
Concept explainers
a) H3C-Cl
Interpretation:
Using δ+/δ- convention, the direction of expected polarity for C-Cl bond in H3C-Cl is to be indicated.
Concept introduction:
Normally a crossed arrow is used to indicate the direction of the bond polarity. By convention electrons are displaced in the direction of the arrow. The tail of the arrow which looks like a plus sign is electron-poor (δ+) and the head of the arrow is electron rich (δ-).
To indicate:
Using δ+/ δ- convention, the direction of expected polarity for C-Cl bond in H3C-Cl.
b) H3C-NH2
Interpretation:
Using δ+/δ- convention, the direction of expected polarity for C-N bond in H3C-NH2 is to be indicated.
Concept introduction:
Normally a crossed arrow is used to indicate the direction of the bond polarity. By convention electrons are displaced in the direction of the arrow. The tail of the arrow which looks like a plus sign is electron-poor (δ+) and the head of the arrow is electron rich (δ-).
To indicate:
Using δ+/δ- convention, the direction of expected polarity for C-N bond in H3C-NH2.
c) H2N-H
Interpretation:
Using δ+/δ- convention, the direction of expected polarity for N-H bond in H2N-H is to be indicated.
Concept introduction:
Normally a crossed arrow is used to indicate the direction of the bond polarity. By convention electrons are displaced in the direction of the arrow. The tail of the arrow which looks like a plus sign is electron-poor (δ+) and the head of the arrow is electron rich (δ-).
To indicate:
Using δ+/ δ- convention, the direction of expected polarity for N-H bond in H2N-H.
d) H3C-SH
Interpretation:
Using δ+/δ- convention, the direction of expected polarity for C-S bond in H3C-SH is to be indicated.
Concept introduction:Â
Normally a crossed arrow is used to indicate the direction of the bond polarity. By convention electrons are displaced in the direction of the arrow. The tail of the arrow which looks like a plus sign is electron-poor (δ+) and the head of the arrow is electron rich (δ-).
To indicate:
Using δ+/δ- convention, the direction of expected polarity for C-S bond in H3C-SH.
e) H3C- Mg Br
Interpretation:
Using δ+/δ- convention, the direction of expected polarity for C-Mg bond in H3C-Mg Br is to be indicated.
Concept introduction:
Normally a crossed arrow is used to indicate the direction of the bond polarity. By convention electrons are displaced in the direction of the arrow. The tail of the arrow which looks like a plus sign is electron-poor (δ+) and the head of the arrow is electron rich (δ-).
To indicate:
Using δ+/δ- convention, the direction of expected polarity for C-Mg bond in H3C-Mg Br.
f) H3C-F
Interpretation:
Using δ+/δ- convention, the direction of expected polarity for C-F bond in H3C-F is to be indicated.
Concept introduction:
Normally a crossed arrow is used to indicate the direction of the bond polarity. By convention electrons are displaced in the direction of the arrow. The tail of the arrow which looks like a plus sign is electron-poor (δ+) and the head of the arrow is electron rich (δ-).
To indicate:
Using δ+/δ- convention, the direction of expected polarity for C-F bond in H3C-F.

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Chapter 2 Solutions
Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!)
- Write the complete common (not IUPAC) name of each molecule below. Note: if a molecule is one of a pair of enantiomers, be sure you start its name with D- or L- so we know which enantiomer it is. molecule Ο C=O common name (not the IUPAC name) H ☐ H3N CH₂OH 0- C=O H NH3 CH₂SH H3N ☐ ☐ X Garrow_forward(Part A) Provide structures of the FGI products and missing reagents (dashed box) 1 eq Na* H* H -H B1 B4 R1 H2 (gas) Lindlar's catalyst A1 Br2 MeOH H2 (gas) Lindlar's catalyst MeO. OMe C6H1402 B2 B3 A1 Product carbons' origins Draw a box around product C's that came from A1. Draw a dashed box around product C's that came from B1.arrow_forwardClassify each of the amino acids below. Note for advanced students: none of these amino acids are found in normal proteins. X CH2 H3N-CH-COOH3N-CH-COO- H3N-CH-COO CH2 CH3-C-CH3 CH2 NH3 N NH (Choose one) ▼ (Choose one) S CH2 OH (Choose one) ▼ + H3N-CH-COO¯ CH2 H3N CH COO H3N-CH-COO CH2 오오 CH CH3 CH2 + O C CH3 O= O_ (Choose one) (Choose one) ▼ (Choose one) Garrow_forward
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- draw skeletal structures for the minor products of the reaction.arrow_forward1. Provide missing starting materials, reagents, products. If a product cannot be made, write NP (not possible) in the starting material box. C7H12O Ph HO H 1) 03-78 C 2) Me₂S + Ph .H OH + 2nd stereoisomer OH Ph D + enantiomer cat OsO 4 NMO H2O acetonearrow_forwardPlease note that it is correct and explains it rightly:Indicate the correct option. The proportion of O, C and H in the graphite oxide is:a) Constant, for the quantities of functional groups of acids, phenols, epoxy, etc. its constants.b) Depending on the preparation method, as much oxidant as the graphite is destroyed and it has less oxygen.c) Depends on the structure of the graphic being processed, whether it can be more tridimensional or with larger crystals, or with smaller crystals and with more edges.arrow_forward
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