Explanation Given: The given equation is e − x 2 = x Concept Used: The Intermediate Value Theorem: If f is continuous on the closed interval [ a , b ] and let N be any number between f ( a ) and f ( b ) , where f ( a ) ≠ f ( b ) . Then there exists a number c in ( a , b ) such that f ( c ) = N . Calculation: To show that there is a root of the equation e − x 2 = x in interval ( 0 , 1 ) First let f ( x ) = e − x 2 − x = 0 and a = 0 , b = 1

15th Edition

ISBN: 9781305177291

Author: James Stewart, Troy Day

Publisher: Cengage Learning

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Chapter 2, Problem 34E

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To show that there is a root of the equation:

e−x2=x , in interval (0,1) , using the Intermediate Value Theorem

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Chapter 2, Problem 33E

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Chapter 2 Solutions

Biocalculus: Calculus For Life Sciences

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To show that there is a root of the equation: e − x 2 = x , in interval ( 0 , 1 ) , using the Intermediate Value Theorem

Solution Summary: The author calculates the root of the equation e-x2=x using the Intermediate Value Theorem.

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To show that there is a root of the equation:

e−x2=x , in interval (0,1) , using the Intermediate Value Theorem

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Chapter 2 Solutions

To show that there is a root of the equation: e − x 2 = x , in interval ( 0 , 1 ) , using the Intermediate Value Theorem

Solution Summary: The author calculates the root of the equation e-x2=x using the Intermediate Value Theorem.

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To show that there is a root of the equation: e−x2=x , in interval (0,1) , using the Intermediate Value Theorem

Want to see the full answer?

Chapter 2 Solutions

To show that there is a root of the equation:

e−x2=x , in interval (0,1) , using the Intermediate Value Theorem