Explanation Given information: x 0 = 0.1 , c = 2 Calculation: Given difference equation x t + 1 = c x t ( 1 − x t ) Where x 0 = 0.1 , c = 2 . Let us calculate some terms of the sequence. x 0 = 0.1 x 1 = 2 ⋅ x 0 ( 1 − x 0 ) = 2 ⋅ ( 0.1 ) ( 0.9 ) = 0.1800 x 2 = 2 ⋅ x 1 ( 1 − x 2 ) = 2 ⋅ ( 0.18 ) ( 1 − 0.18 ) = 0.2952 x 3 = 2 ⋅ x 2 ( 1 − x 2 ) = 2 ⋅ ( 0.2952 ) ( 1 − 0.2952 ) ≈ 0.4161 x 4 = 2 ⋅ x 3 ( 1 − x 3 ) ≈ 2 ⋅ ( 0.41611 ) ( 1 − 0.41611 ) ≈ 0.4859 x 5 = 2 ⋅ x 4 ( 1 − x 4 ) = 2 ⋅ ( 0.4859 ) ( 1 − 0.4859 ) ≈ 0.4996 x 6 = 2 ⋅ x 5 ( 1 − x 5 ) = 2 ⋅ ( 0.4996 ) ( 1 − 0

15th Edition

ISBN: 9781133109631

Author: Stewart, JAMES, Day, Troy

Publisher: Cengage Learning,

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Chapter 2.1, Problem 47E

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To plot: xt+1=cxt(1−xt) and check behaviour of terms behave. Also calculate its exact value.

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Chapter 2.1, Problem 46E

Chapter 2.1, Problem 48E

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Chapter 2 Solutions

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To plot: x t + 1 = c x t ( 1 − x t ) and check behaviour of terms behave. Also calculate its exact value.

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To plot: xt+1=cxt(1−xt) and check behaviour of terms behave. Also calculate its exact value.

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Chapter 2 Solutions