Introductory Chemistry: A Foundation
Introductory Chemistry: A Foundation
9th Edition
ISBN: 9781337671323
Author: ZUMDAHL
Publisher: Cengage
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Chapter 21, Problem 4ALQ
Interpretation Introduction

Interpretation:

Interpret the meaning of inhibition of enzyme and the effect on enzyme on irreversibly inhibition.

Concept Introduction:

Enzyme is a proteinecious structure and helps in catalysing the substrate and thus acts as catalyst. It helps in speeding up the particular reaction.

The enzyme acts on substrate and turns it into a product. With increase in concentration of enzyme the speed of reaction also increases.

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need help please and thanks dont understand only need help with C-F Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).   Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%.   Part B - Compare difference in free energy to the thermal…
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need help please and thanks dont understand a-b Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).   Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%.   Part B - Compare difference in free energy to the thermal energy Divide the…

Chapter 21 Solutions

Introductory Chemistry: A Foundation

Ch. 21 - Prob. 10ALQCh. 21 - Prob. 11ALQCh. 21 - Prob. 1QAPCh. 21 - Prob. 2QAPCh. 21 - Prob. 3QAPCh. 21 - Prob. 4QAPCh. 21 - Prob. 5QAPCh. 21 - Prob. 6QAPCh. 21 - Prob. 7QAPCh. 21 - Prob. 8QAPCh. 21 - Prob. 9QAPCh. 21 - . How many unique amino acid sequences are...Ch. 21 - Prob. 11QAPCh. 21 - Prob. 12QAPCh. 21 - Prob. 13QAPCh. 21 - Prob. 14QAPCh. 21 - Prob. 15QAPCh. 21 - Prob. 16QAPCh. 21 - Prob. 17QAPCh. 21 - Prob. 18QAPCh. 21 - Prob. 19QAPCh. 21 - . What protein is responsible for the transport of...Ch. 21 - Prob. 21QAPCh. 21 - Prob. 22QAPCh. 21 - Prob. 23QAPCh. 21 - Prob. 24QAPCh. 21 - . How does the efficiency of an enzyme compare...Ch. 21 - Prob. 26QAPCh. 21 - Prob. 27QAPCh. 21 - . Describe the lock-and-key model for enzymes. Why...Ch. 21 - Prob. 29QAPCh. 21 - Prob. 30QAPCh. 21 - Prob. 31QAPCh. 21 - Prob. 32QAPCh. 21 - Prob. 33QAPCh. 21 - Prob. 34QAPCh. 21 - Prob. 35QAPCh. 21 - Prob. 36QAPCh. 21 - Prob. 37QAPCh. 21 - Prob. 38QAPCh. 21 - Prob. 39QAPCh. 21 - Prob. 40QAPCh. 21 - Prob. 41QAPCh. 21 - Prob. 42QAPCh. 21 - Prob. 43QAPCh. 21 - Prob. 44QAPCh. 21 - Prob. 45QAPCh. 21 - Prob. 46QAPCh. 21 - Prob. 47QAPCh. 21 - Prob. 48QAPCh. 21 - Prob. 49QAPCh. 21 - Prob. 50QAPCh. 21 - . What is a steroid? What basic ring structure 15...Ch. 21 - Prob. 52QAPCh. 21 - Prob. 53QAPCh. 21 - Prob. 54QAPCh. 21 - Prob. 55APCh. 21 - Prob. 56APCh. 21 - Prob. 57APCh. 21 - Prob. 58APCh. 21 - Prob. 59APCh. 21 - Prob. 60APCh. 21 - Prob. 61APCh. 21 - Prob. 62APCh. 21 - Prob. 63APCh. 21 - Prob. 64APCh. 21 - Prob. 65APCh. 21 - Prob. 66APCh. 21 - Prob. 67APCh. 21 - Prob. 68APCh. 21 - Prob. 69APCh. 21 - Prob. 70APCh. 21 - Prob. 71APCh. 21 - Prob. 72APCh. 21 - Prob. 73APCh. 21 - Prob. 74APCh. 21 - Prob. 75APCh. 21 - Prob. 76APCh. 21 - Prob. 77APCh. 21 - Prob. 78APCh. 21 - Prob. 79APCh. 21 - Prob. 80APCh. 21 - Prob. 81APCh. 21 - Prob. 82APCh. 21 - Prob. 83APCh. 21 - Prob. 84APCh. 21 - Prob. 85APCh. 21 - Prob. 86APCh. 21 - Prob. 87APCh. 21 - Prob. 88APCh. 21 - Prob. 89APCh. 21 - Prob. 90APCh. 21 - Prob. 91APCh. 21 - Prob. 92APCh. 21 - Prob. 93APCh. 21 - Prob. 94APCh. 21 - Prob. 95APCh. 21 - Prob. 96APCh. 21 - . How many possible primary structures exist for a...Ch. 21 - Prob. 98APCh. 21 - Prob. 99APCh. 21 - Prob. 100APCh. 21 - Prob. 101APCh. 21 - Prob. 102APCh. 21 - Prob. 103APCh. 21 - Prob. 104APCh. 21 - Prob. 105APCh. 21 - Prob. 106AP
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