Explanation Given information: x 0 = 0.4 , c = 3.5 Calculation: Given difference equation x t + 1 = c x t ( 1 − x t ) Where x 0 = 0.4 , c = 3.5 . Let us calculate some terms of the sequence. x 0 = 0.4 x 1 = ( 3.5 ) ⋅ x 0 ( 1 − x 0 ) = ( 3.5 ) ⋅ ( 0.4 ) ( 1 − 0.4 ) = 0.8400 x 2 = ( 3.5 ) ⋅ x 1 ( 1 − x 1 ) = ( 3.5 ) ⋅ ( 0.8400 ) ( 1 − 0.8400 ) = 0.4704 x 3 = ( 3.5 ) ⋅ x 2 ( 1 − x 2 ) = ( 3.5 ) ⋅ ( 0.4704 ) ( 1 − 0.4704 ) ≈ 0.8719 x 4 = ( 3.5 ) ⋅ x 3 ( 1 − x 3 ) ≈ ( 3.5 ) ⋅ ( 0.8719 ) ( 1 − 0.8719 ) ≈ 0.3908 x 5 = ( 3.5 ) ⋅ x 4 ( 1 − x 4 ) ≈ ( 3.5 ) ⋅ ( 0

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ISBN: 9781305420878

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Chapter 2.1, Problem 50E

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To plot: xt+1=cxt(1−xt) and calculate its exact value.

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Chapter 2.1, Problem 49E

Chapter 2.1, Problem 51E

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Chapter 2 Solutions

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To plot: x t + 1 = c x t ( 1 − x t ) and calculate its exact value.

Solution Summary: The author explains that the sequence is oscillatory and does not appear to be convergent.

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To plot: xt+1=cxt(1−xt) and calculate its exact value.

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Chapter 2 Solutions