ORGANIC CHEMISTRY (LL)-W/WILEYPLUS
ORGANIC CHEMISTRY (LL)-W/WILEYPLUS
4th Edition
ISBN: 9781119659556
Author: Klein
Publisher: WILEY
Question
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Chapter 21, Problem 61PP

(a)

Interpretation Introduction

Interpretation:

The aldol condensation product for the given molecule should be identified.

Concept introduction:

Aldol condensation reaction is where the aldol addition product undergoes dehydration to give a conjugated enone. In organic chemistry condensation reaction means loss of small molecules. For aldol condensation reaction to take place the starting material should have two α hydrogens in the same carbon atom. The driving force for aldol condensation reaction is the formation of conjugated system. The steps involved in aldol condensation reaction are,

  • Deprotonation of α carbon
  • Attach of enolate ion with the aldehyde (nucleophilic attack)
  • Protonation of the alkoxide ion to give aldol product
  • Dehydration of the aldol addition product to form conjugated enone (aldol condensation product)

Please note that aldol condensation product is formed at higher temperature.

Note: Simple way to enter aldol condensation product is to remove the two α hydrogens from one carbonyl molecule and oxygen from another carbonyl molecule.  Form a double bond between the carbon atoms as shown in scheme below,

ORGANIC CHEMISTRY (LL)-W/WILEYPLUS, Chapter 21, Problem 61PP , additional homework tip  1

To draw : The aldol condensation product formed when the given compound (ketone) is heated in presence of base.

(b)

Interpretation Introduction

Interpretation:

The aldol condensation product for the given molecule should be identified.

Concept introduction:

Aldol condensation reaction is where the aldol addition product undergoes dehydration to give a conjugated enone. In organic chemistry condensation reaction means loss of small molecules. For aldol condensation reaction to take place the starting material should have two α hydrogens in the same carbon atom. The driving force for aldol condensation reaction is the formation of conjugated system. The steps involved in aldol condensation reaction are,

  • Deprotonation of α carbon
  • Attach of enolate ion with the aldehyde (nucleophilic attack)
  • Protonation of the alkoxide ion to give aldol product
  • Dehydration of the aldol addition product to form conjugated enone (aldol condensation product)

Please note that aldol condensation product is formed at higher temperature.

Note: Simple way to enter aldol condensation product is to remove the two α hydrogens from one carbonyl molecule and oxygen from another carbonyl molecule.  Form a double bond between the carbon atoms as shown in scheme below,

ORGANIC CHEMISTRY (LL)-W/WILEYPLUS, Chapter 21, Problem 61PP , additional homework tip  2

To draw : The aldol condensation product formed when the given compound (aldehyde) is heated in presence of base.

(c)

Interpretation Introduction

Interpretation:

The aldol condensation product for the given molecule should be identified.

Concept introduction:

Aldol condensation reaction is where the aldol addition product undergoes dehydration to give a conjugated enone. In organic chemistry condensation reaction means loss of small molecules. For aldol condensation reaction to take place the starting material should have two α hydrogens in the same carbon atom. The driving force for aldol condensation reaction is the formation of conjugated system. The steps involved in aldol condensation reaction are,

  • Deprotonation of α carbon
  • Attach of enolate ion with the aldehyde (nucleophilic attack)
  • Protonation of the alkoxide ion to give aldol product
  • Dehydration of the aldol addition product to form conjugated enone (aldol condensation product)

Please note that aldol condensation product is formed at higher temperature.

Note: Simple way to enter aldol condensation product is to remove the two α hydrogens from one carbonyl molecule and oxygen from another carbonyl molecule.  Form a double bond between the carbon atoms as shown in scheme below,

ORGANIC CHEMISTRY (LL)-W/WILEYPLUS, Chapter 21, Problem 61PP , additional homework tip  3

To draw : The aldol condensation product formed when the compound given aldehyde is heated in presence of base.

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Chapter 21 Solutions

ORGANIC CHEMISTRY (LL)-W/WILEYPLUS

Ch. 21.2 - Prob. 10CCCh. 21.2 - Prob. 11CCCh. 21.2 - Prob. 12CCCh. 21.2 - Prob. 13CCCh. 21.3 - Prob. 2LTSCh. 21.3 - Prob. 14PTSCh. 21.3 - Prob. 15PTSCh. 21.3 - Prob. 3LTSCh. 21.3 - Prob. 4LTSCh. 21.3 - Prob. 19PTSCh. 21.3 - Prob. 21CCCh. 21.3 - Prob. 22CCCh. 21.3 - Prob. 23CCCh. 21.4 - Prob. 24CCCh. 21.4 - Prob. 25CCCh. 21.4 - Prob. 26CCCh. 21.4 - Prob. 27CCCh. 21.4 - Prob. 28CCCh. 21.5 - Prob. 29CCCh. 21.5 - Prob. 30CCCh. 21.5 - Prob. 5LTSCh. 21.5 - Prob. 31PTSCh. 21.5 - Prob. 6LTSCh. 21.5 - Prob. 33PTSCh. 21.5 - Prob. 34ATSCh. 21.6 - Prob. 35CCCh. 21.6 - Prob. 36CCCh. 21.6 - Prob. 37CCCh. 21.6 - Prob. 7LTSCh. 21.6 - Prob. 38PTSCh. 21.7 - Prob. 8LTSCh. 21.7 - Prob. 42PTSCh. 21.7 - Prob. 43PTSCh. 21 - Prob. 47PPCh. 21 - Prob. 48PPCh. 21 - Prob. 49PPCh. 21 - Prob. 50PPCh. 21 - Prob. 51PPCh. 21 - Prob. 52PPCh. 21 - Prob. 53PPCh. 21 - Prob. 54PPCh. 21 - Prob. 55PPCh. 21 - Prob. 56PPCh. 21 - Prob. 57PPCh. 21 - Prob. 58PPCh. 21 - Prob. 59PPCh. 21 - Prob. 60PPCh. 21 - Prob. 61PPCh. 21 - Prob. 62PPCh. 21 - Prob. 63PPCh. 21 - Prob. 64PPCh. 21 - Prob. 65PPCh. 21 - Prob. 66PPCh. 21 - Prob. 67PPCh. 21 - Prob. 68PPCh. 21 - Prob. 69PPCh. 21 - Prob. 70PPCh. 21 - Prob. 71PPCh. 21 - Prob. 72PPCh. 21 - Prob. 73PPCh. 21 - Prob. 74PPCh. 21 - Prob. 75PPCh. 21 - Prob. 76PPCh. 21 - Prob. 77PPCh. 21 - Prob. 78PPCh. 21 - Prob. 79PPCh. 21 - Prob. 80PPCh. 21 - Prob. 81PPCh. 21 - Prob. 82PPCh. 21 - Prob. 83PPCh. 21 - Prob. 84PPCh. 21 - Prob. 85PPCh. 21 - Prob. 86PPCh. 21 - Prob. 87PPCh. 21 - Prob. 88PPCh. 21 - Prob. 97IPCh. 21 - Prob. 98IPCh. 21 - Prob. 99IPCh. 21 - Prob. 100IPCh. 21 - Prob. 101IPCh. 21 - Prob. 107IPCh. 21 - Prob. 108IPCh. 21 - Prob. 109IP
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