Chapter 21.1, Problem 21.1.2PE

Interpretation Introduction

Interpretation: The element, the alpha-emission of which leads to the formation of lead $-208$$\left({}_{\text{82}}^{\text{208}}\text{Pb}\right)$ is to be determined.

Concept introduction: In alpha emission, the atomic number of a nucleus that is undergoing alpha decay is reduced by two and mass number is reduced by four.

To determine: The element, the alpha-emission of which leads to the formation of lead $-208$$\left({}_{\text{82}}^{\text{208}}\text{Pb}\right)$ .