Explanation Given information : The statement “ lim x → 1 x 2 + 6 x − 7 x 2 + 5 x − 6 = lim x → 1 ( x 2 + 6 x − 7 ) lim x → 1 ( x 2 + 5 x − 6 ) .” Consider the provided statement “ lim x → 1 x − 3 x 2 + 2 x − 4 = lim x → 1 ( x − 3 ) lim x → 1 ( x 2 + 2 x − 4 ) .” Recall the quotient law of limits, which is given two functions m ( x ) and n ( x ) the quotient of limit as x tends to k of the individual function is equal to limit of the quotient provided that limit of the denominator is not zero. That is, lim x → k m ( x ) n ( x ) = lim x → k m ( x ) lim x → k n ( x )

15th Edition

ISBN: 9781133109631

Author: Stewart, JAMES, Day, Troy

Publisher: Cengage Learning,

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Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topic…

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Question

Chapter 2, Problem 4TFQ

To determine

To find: Whether the statement “ limx→1x2+6x−7x2+5x−6=limx→1(x2+6x−7)limx→1(x2+5x−6) .” is true or false.

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Chapter 2 Solutions

Biocalculus

Ch. 2.1 - Prob. 1E Ch. 2.1 - Prob. 2E Ch. 2.1 - Prob. 3E Ch. 2.1 - Prob. 4E Ch. 2.1 - Prob. 5E Ch. 2.1 - Prob. 6E Ch. 2.1 - Prob. 7E Ch. 2.1 - Prob. 8E Ch. 2.1 - Prob. 9E Ch. 2.1 - Prob. 10E

Ch. 2.1 - Prob. 11E Ch. 2.1 - Prob. 12E Ch. 2.1 - Prob. 13E Ch. 2.1 - Prob. 14E Ch. 2.1 - Prob. 15E Ch. 2.1 - Prob. 16E Ch. 2.1 - Prob. 17E Ch. 2.1 - Prob. 18E Ch. 2.1 - Prob. 19E Ch. 2.1 - Prob. 20E Ch. 2.1 - Prob. 21E Ch. 2.1 - Prob. 22E Ch. 2.1 - Prob. 23E Ch. 2.1 - Prob. 24E Ch. 2.1 - Prob. 25E Ch. 2.1 - Prob. 26E Ch. 2.1 - Prob. 27E Ch. 2.1 - Prob. 28E Ch. 2.1 - Prob. 29E Ch. 2.1 - Prob. 30E Ch. 2.1 - Prob. 31E Ch. 2.1 - Prob. 32E Ch. 2.1 - Prob. 33E Ch. 2.1 - Prob. 34E Ch. 2.1 - Prob. 35E Ch. 2.1 - Prob. 36E Ch. 2.1 - Prob. 37E Ch. 2.1 - Prob. 38E Ch. 2.1 - Prob. 39E Ch. 2.1 - Prob. 40E Ch. 2.1 - Prob. 41E Ch. 2.1 - Prob. 42E Ch. 2.1 - Prob. 43E Ch. 2.1 - Prob. 44E Ch. 2.1 - Prob. 45E Ch. 2.1 - Prob. 46E Ch. 2.1 - Prob. 47E Ch. 2.1 - Prob. 48E Ch. 2.1 - Prob. 49E Ch. 2.1 - Prob. 50E Ch. 2.1 - Prob. 51E Ch. 2.1 - Prob. 52E Ch. 2.1 - Prob. 53E Ch. 2.1 - Prob. 54E Ch. 2.1 - Prob. 55E Ch. 2.1 - Prob. 56E Ch. 2.1 - Prob. 57E Ch. 2.1 - Prob. 58E Ch. 2.1 - Prob. 59E Ch. 2.1 - Prob. 60E Ch. 2.1 - 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Prob. 9CS

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Whether the statement “ lim x → 1 x 2 + 6 x − 7 x 2 + 5 x − 6 = lim x → 1 ( x 2 + 6 x − 7 ) lim x → 1 ( x 2 + 5 x − 6 ) .” is true or false.

Solution Summary: The author explains the quotient law of limits, which is given two functions m(x) and

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To find: Whether the statement “ limx→1x2+6x−7x2+5x−6=limx→1(x2+6x−7)limx→1(x2+5x−6) .” is true or false.

Chapter 2 Solutions