Chapter 2.1, Problem 40PPS

To determine

To Match: The sentence “one half of g plus thirty-two is as much as the sum of fifteen and six times g” with an equation.

A) $g^2=2\left(g-10\right)$

B) $\frac{1}{2}g+32=15+6g$

C) $g^3=24g+4$

D) $3g^2=30+9g$

Answer to Problem 40PPS

The required equation is $\frac{1}{2}g+32=15+6g$ i.e. option B.

Explanation of Solution

Given information:

The sentence “one half of g plus thirty-two is as much as the sum of fifteen and six times g”.

Calculation:

One half of g can be represented as:

  $\frac{1}{2}g$

One half of g plus thirty-two can be represented as:

  $\frac{1}{2}g+32$

Is can be represented by “=”

Six times g can be represented as:

  $6g$

The sum of fifteen and six times g can be represented as:

  $15+6g$

So, one half of g plus thirty-two is as much as the sum of fifteen and six times g can be written as:

  $\frac{1}{2}g+32=15+6g$

Thus the correct match is option B.