Starting Out with C++ from Control Structures to Objects (9th Edition)
9th Edition
ISBN: 9780134498379
Author: Tony Gaddis
Publisher: PEARSON
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Chapter 21, Problem 23RQE
Program Plan Intro
Binary tree:
- It is a binary tree.
- It focuses on the search operation of a binary tree.
- A binary tree is a tree data structure which comes under hierarchical data structure.
- It is made of nodes that have a left child, right child and a data element.
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Assume the tree node structure is following........
struct node
{
int data;
struct node* left;
struct node* right;
};
struct node *root = null;
and there is a created new node function, called newnode(int new_data).
Please filled the Blank of Insertion function.
void insert(struct node *root, int key) {
struct node *current;
queue q;
q.enque(root);
while(!q.empty()
}
current = q.front();
q.deque();
if(current->left == NULL) {
break;
}
else
}
q.enque(
if(current->right == NULL) {
break;
else
q.enque(_
= newnode(key);
= newnode(key);
_-));
typedef struct node{int data;struct node *left,*right;}BST;The node structure of BST is shown above. Please design an efficient algorithm to return the maximum keyword value in BST. Completion function: int findmax (BST *T)
Programming questions：typedef struct node
{ int data; struct node *left, *right;}BT;The node structure of the binary tree (BT) is shown above. There is a binary tree T, please complete the function: int degreeone(BT *T) to compute how many degree 1 node in the BT. The T is the root pointer, and the function shoule return the total number of degree 1 node.
Chapter 21 Solutions
Starting Out with C++ from Control Structures to Objects (9th Edition)
Ch. 21.1 - Prob. 21.1CPCh. 21.1 - Prob. 21.2CPCh. 21.1 - Prob. 21.3CPCh. 21.1 - Prob. 21.4CPCh. 21.1 - Prob. 21.5CPCh. 21.1 - Prob. 21.6CPCh. 21.2 - Prob. 21.7CPCh. 21.2 - Prob. 21.8CPCh. 21.2 - Prob. 21.9CPCh. 21.2 - Prob. 21.10CP
Ch. 21.2 - Prob. 21.11CPCh. 21.2 - Prob. 21.12CPCh. 21 - Prob. 1RQECh. 21 - Prob. 2RQECh. 21 - Prob. 3RQECh. 21 - Prob. 4RQECh. 21 - Prob. 5RQECh. 21 - Prob. 6RQECh. 21 - Prob. 7RQECh. 21 - Prob. 8RQECh. 21 - Prob. 9RQECh. 21 - Prob. 10RQECh. 21 - Prob. 11RQECh. 21 - Prob. 12RQECh. 21 - Prob. 13RQECh. 21 - Prob. 14RQECh. 21 - Prob. 15RQECh. 21 - Prob. 16RQECh. 21 - Prob. 17RQECh. 21 - Prob. 18RQECh. 21 - Prob. 19RQECh. 21 - Prob. 20RQECh. 21 - Prob. 21RQECh. 21 - Prob. 22RQECh. 21 - Prob. 23RQECh. 21 - Prob. 24RQECh. 21 - Prob. 25RQECh. 21 - Prob. 1PCCh. 21 - Prob. 2PCCh. 21 - Prob. 3PCCh. 21 - Prob. 4PCCh. 21 - Prob. 5PCCh. 21 - Prob. 6PCCh. 21 - Prob. 7PCCh. 21 - Prob. 8PC
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- 77. A full binary tree can be generated using ______ a) post-order and pre-order traversal b) pre-order traversal c) post-order traversal d) in-order traversalarrow_forward#ifndef BT_NODE_H#define BT_NODE_H struct btNode{ int data; btNode* left; btNode* right;}; // pre: bst_root is root pointer of a binary search tree (may be 0 for// empty tree) and portArray has the base address of an array large// enough to hold all the data items in the binary search tree// post: The binary search tree has been traversed in-order and the data// values are written (as they are encountered) to portArray in// increasing positional order starting from the first elementvoid portToArrayInOrder(btNode* bst_root, int* portArray);void portToArrayInOrderAux(btNode* bst_root, int* portArray, int& portIndex); // pre: (none)// post: dynamic memory of all the nodes of the tree rooted at root has been// freed up (returned back to heap/freestore) and the tree is now empty// (root pointer contains the null address)void tree_clear(btNode*& root); // pre: (none)// post: # of nodes contained in tree rooted at root is returnedint…arrow_forwardGet the Longest Path Write a member function called DLList BST:: get longest_path() that returns a DLL of the longest path in the tree. For example, the red nodes in the following tree are on the longest path and should be added to the list. In case there are multiple longest paths, retrieve any of them.arrow_forward
- H.w2: the following figure shows an array representation for a binary tree: L X W E A H M Draw this tree Traverse the tree using Depth-First Traversal and Breadth-First Traversalarrow_forwardBinary search tree. Write a function named totalSum that takes as parameter the root of the binary search tree(with the following type) and returns the total sum of the numbers in the tree. struct tree{ int data; struct tree *left, *right; };arrow_forwardProgram 3: Binary Search Tree Program Objective The primary objective of this program is to learn to implement binary search trees and to combine their functionalities with linked lists. Program Description In a multiplayer game, players' avatars are placed in a large game scene, and each avatar has its information in the game. Write a program to manage players' information in a multiplayer game using a Binary Search (BS) tree for a multiplayer game. A node in the BS tree represents each player. Each player should have an ID number, avatar name, and stamina level. The players will be arranged in the BS tree based on their ID numbers. If there is only one player in the game scene, it is represented by one node (root) in the tree. Once another player enters the game scene, a new node will be created and inserted in the BS tree based on the player ID number. Players during the gameplay will receive hits that reduce their stamina. If the players lose all their stamina, they vanish from the…arrow_forward
- 46. Inorder traversal: Visit the left subtree, then the node, then the right subtree. True False Question 47 47. Postorder traversal: Visit each node after visiting its children. True Falsearrow_forwardC programming I need help writing a code that uses a struct pointer into a binary tree and using the same pointer into an arrayarrow_forwardQ5_3\ Represent the following tree by using array.arrow_forward
- Pythin: A binary search tree, write a function that finds and returns the median value. Assume that the class member variable. [_size] contains the number of elements in the binary search tree. What is the time complexity of your function? def find_median(self):arrow_forwardTask: Complete the function getMinDepth (Node *root), the function takes the root of a tree and returns the minimum depth of the tree. int getMinDepth(Node *root){ //write your code here } Constraints: The number of nodes in the tree is in the range [0, 100000]. -1000 <= Node.val <= 1000arrow_forwardc++ code screenshot and output is mustarrow_forward
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