AP CALCULUS TEST PREP-WORKBOOK
AP CALCULUS TEST PREP-WORKBOOK
6th Edition
ISBN: 9781418300258
Author: Demana
Publisher: SAVVAS L
Question
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Chapter 2.1, Problem 42E

a.

To determine

To find: The value of f′x , x<1

a.

Expert Solution
Check Mark

Answer to Problem 42E

The value is 2x .

Explanation of Solution

Given information:

The function is fx=x2,x≤12x,x>1

Concept used:

The left-hand derivative is given by the formula f′x=limh→0fx+h−fxh

Calculation:

Here, in the piece wise function the value of fx at x<1 is x2 .

Substitute the values in the formula,

  f′x=limh→0x+h2−x2h=limh→0x2+h2+2xh−x2h=limh→0hh+2xh=2x

Conclusion: The value of f′x=2x , x<1 .

b.

To determine

To find: The value of f′x , x>1

b.

Expert Solution
Check Mark

Answer to Problem 42E

The value is 2 .

Explanation of Solution

Given information:

The function is fx=x2,x≤12x,x>1

Concept used:

The right-hand derivative is given by the formula f′x=limh→0fx+h−fxh .

Calculation:

Here, in the piece wise function the value of fx at x<1 is 2x .

Substitute the values in the formula,

  f′x=limh→02x+h−2xh=limh→02x+2h−2xh=2hh=2

Conclusion: The value of f′x=2 , x>1 .

c.

To determine

To find: The value of limx→1−f′x .

c.

Expert Solution
Check Mark

Answer to Problem 42E

The value is 2 .

Explanation of Solution

Given information:

The function is fx=x2,x≤12x,x>1

Concept used:

The left-hand derivative is given by the formula f′x=limh→0fx+h−fxh

Calculation:

Here, in the piece wise function the value of fx at x<1 is x2 .

Substitute the values in the formula,

  f′x=limh→0x+h2−x2h=limh→0x2+h2+2xh−x2h=limh→0hh+2xh=2x

Substitute the values in the formula,

  limx→1−f′x=limx→1−2x=21=2

Conclusion: The value of limx→1−f′x=2

d.

To determine

To find: The value of limx→1+f′x

d.

Expert Solution
Check Mark

Answer to Problem 42E

The value is 2 .

Explanation of Solution

Given information:

The function is fx=x2,x≤12x,x>1

Concept used:

The right-hand derivative is given by the formula f′x=limh→0fx+h−fxh .

Calculation:

Here, in the piece wise function the value of fx at x<1 is 2x .

Substitute the values in the formula,

  f′x=limh→02x+h−2xh=limh→02x+2h−2xh=2hh=2

Substitute the values in the formula,

  limx→1+f′x=limx→1+2=2

Conclusion: The value of f′x=2

e.

To determine

To find: Existence of limx→1f′x .

e.

Expert Solution
Check Mark

Answer to Problem 42E

The limx→1f′x exists.

Explanation of Solution

Given information:

The function is fx=x2,x≤12x,x>1

Concept used:

If limx→1−f′x=limx→1+f′x , then limx→1f′x exists.

Calculation:

Value of limx→1+f′x is calculated as shown below.

  limx→1−f′x=limx→1−2x=21=2

Value of limx→1−f′x is calculated as shown below.

  limx→1−f′x=limx→1−2x=21=2

Conclusion: The value of limx→1f′x exists.

f.

To determine

To find: The value of left hand derivative.

f.

Expert Solution
Check Mark

Answer to Problem 42E

The value of left-hand derivative is 2 .

Explanation of Solution

Given information:

The function is fx=x2,x≤12x,x>1

Concept used:

The left-hand derivative is given by the formula f′x=limh→0+fa+h−fah

Calculation:

Here, in the piece wise function the value of a=1 , and the value of fx at x<1 is 2x .

Substitute the values in the formula,

  limh→0+f1+h−f1h=limh→0+21+h−21h=limh→0+2+2h−2h=limh→0+2hh=2

Conclusion: The value of left-hand derivative of the function is 2 .

g.

To determine

To find: The value of right hand derivative.

g.

Expert Solution
Check Mark

Answer to Problem 42E

The value of right-hand derivative is ∞ .

Explanation of Solution

Given information:

The function is fx=x2,x≤12x,x>1

Concept used:

The left-hand derivative is given by the formula f′x=limh→0+fa+h−fah

Calculation:

Here, in the piece wise function the value of a=1 , and the value of fx at x<1 is 2x .

Substitute the values in the formula,

  limh→0+f1+h−f1h=limh→0+21+h−12h=limh→0+2+2h−1h=limh→0+2h+1h=2+limh→0+1h=∞

Conclusion: The value of right hand derivative is not defined.

h.

To determine

To find: Existence of f′1

h.

Expert Solution
Check Mark

Answer to Problem 42E

The derivative does not exist.

Explanation of Solution

Given information:

The function is fx=x2,x≤12x,x>1

Concept used:

If the left hand derivative and right hand derivative exists and is equal then the derivative exists.

Calculation:

Here, in the piece wise function the value of a=1 , and the value of fx at x<1 is 2x .

Substitute the values in the formula,

  limh→0+f1+h−f1h=limh→0+21+h−21h=limh→0+2+2h−2h=limh→0+2hh=2

Here, in the piece wise function the value of a=1 , and the value of fx at x<1 is 2x .

Substitute the values in the formula,

  limh→0+f1+h−f1h=limh→0+21+h−12h=limh→0+2+2h−1h=limh→0+2h+1h=2+limh→0+1h=∞

Conclusion: The derivative does not exist.

Previous
Chapter 2.1, Problem 41E
Next
Chapter 2.1, Problem 43E

Chapter 2 Solutions

AP CALCULUS TEST PREP-WORKBOOK

Ch. 2.1 - Prob. 1QRCh. 2.1 - Prob. 2QRCh. 2.1 - Prob. 3QRCh. 2.1 - Prob. 4QRCh. 2.1 - Prob. 5QRCh. 2.1 - Prob. 6QRCh. 2.1 - Prob. 7QRCh. 2.1 - Prob. 8QRCh. 2.1 - Prob. 9QRCh. 2.1 - Prob. 10QR
Ch. 2.1 - Prob. 1ECh. 2.1 - Prob. 2ECh. 2.1 - Prob. 3ECh. 2.1 - Prob. 4ECh. 2.1 - Prob. 5ECh. 2.1 - Prob. 6ECh. 2.1 - Prob. 7ECh. 2.1 - Prob. 8ECh. 2.1 - Prob. 9ECh. 2.1 - Prob. 10ECh. 2.1 - Prob. 11ECh. 2.1 - Prob. 12ECh. 2.1 - Prob. 13ECh. 2.1 - Prob. 14ECh. 2.1 - Prob. 15ECh. 2.1 - Prob. 16ECh. 2.1 - Prob. 17ECh. 2.1 - Prob. 18ECh. 2.1 - Prob. 19ECh. 2.1 - Prob. 20ECh. 2.1 - Prob. 21ECh. 2.1 - Prob. 22ECh. 2.1 - Prob. 23ECh. 2.1 - Prob. 24ECh. 2.1 - Prob. 25ECh. 2.1 - Prob. 26ECh. 2.1 - Prob. 27ECh. 2.1 - Prob. 28ECh. 2.1 - Prob. 29ECh. 2.1 - Prob. 30ECh. 2.1 - Prob. 31ECh. 2.1 - Prob. 32ECh. 2.1 - Prob. 33ECh. 2.1 - Prob. 34ECh. 2.1 - Prob. 35ECh. 2.1 - Prob. 36ECh. 2.1 - Prob. 37ECh. 2.1 - Prob. 38ECh. 2.1 - Prob. 39ECh. 2.1 - Prob. 40ECh. 2.1 - Prob. 41ECh. 2.1 - Prob. 42ECh. 2.1 - Prob. 43ECh. 2.1 - Prob. 44ECh. 2.1 - Prob. 45ECh. 2.1 - Prob. 46ECh. 2.2 - Prob. 1QRCh. 2.2 - Prob. 2QRCh. 2.2 - Prob. 3QRCh. 2.2 - Prob. 4QRCh. 2.2 - Prob. 5QRCh. 2.2 - Prob. 6QRCh. 2.2 - Prob. 7QRCh. 2.2 - Prob. 8QRCh. 2.2 - Prob. 9QRCh. 2.2 - Prob. 10QRCh. 2.2 - Prob. 1ECh. 2.2 - Prob. 2ECh. 2.2 - Prob. 3ECh. 2.2 - Prob. 4ECh. 2.2 - Prob. 5ECh. 2.2 - Prob. 6ECh. 2.2 - Prob. 7ECh. 2.2 - Prob. 8ECh. 2.2 - Prob. 9ECh. 2.2 - Prob. 10ECh. 2.2 - Prob. 11ECh. 2.2 - Prob. 12ECh. 2.2 - Prob. 13ECh. 2.2 - Prob. 14ECh. 2.2 - Prob. 15ECh. 2.2 - Prob. 16ECh. 2.2 - Prob. 17ECh. 2.2 - Prob. 18ECh. 2.2 - Prob. 19ECh. 2.2 - Prob. 20ECh. 2.2 - Prob. 21ECh. 2.2 - Prob. 22ECh. 2.2 - Prob. 23ECh. 2.2 - Prob. 24ECh. 2.2 - Prob. 25ECh. 2.2 - Prob. 26ECh. 2.2 - Prob. 27ECh. 2.2 - Prob. 28ECh. 2.2 - Prob. 29ECh. 2.2 - Prob. 30ECh. 2.2 - Prob. 31ECh. 2.2 - Prob. 32ECh. 2.2 - Prob. 33ECh. 2.2 - Prob. 34ECh. 2.2 - Prob. 35ECh. 2.2 - Prob. 36ECh. 2.2 - Prob. 37ECh. 2.2 - Prob. 38ECh. 2.2 - Prob. 39ECh. 2.2 - Prob. 40ECh. 2.2 - Prob. 41ECh. 2.2 - Prob. 42ECh. 2.2 - Prob. 43ECh. 2.2 - Prob. 44ECh. 2.2 - Prob. 45ECh. 2.2 - Prob. 46ECh. 2.2 - Prob. 47ECh. 2.2 - Prob. 48ECh. 2.3 - Prob. 1QRCh. 2.3 - Prob. 2QRCh. 2.3 - Prob. 3QRCh. 2.3 - Prob. 4QRCh. 2.3 - Prob. 5QRCh. 2.3 - Prob. 6QRCh. 2.3 - Prob. 7QRCh. 2.3 - Prob. 8QRCh. 2.3 - Prob. 9QRCh. 2.3 - Prob. 10QRCh. 2.3 - Prob. 1ECh. 2.3 - Prob. 2ECh. 2.3 - Prob. 3ECh. 2.3 - Prob. 4ECh. 2.3 - Prob. 5ECh. 2.3 - Prob. 6ECh. 2.3 - Prob. 7ECh. 2.3 - Prob. 8ECh. 2.3 - Prob. 9ECh. 2.3 - Prob. 10ECh. 2.3 - Prob. 11ECh. 2.3 - Prob. 12ECh. 2.3 - Prob. 13ECh. 2.3 - Prob. 14ECh. 2.3 - Prob. 15ECh. 2.3 - Prob. 16ECh. 2.3 - Prob. 17ECh. 2.3 - Prob. 18ECh. 2.3 - Prob. 19ECh. 2.3 - Prob. 20ECh. 2.3 - Prob. 21ECh. 2.3 - Prob. 22ECh. 2.3 - Prob. 23ECh. 2.3 - Prob. 24ECh. 2.3 - Prob. 25ECh. 2.3 - Prob. 26ECh. 2.3 - Prob. 27ECh. 2.3 - Prob. 28ECh. 2.3 - Prob. 29ECh. 2.3 - Prob. 30ECh. 2.3 - Prob. 31ECh. 2.3 - Prob. 32ECh. 2.3 - Prob. 33ECh. 2.3 - Prob. 34ECh. 2.3 - Prob. 35ECh. 2.3 - Prob. 36ECh. 2.3 - Prob. 37ECh. 2.3 - Prob. 38ECh. 2.3 - Prob. 39ECh. 2.3 - Prob. 40ECh. 2.3 - Prob. 41ECh. 2.3 - Prob. 42ECh. 2.3 - Prob. 43ECh. 2.3 - Prob. 44ECh. 2.3 - Prob. 45ECh. 2.3 - Prob. 46ECh. 2.3 - Prob. 47ECh. 2.3 - Prob. 48ECh. 2.3 - Prob. 49ECh. 2.3 - Prob. 50ECh. 2.3 - Prob. 51ECh. 2.3 - Prob. 52ECh. 2.3 - Prob. 53ECh. 2.3 - Prob. 54ECh. 2.3 - Prob. 55ECh. 2.3 - Prob. 56ECh. 2.3 - Prob. 57ECh. 2.3 - Prob. 58ECh. 2.3 - Prob. 59ECh. 2.3 - Prob. 1QQCh. 2.3 - Prob. 2QQCh. 2.3 - Prob. 3QQCh. 2.3 - Prob. 4QQCh. 2.4 - Prob. 1QRCh. 2.4 - Prob. 2QRCh. 2.4 - Prob. 3QRCh. 2.4 - Prob. 4QRCh. 2.4 - Prob. 5QRCh. 2.4 - Prob. 6QRCh. 2.4 - Prob. 7QRCh. 2.4 - Prob. 8QRCh. 2.4 - Prob. 9QRCh. 2.4 - Prob. 10QRCh. 2.4 - Prob. 1ECh. 2.4 - Prob. 2ECh. 2.4 - Prob. 3ECh. 2.4 - Prob. 4ECh. 2.4 - Prob. 5ECh. 2.4 - Prob. 6ECh. 2.4 - Prob. 7ECh. 2.4 - Prob. 8ECh. 2.4 - Prob. 9ECh. 2.4 - Prob. 10ECh. 2.4 - Prob. 11ECh. 2.4 - Prob. 12ECh. 2.4 - Prob. 13ECh. 2.4 - Prob. 14ECh. 2.4 - Prob. 15ECh. 2.4 - Prob. 16ECh. 2.4 - Prob. 17ECh. 2.4 - Prob. 18ECh. 2.4 - Prob. 19ECh. 2.4 - Prob. 20ECh. 2.4 - Prob. 21ECh. 2.4 - Prob. 22ECh. 2.4 - Prob. 23ECh. 2.4 - Prob. 24ECh. 2.4 - Prob. 25ECh. 2.4 - Prob. 26ECh. 2.4 - Prob. 27ECh. 2.4 - Prob. 28ECh. 2.4 - Prob. 29ECh. 2.4 - Prob. 30ECh. 2.4 - Prob. 31ECh. 2.4 - Prob. 32ECh. 2.4 - Prob. 33ECh. 2.4 - Prob. 34ECh. 2.4 - Prob. 35ECh. 2.4 - Prob. 36ECh. 2.4 - Prob. 37ECh. 2.4 - Prob. 38ECh. 2.4 - Prob. 39ECh. 2.4 - Prob. 40ECh. 2.4 - Prob. 41ECh. 2.4 - Prob. 42ECh. 2.4 - Prob. 43ECh. 2.4 - Prob. 44ECh. 2.4 - Prob. 45ECh. 2.4 - Prob. 46ECh. 2.4 - Prob. 47ECh. 2.4 - Prob. 48ECh. 2.4 - Prob. 49ECh. 2.4 - Prob. 50ECh. 2.5 - Prob. 1QRCh. 2.5 - Prob. 2QRCh. 2.5 - Prob. 3QRCh. 2.5 - Prob. 4QRCh. 2.5 - Prob. 5QRCh. 2.5 - Prob. 6QRCh. 2.5 - Prob. 7QRCh. 2.5 - Prob. 8QRCh. 2.5 - Prob. 9QRCh. 2.5 - Prob. 10QRCh. 2.5 - Prob. 1ECh. 2.5 - Prob. 2ECh. 2.5 - Prob. 3ECh. 2.5 - Prob. 4ECh. 2.5 - Prob. 5ECh. 2.5 - Prob. 6ECh. 2.5 - Prob. 7ECh. 2.5 - Prob. 8ECh. 2.5 - Prob. 9ECh. 2.5 - Prob. 10ECh. 2.5 - Prob. 11ECh. 2.5 - Prob. 12ECh. 2.5 - Prob. 13ECh. 2.5 - Prob. 14ECh. 2.5 - Prob. 15ECh. 2.5 - Prob. 16ECh. 2.5 - Prob. 17ECh. 2.5 - Prob. 18ECh. 2.5 - Prob. 19ECh. 2.5 - Prob. 20ECh. 2.5 - Prob. 21ECh. 2.5 - Prob. 22ECh. 2.5 - Prob. 23ECh. 2.5 - Prob. 24ECh. 2.5 - Prob. 25ECh. 2.5 - Prob. 26ECh. 2.5 - Prob. 27ECh. 2.5 - Prob. 28ECh. 2.5 - Prob. 29ECh. 2.5 - Prob. 30ECh. 2.5 - Prob. 31ECh. 2.5 - Prob. 32ECh. 2.5 - Prob. 33ECh. 2.5 - Prob. 34ECh. 2.5 - Prob. 35ECh. 2.5 - Prob. 36ECh. 2.5 - Prob. 37ECh. 2.5 - Prob. 38ECh. 2.5 - Prob. 39ECh. 2.5 - Prob. 40ECh. 2.5 - Prob. 41ECh. 2.5 - Prob. 42ECh. 2.5 - Prob. 43ECh. 2.5 - Prob. 44ECh. 2.5 - Prob. 45ECh. 2.5 - Prob. 46ECh. 2.5 - Prob. 47ECh. 2.5 - Prob. 48ECh. 2.5 - Prob. 49ECh. 2.5 - Prob. 50ECh. 2.5 - Prob. 51ECh. 2.5 - Prob. 52ECh. 2.5 - Prob. 1QQCh. 2.5 - Prob. 2QQCh. 2.5 - Prob. 3QQCh. 2.5 - Prob. 4QQCh. 2 - Prob. 1RWDTCh. 2 - Prob. 2RWDTCh. 2 - Prob. 3RWDTCh. 2 - Prob. 4RWDTCh. 2 - Prob. 5RWDTCh. 2 - Prob. 6RWDTCh. 2 - Prob. 7RWDTCh. 2 - Prob. 8RWDTCh. 2 - Prob. 9RWDTCh. 2 - Prob. 10RWDTCh. 2 - Prob. 1RECh. 2 - Prob. 2RECh. 2 - Prob. 3RECh. 2 - Prob. 4RECh. 2 - Prob. 5RECh. 2 - Prob. 6RECh. 2 - Prob. 7RECh. 2 - Prob. 8RECh. 2 - Prob. 9RECh. 2 - Prob. 10RECh. 2 - Prob. 11RECh. 2 - Prob. 12RECh. 2 - Prob. 13RECh. 2 - Prob. 14RECh. 2 - Prob. 15RECh. 2 - Prob. 16RECh. 2 - Prob. 17RECh. 2 - Prob. 18RECh. 2 - Prob. 19RECh. 2 - Prob. 20RECh. 2 - Prob. 21RECh. 2 - Prob. 22RECh. 2 - Prob. 23RECh. 2 - Prob. 24RECh. 2 - Prob. 25RECh. 2 - Prob. 26RECh. 2 - Prob. 27RECh. 2 - Prob. 28RECh. 2 - Prob. 29RECh. 2 - Prob. 30RECh. 2 - Prob. 31RECh. 2 - Prob. 32RECh. 2 - Prob. 33RECh. 2 - Prob. 34RECh. 2 - Prob. 35RECh. 2 - Prob. 36RECh. 2 - Prob. 37RECh. 2 - Prob. 38RECh. 2 - Prob. 39RECh. 2 - Prob. 40RECh. 2 - Prob. 41RECh. 2 - Prob. 42RECh. 2 - Prob. 43RECh. 2 - Prob. 44RECh. 2 - Prob. 45RECh. 2 - Prob. 46RECh. 2 - Prob. 47RECh. 2 - Prob. 48RECh. 2 - Prob. 49RECh. 2 - Prob. 50RECh. 2 - Prob. 51RECh. 2 - Prob. 52RECh. 2 - Prob. 53RECh. 2 - Prob. 54RECh. 2 - Prob. 55RECh. 2 - Prob. 56RECh. 2 - Prob. 57RECh. 2 - Prob. 58RECh. 2 - Prob. 59RECh. 2 - Prob. 60RECh. 2 - Prob. 61RECh. 2 - Prob. 62RECh. 2 - Prob. 63RECh. 2 - Prob. 64RECh. 2 - Prob. 65RECh. 2 - Prob. 66RECh. 2 - Prob. 67RECh. 2 - Prob. 68RECh. 2 - Prob. 69RECh. 2 - Prob. 70RECh. 2 - Prob. 71RECh. 2 - Prob. 72RECh. 2 - Prob. 73RECh. 2 - Prob. 74RECh. 2 - Prob. 75RECh. 2 - Prob. 76RECh. 2 - Prob. 77RECh. 2 - Prob. 78RECh. 2 - Prob. 79RECh. 2 - Prob. 80RECh. 2 - Prob. 81EPCh. 2 - Prob. 82EPCh. 2 - Prob. 83EP
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