ORGANIC CHEMISTRY-ETEXT REG ACCESS
12th Edition
ISBN: 9781119308362
Author: Solomons
Publisher: WILEY
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Question
Chapter 21, Problem 7PP
Interpretation Introduction
Interpretation:
Products formed in the Stille coupling reactions for given compounds are to be determined.
Concept introduction:
Stille coupling is a reaction in which organotin compounds are coupled with organic halides. Here, organotin compounds are used as coupling agents.
Stille coupling is a carbon–carbon bond formation reaction between aryl halide and organotin compound.
The Stille coupling reaction takes place in presence of palladium catalysts. This reaction is commonly used for
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יווי
10
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3.5
3
2.5
2
1.5
1
[ppm]
3.5
3
2.5
2
1.5
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6 [ppm]
1
1.5
-2.5
3.5
2H2S(g)+3O2(g)→2SO2(g)+2H2O(g)
A 1.2mol sample of H2S(g) is combined with excess O2(g), and the reaction goes to completion.
Question
Which of the following predicts the theoretical yield of SO2(g) from the reaction?
Responses
1.2 g
Answer A: 1.2 grams
A
41 g
Answer B: 41 grams
B
77 g
Answer C: 77 grams
C
154 g
Answer D: 154 grams
D
Part VII. Below are the 'HNMR, 13 C-NMR, COSY 2D- NMR, and HSQC 2D-NMR (similar with HETCOR but axes are reversed) spectra of an
organic compound with molecular formula C6H1003 - Assign chemical shift values to the H and c atoms of the
compound. Find the structure. Show complete solutions.
Predicted 1H NMR Spectrum
4.7 4.6 4.5 4.4 4.3 4.2 4.1 4.0 3.9 3.8 3.7 3.6 3.5 3.4 3.3 3.2 3.1 3.0 2.9 2.8 2.7 2.6 2.5 2.4 2.3 2.2 2.1 2.0 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1
f1 (ppm)
Predicted 13C NMR Spectrum
100
f1 (ppm)
30
220 210 200 190 180
170
160 150 140 130 120
110
90
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70
-26
60
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46
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115
10
1.0 0.9 0.8
0
-10
Chapter 21 Solutions
ORGANIC CHEMISTRY-ETEXT REG ACCESS
Ch. 21 - PRACTICE PROBLEM 21.1
For each of the following...Ch. 21 - Prob. 2PPCh. 21 - PRACTICE PROBLEM 21.3 What product would you...Ch. 21 - Prob. 4PPCh. 21 - PRACTICE PROBLEM 21.5 What is the product of the...Ch. 21 - Prob. 6PPCh. 21 - Prob. 7PPCh. 21 - Prob. 8PPCh. 21 - Prob. 9PPCh. 21 - Prob. 10PP
Ch. 21 - Prob. 11PPCh. 21 - Practice Problem 21.12 What products would form...Ch. 21 - Prob. 13PCh. 21 - Prob. 14PCh. 21 - How would you synthesize each of the following...Ch. 21 - Prob. 16PCh. 21 - Predict the product(s) for each of the following...Ch. 21 - Prob. 18PCh. 21 - Prob. 19PCh. 21 - Prob. 20PCh. 21 - Prob. 21PCh. 21 - 21.22 Write a mechanism that can account for the...Ch. 21 - Prob. 23PCh. 21 - Prob. 24PCh. 21 - Prob. 25PCh. 21 - 21.26 In 1985, T. Katz (Columbia University)...Ch. 21 - When the following molecule was exposed to the...Ch. 21 - During the course of the following Stille...Ch. 21 - 1. In “The Chemistry of... Complex Cross...Ch. 21 - Prob. 2LGP
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- Nonearrow_forward4. Draw and label all possible isomers for [M(py)3(DMSO)2(CI)] (py = pyridine, DMSO dimethylsulfoxide).arrow_forwardThe emission data in cps displayed in Table 1 is reported to two decimal places by the chemist. However, the instrument output is shown in Table 2. Table 2. Iron emission from ICP-AES Sample Blank Standard Emission, cps 579.503252562 9308340.13122 Unknown Sample 343.232365741 Did the chemist make the correct choice in how they choose to display the data up in Table 1? Choose the best explanation from the choices below. No. Since the instrument calculates 12 digits for all values, they should all be kept and not truncated. Doing so would eliminate significant information. No. Since the instrument calculates 5 decimal places for the standard, all of the values should be limited to the same number. The other decimal places are not significant for the blank and unknown sample. Yes. The way Saman made the standards was limited by the 250-mL volumetric flask. This glassware can report values to 2 decimal places, and this establishes our number of significant figures. Yes. Instrumental data…arrow_forward
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