Chemistry: The Central Science (14th Edition)
14th Edition
ISBN: 9780134554563
Author: Brown
Publisher: PEARSON
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Question
Chapter 21, Problem 4E
(a)
Interpretation Introduction
To determine: The identities of the four particles involved in the reaction depicted.
(b)
Interpretation Introduction
To determine: The transformation represented in the figure 1 using condensed notation.
(c)
Interpretation Introduction
To determine: The product formed is stable or radioactive on the bases of its atomic number and mass number.
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A solution contains 0.097 M Ce3+, 1.55x10-3 M Ce4+, 1.55x10-3 M Mn2+, 0.097 M MnO4-, and 1.00 M HClO4 (F= 9.649 x 104 C/mol).
a) Write a balanced net reaction that can occur between species in this solution.
b) Calculate deltaG0 and K for the reaction.
c) Calculate E and deltaG for the conditions given.
Ce4+ + e- = Ce3+ E0= 1.70 V
MnO4- + 8H+ + 5e- = Mn2+ + 4H2O E0= 1.507 V
1. Provide a step-by-step mechanism for formation of ALL STEREOISOMERS in
the following reaction.
Na HCO3 (Sodium bicarbonate, baking soda) is not soluble in CH2Cl2. The powder is
a weak base used to neutralize strong acid (pKa < 0) produced by the reaction.
Redraw the product to show the configuration(s) that form at C-2 and C-4.
Br2
OH
CH2Cl2
Na* HCO3
Br
HO
OH
+ Na Br +
2. Specify the solvent and reagent(s) required to carry out each of the following FGI. If
two reagent sets must be used for the FGI, specify the solvent and reagent(s) for each
reagent set. If a reaction cannot be carried out with reagents (sets)
class, write NP (not possible) in the solvent box for reagent set #1.
Use the letter abbreviation for each solvent; use a number abbreviation for reagent(s).
Solvents: CH2Cl2 (A);
H₂O (B);
Reagents:
HBr (1);
R₂BH (6);
H2SO4 (2);
CH3OH (C);
Br₂ (3);
CH3CO₂H (D)
NaHCO3 (4);
Hg(OAc)2 (5);
H₂O2/HO (7);
NaBH4 (8)
Reagent Set #1
Reagent Set #2
FGI
+ enant
OH
Solvent Reagent(s) Solvent Reagent(s)
Chapter 21 Solutions
Chemistry: The Central Science (14th Edition)
Ch. 21.1 - Prob. 21.1.1PECh. 21.1 - Prob. 21.1.2PECh. 21.1 - Prob. 21.2.1PECh. 21.1 - Prob. 21.2.2PECh. 21.2 - Prob. 21.3.1PECh. 21.2 - Prob. 21.3.2PECh. 21.3 - Prob. 21.4.1PECh. 21.3 - Prob. 21.4.2PECh. 21.4 - Prob. 21.5.1PECh. 21.4 - Prob. 21.5.2PE
Ch. 21.4 - Prob. 21.6.1PECh. 21.4 - Prob. 21.6.2PECh. 21.4 - Prob. 21.7.1PECh. 21.4 - Prob. 21.7.2PECh. 21.6 - Prob. 21.8.1PECh. 21.6 - Prob. 21.8.2PECh. 21 - Prob. 1DECh. 21 - Prob. 1ECh. 21 - Prob. 2ECh. 21 - Prob. 3ECh. 21 - Prob. 4ECh. 21 - Prob. 5ECh. 21 - Prob. 6ECh. 21 - Prob. 7ECh. 21 - Prob. 8ECh. 21 - Prob. 9ECh. 21 - Prob. 10ECh. 21 - Prob. 11ECh. 21 - Prob. 12ECh. 21 - Prob. 13ECh. 21 - Prob. 14ECh. 21 - Prob. 15ECh. 21 - Prob. 16ECh. 21 - Prob. 17ECh. 21 - Prob. 18ECh. 21 - Prob. 19ECh. 21 - Prob. 20ECh. 21 - Prob. 21ECh. 21 - Prob. 22ECh. 21 - Prob. 23ECh. 21 - Prob. 24ECh. 21 - Prob. 25ECh. 21 - Prob. 26ECh. 21 - Prob. 27ECh. 21 - Prob. 28ECh. 21 - Prob. 29ECh. 21 - Prob. 30ECh. 21 - Prob. 31ECh. 21 - Prob. 32ECh. 21 - Prob. 33ECh. 21 - Prob. 34ECh. 21 - Prob. 35ECh. 21 - Prob. 36ECh. 21 - Prob. 37ECh. 21 - Prob. 38ECh. 21 - Prob. 39ECh. 21 - Prob. 40ECh. 21 - Prob. 41ECh. 21 - Prob. 42ECh. 21 - Prob. 43ECh. 21 - Prob. 44ECh. 21 - Prob. 45ECh. 21 - Prob. 46ECh. 21 - Prob. 47ECh. 21 - Prob. 48ECh. 21 - The atomic masses of hydrogen-2 (deuterium),...Ch. 21 - Prob. 50ECh. 21 - Prob. 51ECh. 21 - Prob. 52ECh. 21 - Prob. 53ECh. 21 - Prob. 54ECh. 21 - Prob. 55ECh. 21 - Prob. 56ECh. 21 - Prob. 57ECh. 21 - Prob. 58ECh. 21 - Prob. 59ECh. 21 - Prob. 60ECh. 21 - Prob. 61ECh. 21 - Prob. 62ECh. 21 - Prob. 63ECh. 21 - Prob. 64ECh. 21 - Prob. 65ECh. 21 - Prob. 66ECh. 21 - Prob. 67ECh. 21 - Prob. 68ECh. 21 - Prob. 69ECh. 21 - Prob. 70ECh. 21 - Prob. 71AECh. 21 - Prob. 72AECh. 21 - Prob. 73AECh. 21 - Prob. 74AECh. 21 - Prob. 75AECh. 21 - Prob. 76AECh. 21 - Prob. 77AECh. 21 - Prob. 78AECh. 21 - Prob. 79AECh. 21 - Prob. 80AECh. 21 - Prob. 81AECh. 21 - Prob. 82AECh. 21 - Prob. 83AECh. 21 - Prob. 84AECh. 21 - Prob. 85AECh. 21 - Prob. 86AECh. 21 - Prob. 87IECh. 21 - Prob. 88IECh. 21 - Prob. 89IECh. 21 - Prob. 90IECh. 21 - Prob. 91IECh. 21 - Prob. 92IE
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