Explanation Given information: The Ricker equation: x t + 1 = c x t e − x t was introduced in Exercise 1.6.32. x 0 = 0.4 , c = 3 Calculation: Given difference equation x t + 1 = c x t e − x t Where x 0 = 0.4 , c = 3 , Let us calculate some terms of the sequence. x 0 = 0.3 x 1 = 3 x 0 e − x 0 = 3 ( 0.3 ) e − 0.3 ≈ 0.6667 x 2 = 3 x 1 e − x 1 ≈ 3 ( 0.6667 ) e − 0.6667 ≈ 1.0269 x 3 = 3 x 2 e − x 2 ≈ 3 ( 1.0269 ) e − 1.0269 ≈ 1.1032 x 4 = 3 x 3 e − x 3 ≈ 3 ( 1.1032 ) e − 1.1032 ≈ 1.0981 x 5 = 3 x 4 e − x 4 ≈ 3 ( 1.0981 ) e − 1.0981 ≈ 1.0986 x 6 = 3 x 5 e − x 5 ≈ 3 ( 1.0986 ) e − 1

15th Edition

ISBN: 9781305420878

Author: Stewart

Publisher: CENGAGE L

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Sequence and Series

A sequence is defined as a collection of things. Series is defined to sum the things one by one in the sequence. It was invented by German mathematician Carl Friedrich Gauss.

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Chapter 2.1, Problem 56E

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To plot: Plot enough terms of the Ricker equation to see how the terms behave and estimate the limit and then, assuming the limit exists, calculate its exact value. If not, describe the behavior of the terms

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Chapter 2.1, Problem 55E

Chapter 2.1, Problem 57E

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Chapter 2 Solutions

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To plot: Plot enough terms of the Ricker equation to see how the terms behave and estimate the limit and then, assuming the limit exists, calculate its exact value. If not, describe the behavior of the terms

Solution Summary: The author explains the Ricker equation, which was introduced in Exercise 1.6.32.

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To plot: Plot enough terms of the Ricker equation to see how the terms behave and estimate the limit and then, assuming the limit exists, calculate its exact value. If not, describe the behavior of the terms

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Chapter 2 Solutions