Explanation Given information: x 0 = 0.4 , c = 3.5 Calculation: Given difference equation x t + 1 = c x t ( 1 − x t ) Where x 0 = 0.4 , c = 3.5 . Let us calculate some terms of the sequence. x 0 = 0.4 x 1 = ( 3.5 ) ⋅ x 0 ( 1 − x 0 ) = ( 3.5 ) ⋅ ( 0.4 ) ( 1 − 0.4 ) = 0.8400 x 2 = ( 3.5 ) ⋅ x 1 ( 1 − x 1 ) = ( 3.5 ) ⋅ ( 0.8400 ) ( 1 − 0.8400 ) = 0.4704 x 3 = ( 3.5 ) ⋅ x 2 ( 1 − x 2 ) = ( 3.5 ) ⋅ ( 0.4704 ) ( 1 − 0.4704 ) ≈ 0.8719 x 4 = ( 3.5 ) ⋅ x 3 ( 1 − x 3 ) ≈ ( 3.5 ) ⋅ ( 0.8719 ) ( 1 − 0.8719 ) ≈ 0.3908 x 5 = ( 3.5 ) ⋅ x 4 ( 1 − x 4 ) ≈ ( 3.5 ) ⋅ ( 0

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Publisher: Cengage Learning

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Chapter 2.1, Problem 50E

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To plot: xt+1=cxt(1−xt) and calculate its exact value.

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Chapter 2.1, Problem 49E

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Chapter 2 Solutions

Biocalculus: Calculus For Life Sciences

Ch. 2.1 - Prob. 1E Ch. 2.1 - Prob. 2E Ch. 2.1 - Prob. 3E Ch. 2.1 - Prob. 4E Ch. 2.1 - Prob. 5E Ch. 2.1 - Prob. 6E Ch. 2.1 - Prob. 7E Ch. 2.1 - Prob. 8E Ch. 2.1 - Prob. 9E Ch. 2.1 - Prob. 10E

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To plot: x t + 1 = c x t ( 1 − x t ) and calculate its exact value.

Solution Summary: The author explains that the sequence is oscillatory and does not appear to be convergent.

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To plot: xt+1=cxt(1−xt) and calculate its exact value.

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Chapter 2 Solutions