EBK INTRODUCTORY CHEMISTRY
8th Edition
ISBN: 9780100480483
Author: DECOSTE
Publisher: YUZU
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Chapter 21, Problem 50QAP
Interpretation Introduction
Interpretation:
Interpret and define micelle and determine the formation of micelles during the cleansing action of soap.
Concept Introduction:
Grease is a hydrophobic molecule having no effect of water on it, thus can be removed with the help of soap or detergent.
Soap is formed from the potassium hydroxide or sodium hydroxide with triglyceride while triglycerides consists of glycerol and 3 fatty acid. Thus, soups are sodium or potassium salt of long chain fatty acids.
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Chapter 21 Solutions
EBK INTRODUCTORY CHEMISTRY
Ch. 21.9 - Prob. 1CTCh. 21 - Differentiate among primary, secondary, and...Ch. 21 - Prob. 2ALQCh. 21 - Prob. 3ALQCh. 21 - Prob. 4ALQCh. 21 - Prob. 5ALQCh. 21 - Prob. 6ALQCh. 21 - Prob. 7ALQCh. 21 - Prob. 8ALQCh. 21 - Prob. 9ALQ
Ch. 21 - Prob. 10ALQCh. 21 - Prob. 11ALQCh. 21 - Prob. 1QAPCh. 21 - Prob. 2QAPCh. 21 - Prob. 3QAPCh. 21 - Prob. 4QAPCh. 21 - Prob. 5QAPCh. 21 - Prob. 6QAPCh. 21 - Prob. 7QAPCh. 21 - Prob. 8QAPCh. 21 - Prob. 9QAPCh. 21 - . How many unique amino acid sequences are...Ch. 21 - Prob. 11QAPCh. 21 - Prob. 12QAPCh. 21 - Prob. 13QAPCh. 21 - Prob. 14QAPCh. 21 - Prob. 15QAPCh. 21 - Prob. 16QAPCh. 21 - Prob. 17QAPCh. 21 - Prob. 18QAPCh. 21 - Prob. 19QAPCh. 21 - . What protein is responsible for the transport of...Ch. 21 - Prob. 21QAPCh. 21 - Prob. 22QAPCh. 21 - Prob. 23QAPCh. 21 - Prob. 24QAPCh. 21 - . How does the efficiency of an enzyme compare...Ch. 21 - Prob. 26QAPCh. 21 - Prob. 27QAPCh. 21 - . Describe the lock-and-key model for enzymes. Why...Ch. 21 - Prob. 29QAPCh. 21 - Prob. 30QAPCh. 21 - Prob. 31QAPCh. 21 - Prob. 32QAPCh. 21 - Prob. 33QAPCh. 21 - Prob. 34QAPCh. 21 - Prob. 35QAPCh. 21 - Prob. 36QAPCh. 21 - Prob. 37QAPCh. 21 - Prob. 38QAPCh. 21 - Prob. 39QAPCh. 21 - Prob. 40QAPCh. 21 - Prob. 41QAPCh. 21 - Prob. 42QAPCh. 21 - Prob. 43QAPCh. 21 - Prob. 44QAPCh. 21 - Prob. 45QAPCh. 21 - Prob. 46QAPCh. 21 - Prob. 47QAPCh. 21 - Prob. 48QAPCh. 21 - Prob. 49QAPCh. 21 - Prob. 50QAPCh. 21 - . What is a steroid? What basic ring structure 15...Ch. 21 - Prob. 52QAPCh. 21 - Prob. 53QAPCh. 21 - Prob. 54QAPCh. 21 - Prob. 55APCh. 21 - Prob. 56APCh. 21 - Prob. 57APCh. 21 - Prob. 58APCh. 21 - Prob. 59APCh. 21 - Prob. 60APCh. 21 - Prob. 61APCh. 21 - Prob. 62APCh. 21 - Prob. 63APCh. 21 - Prob. 64APCh. 21 - Prob. 65APCh. 21 - Prob. 66APCh. 21 - Prob. 67APCh. 21 - Prob. 68APCh. 21 - Prob. 69APCh. 21 - Prob. 70APCh. 21 - Prob. 71APCh. 21 - Prob. 72APCh. 21 - Prob. 73APCh. 21 - Prob. 74APCh. 21 - Prob. 75APCh. 21 - Prob. 76APCh. 21 - Prob. 77APCh. 21 - Prob. 78APCh. 21 - Prob. 79APCh. 21 - Prob. 80APCh. 21 - Prob. 81APCh. 21 - Prob. 82APCh. 21 - Prob. 83APCh. 21 - Prob. 84APCh. 21 - Prob. 85APCh. 21 - Prob. 86APCh. 21 - Prob. 87APCh. 21 - Prob. 88APCh. 21 - Prob. 89APCh. 21 - Prob. 90APCh. 21 - Prob. 91APCh. 21 - Prob. 92APCh. 21 - Prob. 93APCh. 21 - Prob. 94APCh. 21 - Prob. 95APCh. 21 - Prob. 96APCh. 21 - . How many possible primary structures exist for a...Ch. 21 - Prob. 98APCh. 21 - Prob. 99APCh. 21 - Prob. 100APCh. 21 - Prob. 101APCh. 21 - Prob. 102APCh. 21 - Prob. 103APCh. 21 - Prob. 104APCh. 21 - Prob. 105APCh. 21 - Prob. 106AP
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- Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction. For the decomposition reaction of N2O5(g): 2 N2O5(g) · 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 -> NO2 + NO3_(K1) NO2 + NO3 →> N2O5 (k-1) → NO2 + NO3 → NO2 + O2 + NO (K2) NO + N2O5 → NO2 + NO2 + NO2 (K3) Give the expression for the acceptable rate. (A). d[N₂O] dt = -1 2k,k₂[N205] k₁+k₂ d[N₂O5] (B). dt =-k₁[N₂O₂] + k₁[NO2][NO3] - k₂[NO2]³ (C). d[N₂O] dt =-k₁[N₂O] + k₁[N205] - K3 [NO] [N205] (D). d[N2O5] =-k₁[NO] - K3[NO] [N₂05] dtarrow_forwardA 0.10 M solution of acetic acid (CH3COOH, Ka = 1.8 x 10^-5) is titrated with a 0.0250 M solution of magnesium hydroxide (Mg(OH)2). If 10.0 mL of the acid solution is titrated with 20.0 mL of the base solution, what is the pH of the resulting solution?arrow_forwardFor the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3) → Give the expression for the acceptable rate. → → (A). d[N205] dt == 2k,k₂[N₂O₂] k₁+k₁₂ (B). d[N2O5] =-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³ dt (C). d[N2O5] =-k₁[N₂O] + k [NO] - k₂[NO] [NO] d[N2O5] (D). = dt = -k₁[N2O5] - k¸[NO][N₂05] dt Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.arrow_forward
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