pKa value of carboxyl group of that amino acid.

If the amino acid has ionizable side chain, then the pI value is the average of pKa value of similarly ionizing groups.

The pI value of lysine is 9.87.

(b)

Interpretation Introduction

Interpretation:

The percentage of β-amino group of lysine will be protonated at its pI has to be calculated.

Concept introduction:

The isoelectric point (pI) is the pH at which the amount of positive charge and negative charge on an amino acid becomes balanced.

The value of pI is depends upon the pKa value of protonated amino group and pKa value of carboxyl group of an amino acid.

If the amino acid has no ionizable side chain, then the pI value is the average of pKa value of protonated amino group and pKa value of carboxyl group of that amino acid.

If the amino acid has ionizable side chain, then the pI value is the average of pKa value of similarly ionizing groups.

The pI value of lysine is 9.87.

Answer 6

Chapter 21.4, Problem 13P

(a)

Interpretation Introduction

Interpretation:

The percentage of α-amino group of lysine will be protonated at its pI has to be calculated.

Concept introduction:

The isoelectric point (pI) is the pH at which the amount of positive charge and negative charge on an amino acid becomes balanced.

The value of pI is depends upon the pKa value of protonated amino group and pKa value of carboxyl group of an amino acid.

If the amino acid has no ionizable side chain, then the pI value is the average of pKa value of protonated amino group and pKa value of carboxyl group of that amino acid.

If the amino acid has ionizable side chain, then the pI value is the average of pKa value of similarly ionizing groups.

The pI value of lysine is 9.87.

Answer 7

Chapter 21.4, Problem 13P

(a)

Interpretation Introduction

Interpretation:

The percentage of α-amino group of lysine will be protonated at its pI has to be calculated.

Concept introduction:

The isoelectric point (pI) is the pH at which the amount of positive charge and negative charge on an amino acid becomes balanced.

The value of pI is depends upon the pKa value of protonated amino group and pKa value of carboxyl group of an amino acid.

If the amino acid has no ionizable side chain, then the pI value is the average of pKa value of protonated amino group and pKa value of carboxyl group of that amino acid.

If the amino acid has ionizable side chain, then the pI value is the average of pKa value of similarly ionizing groups.

The pI value of lysine is 9.87.

Answer 8

(b)

Interpretation Introduction

Interpretation:

The percentage of β-amino group of lysine will be protonated at its pI has to be calculated.

Concept introduction:

The isoelectric point (pI) is the pH at which the amount of positive charge and negative charge on an amino acid becomes balanced.

The value of pI is depends upon the pKa value of protonated amino group and pKa value of carboxyl group of an amino acid.

If the amino acid has no ionizable side chain, then the pI value is the average of pKa value of protonated amino group and pKa value of carboxyl group of that amino acid.

If the amino acid has ionizable side chain, then the pI value is the average of pKa value of similarly ionizing groups.

The pI value of lysine is 9.87.

Answer 9

(b)

Interpretation Introduction

Interpretation:

The percentage of β-amino group of lysine will be protonated at its pI has to be calculated.

Concept introduction:

The isoelectric point (pI) is the pH at which the amount of positive charge and negative charge on an amino acid becomes balanced.

The value of pI is depends upon the pKa value of protonated amino group and pKa value of carboxyl group of an amino acid.

If the amino acid has no ionizable side chain, then the pI value is the average of pKa value of protonated amino group and pKa value of carboxyl group of that amino acid.

If the amino acid has ionizable side chain, then the pI value is the average of pKa value of similarly ionizing groups.

The pI value of lysine is 9.87.

Answer 10

Expert Solution & Answer

Answer 11

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Answer 12

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Answer 13

Ch. 21.1 - a. Explain why, when the imidazole ring of...Ch. 21.2 - a. Which isomer(R)-alanine or (S)-alanineis...Ch. 21.2 - Prob. 4P Ch. 21.3 - Prob. 5P Ch. 21.3 - Prob. 6P Ch. 21.3 - Draw the predominant form for glutamate in a...Ch. 21.3 - a. Why is the pKa of the glutamate side chain...Ch. 21.4 - Calculate the pI of each of the following amino...Ch. 21.4 - a. Which amino acid has the lowest pI value? b....Ch. 21.4 - Prob. 12P

Solution Summary: The author explains that the isoelectric point is the pH at which the amount of positive and negative charge on an amino acid becomes balanced.

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Chapter 21 Solutions